xsl: write only certain attribute

[kelvin273]

hello,
i've an xml file and i want to transform it to another one with only certain attribute in certain nodes (!)
for example, all the node have id, title and description are attributes.
but i want the first node display only title, the second id and title, the third only description, etc.

the xml is:

<guide id="" title="" description="">
   <version id="" title="" description="">
   <module id="" title="" description="">
      <unit id="" title="" description="">

i write the following xsl file, but it work only for child on the root node (not for the child of the child...):

<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 
  <xsl:template match="@* | node()">
    <xsl:copy>
      <xsl:apply-templates select="@* | node()"/>
    </xsl:copy>
  </xsl:template>
 
  <xsl:template match="version">
    <xsl:copy>
      <xsl:copy-of select="@*[name() = 'id']"/>
      <xsl:apply-templates select="version"/>
    </xsl:copy>
  </xsl:template>
 
  <xsl:template match="module">
    <xsl:copy>
      <xsl:copy-of select="@*[name() = 'id']"/>
      <xsl:apply-templates select="module"/>
    </xsl:copy>
  </xsl:template>
 
  <xsl:template match="unit">
    <xsl:copy>
      <xsl:copy-of select="@*[name() = 'title']"/>
    </xsl:copy>
  </xsl:template>
 
</xsl:stylesheet>
 

my idea is to have an output similar of the follow:

<guide title="">
   <version id="">
   <module id="" title="">
      <unit title="" description="">

can anyone helps me, please?
(excuse me for my bad english)

[dorinbogdan]

How are you testing it?
Please provide a valid XML that can be tested against.
Currently, I get a blank page if open the XML in IE browser.

If you use other tool (Saxon?) I cannot be of much help since I have no 3th party tool.

Thanks.