String in XSLT

[sani723]

i ma usin gthe extension object in XSLT and then passing a string to XSLT like this

for(int i=0;i<xmlnode.Count;i++)
{
    XmlAttributeCollection xmlattrc = xmlnode[i].Attributes;
 
    all += "<br>";
    all += xmlattrc[0].Name;
    all += xmlattrc[0].Value;
 
    all += "<br>";
    all += xmlnode[i].FirstChild.Name;
    all += xmlnode[i].FirstChild.InnerText;
 
 
    all += xmlnode[i].LastChild.Name;
    all += xmlnode[i].LastChild.InnerText;
 
}
return all;
 

and then using it in XSLT like this

<xsl:value-of select="RDisc:GetAllData()" />

but is showing data in one line also included the <br> how i can solve this. I have also tried as

all +=&lt;br&gt;

[dorinbogdan]

See this thread.

[dorinbogdan]

And see this link too.

[sani723]

not working

[dorinbogdan]

Could you post the XSL and a relevant part of the XML to test?

[sani723]

here is the XML file

XML
[html]
<?xml version="1.0"?>
<data>
<room type="Single">
<units>1</units>
<extrabed>0</extrabed>
</room>
<room type="Double">
<units>2</units>
<extrabed>0</extrabed>
</room>
<room type="TSU">
<units>3</units>
<extrabed>0</extrabed>
</room>
<room type="Triple">
<units>4</units>
<extrabed>0</extrabed>
</room>
<room type="Quad">
<units>5</units>
<extrabed>0</extrabed>
</room>
</data>
[/html]

and here is the CSharp Class

using System;
using System.Xml;
using System.IO;
 
namespace creport.component
{
    /// <summary>
    /// Summary description for discount.
    /// </summary>
    public class discount
    {
        public discount()
        {
            //
            // TODO: Add constructor logic here
            //
        }
 
        public string ReturnTotalAmount(int a)
        {
            XmlDocument xmldoc;
            string path = System.Web.HttpContext.Current.Server.MapPath("stu2.xml");
            FileStream fs = new FileStream(path,FileMode.Open,FileAccess.Read,FileShare.ReadWrite);
            xmldoc = new XmlDocument();
            xmldoc.Load(fs);
 
 
            XmlNodeList xmlnode = xmldoc.GetElementsByTagName("room");
 
            string u="",e="";
 
            for(int i=0;i<xmlnode.Count;i++)
            {
                XmlAttributeCollection xmlattrc = xmlnode[i].Attributes;
 
                if (xmlattrc[0].Value == "Single" && a == 1)
                {
                    u = xmlnode[i].FirstChild.InnerText;
                    e = xmlnode[i].LastChild.InnerText;
 
                }
                if (xmlattrc[0].Value == "Double" && a == 2)
                {
                    u = xmlnode[i].FirstChild.InnerText;
                    e = xmlnode[i].LastChild.InnerText;
 
                }
                if (xmlattrc[0].Value == "TSU" && a == 3)
                {
                    u = xmlnode[i].FirstChild.InnerText;
                    e = xmlnode[i].LastChild.InnerText;
 
                }
                if (xmlattrc[0].Value == "Triple" && a == 4)
                {
                    u = xmlnode[i].FirstChild.InnerText;
                    e = xmlnode[i].LastChild.InnerText;
 
                }
                if (xmlattrc[0].Value == "Quad" && a == 5)
                {
                    u = xmlnode[i].FirstChild.InnerText;
                    e = xmlnode[i].LastChild.InnerText;
 
                }
 
            }
 
            string str = u + "," + e; 
            return str;
            fs.Close(); 
            fs = null;
            xmldoc = null;
        }
 
 
        public string GetAllData()
        {
            XmlDocument xmldoc;
            string path = System.Web.HttpContext.Current.Server.MapPath("stu2.xml");
 
            FileStream fs = new FileStream(path,FileMode.Open,FileAccess.Read,FileShare.ReadWrite);
            xmldoc = new XmlDocument();
            xmldoc.Load(fs);
 
            XmlNodeList xmlnode = xmldoc.GetElementsByTagName("room");
 
            string all="";
 
            for(int i=0;i<xmlnode.Count;i++)
            {
                XmlAttributeCollection xmlattrc = xmlnode[i].Attributes;
 
                all += "&lt;br /&gt;"; // and i also tried this "<br />"
                all += xmlattrc[0].Name;
                all += xmlattrc[0].Value;
 
                all += "&lt;br /&gt;";
                all += xmlnode[i].FirstChild.Name;
                all += xmlnode[i].FirstChild.InnerText;
 
 
                all += xmlnode[i].LastChild.Name;
                all += xmlnode[i].LastChild.InnerText;
 
            }
            return all;
            fs.Close(); 
            fs = null;
            xmldoc = null;
        }
 
 
    }
}
 
 

XSLT Code

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:myDiscount="urn:myDiscount" version="1.0">
 <tr>
    <td  class="gridHeader">Your Requirement</td>
  </tr>
  <tr>
    <td class="SearchResultItem">
    <xsl:value-of select="myDiscount:GetAllData()" />
    </td>
  </tr>
 

Extension Object:

discount obj = new discount(); 
args.AddExtensionObject("urn:myDiscount",obj);

[sani723]

Output

if i use &lt;br /&gt; the

<br />typeSingle<br />units1extrabed0<br />typeDouble<br />units2extrabed0<br />typeTSU<br />units3extrabed0<br />typeTriple<br />units4extrabed0<br />typeQuad<br />units5extrabed0
 

else

<br />typeSingle<br />units1extrabed0<br />typeDouble<br />units2extrabed0<br />typeTSU<br />units3extrabed0<br />typeTriple<br />units4extrabed0<br />typeQuad<br />units5extrabed0

[sani723]

waiting for reply

[sani723]

come on i am still waiting fro reply, is there anyone

[dorinbogdan]

Use the case that generates the second output (with <br />) , but add the
[html]xsl:output method="html"[/html] to the XSL as the second line.

If still not working , use:

//in code you must remove the spaces from "& # 1 0 ;" 
//I added spaces just to stop browser from interpreting it
all += "& # 1 0 ;" 
//instead of 
all += "<br />"

Also, add <pre> or <div> tags in XSL:
[html]<pre>
<xsl:value-of select="myDiscount:GetAllData()" />
</pre>
[/html]

Please let me know the result.

[sani723]

not working, still same result

[dorinbogdan]

Let me know to see how you could send me all required files with source code and resources in order to test your project locally.
Are you agree with this?
At this point I have no other idea.

[dorinbogdan]

1. This is the method to attach files:

"Posters can attach files zip files up to 39kb to a post. This is done by posting a dummy post with at least 10 characters (minimum requirement) then edit the post straight away (there is a 5 min limit) and the option to attach a file is available."

So you need to add a short message reply, then Submit it, and then reopen it for Edit (not later than 5 min), and Manage Attachments button appears.

Just attach the source code, without XML, XSL...that already was included before.

2. If it seems too complicate, then help me to create a similar project, and give some details.

[dorinbogdan]

Hi,
Did you succeed to solve the problem ?
If yes, please let me know, in order to close the thread.
Thanks,
Dorin.

[sani723]

no, not yet