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Traversing XML with Javascript

6 New Member
Hi team I'm traversing an XML file with 3000 + records in it. I've now run into some serious performance issues as a consequence... Is there an alternative to the below code I'm using? Or is there something in here that is really slowing it down? Any help would be much appreciated, it is currerntly taking 15 seconds to traverse my XML file!!!

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  1. <supplier>
  2. <id>001</id>
  3. <name>My Supplier</name>
  4. </supplier>
  5. <supplier>
  6. <id>002</id>
  7. <name>Another One</name>
  8. </supplier>
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  1. xmlDoc.validateOnParse = false;
  2. xmlDoc.resolveExternals = false;
  3. xmlDoc.preserveWhiteSpace = false;
  4. xmlDoc.async = false;
  5. xmlDoc.load(suppliers.xml);
  6. xmlObj = xmlDoc.documentElement;
  9. var aPrint = document.getElementById("items");
  12. for (var i=0; i<xmlObj.childNodes.length;i++)
  13. {
  14. var sDiv = document.createElement("div");
  15. sDiv.setAttribute("id","item" + i);
  16. sDiv.innerHTML = sDiv.innerHTML + "<h2>" + xmlObj.childNodes(i).childNodes(0).text + "</h2>";
  17. sDiv.innerHTML = sDiv.innerHTML + "<h3>" + xmlObj.childNodes(i).childNodes(1).text + "</h3>";
  18. var sBreak = document.createElement("hr");
  19. sDiv.appendChild(sBreak);        
  20. aPrint.appendChild(sDiv);
  21. }
Dec 12 '07 #1
5 2102
2,057 Recognized Expert Top Contributor
Unfortunately, javascript tends to be very slow. Have you tried using another tool such as XSLT instead?
Dec 12 '07 #2
6 New Member
Thanks for the tip! The data comes straight in using XSL, no loading time at all.

Much appreciated!

Last question for the day, I'm currently googling it with little luck, is there a way to use XSL to do a search on the XML file based on text in a textbox?

Dec 12 '07 #3
6 New Member
I've managed to get no where today with the search... Does anyone know how I can pass the value of a textbox to an xsl:param???

What I'm trying to do now is:

<xsl:if test="contains( name, 'MYSEARCHSTRING '">

Where MYSEARCHSTRING is the value in a text box.

Thanks again!
Dec 13 '07 #4
2,057 Recognized Expert Top Contributor
Are you running the xsl transformation in javascript?

Generally the syntax is like:
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  1. xslProc.addParameter("sortOrder", myvalue);
Dec 13 '07 #5
6 New Member
That's it, works perfectly.

Dec 17 '07 #6

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