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Find Xpath Expn of current node using ancestor-or-self

9 New Member
I'm trying to Xpath EXprn for a current node(name unknown).I tried using the below syntax,but it fails .Pls help.



<xsl:variable name= "xpath" select ="name(ances tor-or-self::(.))"/>
Oct 5 '07 #1
4 3444
jkmyoung
2,057 Recognized Expert Top Contributor
probably
<xsl:variable name="xpath" select="name()"/>
or
<xsl:variable name="xpath" select="local-name()"/>
Oct 5 '07 #2
Muthu08
9 New Member
nmae() or local-name() would only return me th ename of the current node.But i'm trying to find out the Xpath Expression ,which would return the ancestors names also

I need the name of current node plus its ancestors.

ex: root/toplevelnode1/node2/ current node

So i tried :

<xsl:variable name= "xpath" select ="name(ances tor-or-self::[name()])"/>

I need the syntax which would return current nodes path from the root.Pls help.

thanks in advance.
Oct 5 '07 #3
jkmyoung
2,057 Recognized Expert Top Contributor
Expand|Select|Wrap|Line Numbers
  1. <xsl:variable name= "xpath">
  2.   <xsl:for-each select="ancestor::*">
  3.     <xsl:value-of select="name()"/><xsl:text>/</xsl:text>
  4.   </xsl:for-each>
  5.   <xsl:value-of select="name()"/>
  6. </xsl:variable>
Oct 5 '07 #4
Muthu08
9 New Member
Cool!! That worked Thanks!!
Oct 5 '07 #5

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