Removing items from a listbox and from object collection

[maylortaylor]

I am having troubles with my listbox. I have two buttons for the box.

1)add files
2)remove files

..simple enough. However, whenever i use the remove button it will take the text out of the listbox; but it will not remove it from the selectobjectcollection (i'm assuming that's where the info is stored..sorta new to VB)

The end of the program takes all the files in the list box and compiles them into a XML file. However, at the present moment the program adds every file I initially added using the "add files" button. So, basically, the "remove file" button is only for physical appearences on the list box..nothing more.

Any help?

This is the code for the "Remove Files" button.

        Do While (listbox.SelectedItems.Count > 0)
            listbox.Items.Remove(listbox.SelectedItem)
        Loop
 

[Flinty]

There is no such property as "SelectedItems" or "SelectedItem" so the code will never work. I do not understand why you are not getting error messages when you try to run this code. Look in the MSDN Library and search for listbox and look for RemoveItem method.
Further the "Selected" property is a boolean property and is either True or False only.

[zmbd]

@maylortaylor:
You did not mention the version information for the environment; hence you might get a verity of answers. You should reference this: ListBox Control for Visual Basic 6.0 Users.
Second, you should always attempt to compile your code before posting. Most VBE will provide you with some information.

@Flinty:
You should also reference the link I have given above. You will find that your statements are not the most correct as related to the properties. In fact, quoted from the table provided in the the link given:

Visual Basic 6.0 = SelCount
Visual Basic 2005 Equivalent = Count (SelectedItem.Count)

I've altered the quote slightly to allow for the correct table header relationships.

[Flinty]

As the question was posted under Visual Basic 4/5/6 it's reasonable to use the properties and methods relating to these versions and not VB.Net.

[zmbd]

and you'll note the link is to the VB6 {cross-reference}
As a Chemist and a Mod I am very aware of what little differences in titles and names can mean.
I do not usually provide links or suggestions without due thought, proof reading, and other considerations.

[Flinty]

Firstly I recognise your expertise and high position and I do not wish to cause any upset, but your link is for Visual Studio 5 (.Net)users and how it differs from VB 6.0

[zmbd]

I understand what you are saying.

First, I never assume that a poster will be in the correct forum. All too often questions for VBA shows up in JAVA and MS Access in one of the other DB forums. To that extent, you will note that I have lightly "admonished" OP for failing to note which version of the BASIC language is being used.

Take a careful look at the code offered by OP... does it not strike you that the formatting is the same as would be seen from code that is from intellisense - such as from VS2005? It would also explain why OP is not seeing an error, it also explains the other behavior OP is observing (well, to a point).
Code taken directly from VS2005:

' Visual Basic 2005
Dim theItem As ListViewItem
If ListView1.SelectedItems.Count > 0 Then
    theItem = ListView1.SelectedItems(0)
Else
    theItem = Nothing
End If

You will also want to take note that OP could very well be using an ActiveX control... I'll stay within the VB6 editor reference: Visual Studio 6.0 - SelectedItem Property (ActiveX Controls)

Thus, without knowing the correct IDE that OP is using, I reviewed the information at hand along with what experience I have in programing and selected an answer that could cover either a VB6 or earlier question or one that is possibly a dot-net starting with VS2005....

-
As for causing upset... it takes considerably more than a slight disagreement to upset me (well, provided I get a few hours of sleep :) )
Despite my age and knowledge; I am wise enough to understand that I do make mistakes.