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I pulled this code from Vbasic.net or generating random passwords. I want to know how I can set up so that each time the page is refreshed a new password is generated without having to fill in the form boxes. Anyone lend a hand?
http://vbasic.net/detail.aspx?tid=105
Code:
<form id="form1" runat="server">
<div> Enter Required Password Length:
<asp:TextBox ID="TextBox1" runat="server" Columns="2" MaxLength="2"></asp:TextBox><br />
<asp:Label ID="Label1" runat="server"></asp:Label><br />
<asp:Button ID="Button1" runat="server" Text="Generate Password" OnClick="Button1_Click" />
</div>
</form> The simple method is shown below. This is how the code-behind should look:
Code:
Imports Microsoft.VisualBasic
Imports System
Imports System.Data
Imports System.Configuration
Imports System.Web
Imports System.Web.Security
Imports System.Web.UI
Imports System.Web.UI.WebControls
Imports System.Web.UI.WebControls.WebParts
Imports System.Web.UI.HtmlControls
Partial Public Class _Default Inherits System.Web.UI.Page
Protected Sub Page_Load(ByVal sender As Object, ByVal e As EventArgs) If IsPostBack Then Label1.Text = "Please enter a password length (e.g. 8)"
End If
End Sub
Public Shared Function CreateRandomPassword(ByVal PasswordLength As Integer) As String Dim _allowedChars As String = "abcdefghijkmnopqrstuvwxyzABCDEFGHJKLMNOPQRSTUVWXY Z0123456789"
Dim randNum As New Random()
Dim chars(PasswordLength - 1) As Char
Dim allowedCharCount As Integer = _allowedChars.Length
For i As Integer = 0 To PasswordLength - 1 chars(i) = _allowedChars.Chars(CInt(Fix((_allowedChars.Length ) * randNum.NextDouble())))
Next i
Return New String(chars)
End Function
Protected Sub Button1_Click(ByVal sender As Object, ByVal e As EventArgs) If TextBox1.Text <> "" Then Dim myInt As String = TextBox1.Text.ToString()
Label1.Text = "Your generated password is: " & CreateRandomPassword(Integer.Parse(myInt))
End If
End Sub
End Class
