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opening a file

17
i want to open a file that should be done with the help of common dialog box. so plz help as soon as possible ya.
acording to my project the the text file should selected form the common dialog box from form1 and should display in form3(rich textbox) hope u guys understand
Feb 14 '08 #1
6 885
Ali Rizwan
925 512MB
Just add Microsoft Common Dialoge control in your project and write this control in a Button's click event.

Expand|Select|Wrap|Line Numbers
  1.  CommonDialog1.Open
open dialog box will show.

For an example of this you can tell me.

Regards
>> ALI <<
Feb 14 '08 #2
Bum
19
Yes,

commondialog1.open

but make sure you add a commondialog reference to your toolbox first.
Feb 14 '08 #3
Killer42
8,435 Expert 8TB
I think it would help if we knew what version of VB we're talking about here.
Feb 15 '08 #4
nivaz
17
I think it would help if we knew what version of VB we're talking about here.


this s VB6.0 guys plz help those are not working
Mar 7 '08 #5
debasisdas
8,127 Expert 4TB
try using this
Expand|Select|Wrap|Line Numbers
  1. CommonDialog1.ShowOpen
  2. If CommonDialog1.FileName <> "" Then
  3. RichTextBox1.LoadFile CommonDialog1.FileName
  4. End If
  5.  
Mar 7 '08 #6
VACEPROGRAMER
168 100+
Yes! Insert the MicrosoftCommonDialog 6.0 and put into the For. Tipe this code


CommonDialalog1.Filter = . . .. ' the file type you want to open
CommonDialog1.SHow open

And other memebers have told you the reset of the code . . .

VxE
Mar 8 '08 #7

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