I have a data grid view, list the files saved in SQL server. File type
may different in different rows. I want to achieve:
doule click one row in data grid view, a standard program be called to
open the selected file. Say MS word to open a .doc file, MS power
point to open .ppt file, etc.
In asp.net, I use Response.OutputStream.Write to achieve this, it's
pretty easy. is that a similar way in Windows application? Thanks in
advance!
2  1383 
On Aug 3, 11:46 am, AY Xu <ay...@yahoo.comwrote:
I have a data grid view, list the files saved in SQL server. File type
may different in different rows. I want to achieve:
doule click one row in data grid view, a standard program be called to
open the selected file. Say MS word to open a .doc file, MS power
point to open .ppt file, etc.
In asp.net, I use Response.OutputStream.Write to achieve this, it's
pretty easy. is that a similar way in Windows application? Thanks in
advance!
If i understood correclty,
System.Diagnostics.Process.Start http://msdn.microsoft.com/en-us/libr...ess.start.aspx
Sure, if necessary applications have been associated with proper file
types like Ms Word for *.doc extensions already.
Hope this helps,
Onur Güzel
On 8ÔÂ3ÈÕ, ÏÂÎç5ʱ19·Ö, kimiraikkonen <kimiraikkone....@gmail.comwrote:
On Aug 3, 11:46 am, AY Xu <ay...@yahoo.comwrote:
I have a data grid view, list the files saved in SQL server. File type
may different in different rows. I want to achieve:
doule click one row in data grid view, a standard program be called to
open the selected file. Say MS word to open a .doc file, MS power
point to open .ppt file, etc.
In asp.net, I use Response.OutputStream.Write to achieve this, it's
pretty easy. is that a similar way in Windows application? Thanks in
advance!
If i understood correclty,
System.Diagnostics.Process.Starthttp://msdn.microsoft.com/en-us/library/system.diagnostics.process.st...
Sure, if necessary applications have been associated with proper file
types like Ms Word for *.doc extensions already.
Hope this helps,
Onur G¨¹zel
Great, you point me to the right direction! i just set the file name,
then process.start(), .net automatically start right program to open
the file. that's great! thanks for help! This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics
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