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calculated values

how can i do this:
textbox1 + textbox2 = textbox3

(the two fields are given and the last field is automatically calculated.)

--
Message posted via DotNetMonster.com
http://www.dotnetmonster.com/Uwe/For...b-net/200803/1

Mar 12 '08 #1
18 1248
On Mar 12, 2:41*am, "enrico via DotNetMonster.com" <u41845@uwewrote:
how can i do this:
textbox1 + textbox2 = textbox3

(the two fields are given and the last field is automatically calculated.)

--
Message posted via DotNetMonster.comhttp://www.dotnetmonster.com/Uwe/Forums.aspx/dotnet-vb-net/200803/1
You mean? :

textbox3.text = textbox1.text + textbox2.text

But be careful textbox holds strings, that your input must consist of
numbers not to get an exception.
Mar 12 '08 #2


"kimiraikkonen" wrote:
On Mar 12, 2:41 am, "enrico via DotNetMonster.com" <u41845@uwewrote:
how can i do this:
textbox1 + textbox2 = textbox3

(the two fields are given and the last field is automatically calculated.)

--
Message posted via DotNetMonster.comhttp://www.dotnetmonster.com/Uwe/Forums.aspx/dotnet-vb-net/200803/1

You mean? :

textbox3.text = textbox1.text + textbox2.text

But be careful textbox holds strings, that your input must consist of
numbers not to get an exception.
Actually, this concatenates the strings. If Textbox1.text = "4" and
textbox2.text = "5" then textbox3.text will be set to "45". If Textbox1.text
= "Blue" and textbox2.text = "green", then textbox3.text will be set to
"Bluegreen".
Mar 12 '08 #3
what if your calculating numbers represented by an integer or double and not
string?

--
Message posted via DotNetMonster.com
http://www.dotnetmonster.com/Uwe/For...b-net/200803/1

Mar 12 '08 #4
On Mar 12, 3:42*am, "enrico via DotNetMonster.com" <u41845@uwewrote:
what if your calculating numbers represented by an integer or double and not
string?

--
Message posted via DotNetMonster.comhttp://www.dotnetmonster.com/Uwe/Forums.aspx/dotnet-vb-net/200803/1
Enrico,

Just type that code should work fine as far as you enter valid numbers
into textboxes:

Here you can change integer to double or long whatever variable you
wish to use depends on your variable's scale:

Dim firstval As Integer = textbox1.text
Dim secondval As Integer = textbox2.text
Dim result As Integer = textbox3.text

result = firstval + secondval

Hope this helps...
Mar 12 '08 #5
"enrico via DotNetMonster.com" <u41845@uweschrieb:
how can i do this:
textbox1 + textbox2 = textbox3

(the two fields are given and the last field is automatically calculated.)

In addition to the other replies, take a look at 'Integer.TryParse' and
'Double.TryParse'.

--
M S Herfried K. Wagner
M V P <URL:http://dotnet.mvps.org/>
V B <URL:http://dotnet.mvps.org/dotnet/faqs/>

Mar 12 '08 #6


"kimiraikkonen" wrote:
On Mar 12, 3:42 am, "enrico via DotNetMonster.com" <u41845@uwewrote:
what if your calculating numbers represented by an integer or double and not
string?

--
Message posted via DotNetMonster.comhttp://www.dotnetmonster.com/Uwe/Forums.aspx/dotnet-vb-net/200803/1

Enrico,

Just type that code should work fine as far as you enter valid numbers
into textboxes:

Here you can change integer to double or long whatever variable you
wish to use depends on your variable's scale:

Dim firstval As Integer = textbox1.text
Dim secondval As Integer = textbox2.text
Dim result As Integer = textbox3.text

result = firstval + secondval

Hope this helps...
Well, with strict on, it does not compile. Without that, it is not working
for me. I believe you will need to use Integer.TryParse(textbox1.text), etc,
as Herfreid suggested.

Mar 12 '08 #7


"Family Tree Mike" wrote:
>

"kimiraikkonen" wrote:
On Mar 12, 3:42 am, "enrico via DotNetMonster.com" <u41845@uwewrote:
what if your calculating numbers represented by an integer or double and not
string?
>
--
Message posted via DotNetMonster.comhttp://www.dotnetmonster.com/Uwe/Forums.aspx/dotnet-vb-net/200803/1
Enrico,

Just type that code should work fine as far as you enter valid numbers
into textboxes:

Here you can change integer to double or long whatever variable you
wish to use depends on your variable's scale:

Dim firstval As Integer = textbox1.text
Dim secondval As Integer = textbox2.text
Dim result As Integer = textbox3.text

result = firstval + secondval

Hope this helps...

Well, with strict on, it does not compile. Without that, it is not working
for me. I believe you will need to use Integer.TryParse(textbox1.text), etc,
as Herfreid suggested.
Sorry Kimi, my bad... I missed a line. It does work with option strict off.
Mar 12 '08 #8
where will i insert that "...parse" code in my procedure? i'm new to this
language, haven't gone a long way yet...

--
Message posted via DotNetMonster.com
http://www.dotnetmonster.com/Uwe/For...b-net/200803/1

Mar 12 '08 #9
Enrico,

As you know that it are integers

if Isnumeric(textbox2) and also Isnumeric(textbox1) then
textbox3.text = (CInt(textbox2) + (Cint(textbox3)).ToString
End if

Be aware that as soon as you use decimals it has to be CDouble or CDecimal

Cor
>
Mar 12 '08 #10
Herfried,
>
In addition to the other replies, take a look at 'Integer.TryParse' and
'Double.TryParse'.
In my idea not very much VB program language likewise.

However my idea as I wrote.

Cor
Mar 12 '08 #11
On Mar 12, 4:54*am, Family Tree Mike
<FamilyTreeM...@discussions.microsoft.comwrote:
"Family Tree Mike" wrote:
"kimiraikkonen" wrote:
On Mar 12, 3:42 am, "enrico via DotNetMonster.com" <u41845@uwewrote:
what if your calculating numbers represented by an integer or doubleand not
string?
--
Message posted via DotNetMonster.comhttp://www.dotnetmonster.com/Uwe/Forums.aspx/dotnet-vb-net/200803/1
Enrico,
Just type that code should work fine as far as you enter valid numbers
into textboxes:
Here you can change integer to double or long whatever variable you
wish to use depends on your variable's scale:
Dim firstval As Integer = textbox1.text
Dim secondval As Integer = textbox2.text
Dim result As Integer = textbox3.text
result = firstval + secondval
Hope this helps...
Well, with strict on, it does not compile. *Without that, it is not working
for me. *I believe you will need to use Integer.TryParse(textbox1.text), etc,
as Herfreid suggested.

Sorry Kimi, my bad... * I missed a line. *It does work with option strict off.- Hide quoted text -

- Show quoted text -
Yeah, i didn't use any option strict mode to get it work.
Mar 12 '08 #12
"Cor Ligthert[MVP]" <no************@planet.nlschrieb:
As you know that it are integers

if Isnumeric(textbox2) and also Isnumeric(textbox1) then
textbox3.text = (CInt(textbox2) + (Cint(textbox3)).ToString
End if
What's the 'IsNumeric' check for? 'IsNumeric' will return 'True' for values
which 'CInt' cannot handle and which maybe cannot be represented in the
'Integer' type.

--
M S Herfried K. Wagner
M V P <URL:http://dotnet.mvps.org/>
V B <URL:http://dotnet.mvps.org/dotnet/faqs/>

Mar 12 '08 #13
"enrico via DotNetMonster.com" <u41845@uweschrieb:
where will i insert that "...parse" code in my procedure? i'm new to this
language, haven't gone a long way yet...
\\\
Dim a, b As Integer
If Not Integer.TryParse(Me.TextBox1.Text, a) Then

' Set error provider or show an error message.
Return
End If
If Not Integer.TryParse(Me.TextBox2.Text, b) Then

' Set error provider or show an error message.
Return
End If
Me.TextBox3.Text = (a + b).ToString()
///

--
M S Herfried K. Wagner
M V P <URL:http://dotnet.mvps.org/>
V B <URL:http://dotnet.mvps.org/dotnet/faqs/>
Mar 12 '08 #14
Herfried,

It checks for most things normal users enter, even exponents.

I thought I had set in my messages, that if there would be decimals to use
CDouble, I used Cint to show how simple it was.

Cor

"Herfried K. Wagner [MVP]" <hi***************@gmx.atschreef in bericht
news:uZ**************@TK2MSFTNGP04.phx.gbl...
"Cor Ligthert[MVP]" <no************@planet.nlschrieb:
>As you know that it are integers

if Isnumeric(textbox2) and also Isnumeric(textbox1) then
textbox3.text = (CInt(textbox2) + (Cint(textbox3)).ToString
End if

What's the 'IsNumeric' check for? 'IsNumeric' will return 'True' for
values which 'CInt' cannot handle and which maybe cannot be represented in
the 'Integer' type.

--
M S Herfried K. Wagner
M V P <URL:http://dotnet.mvps.org/>
V B <URL:http://dotnet.mvps.org/dotnet/faqs/>
Mar 12 '08 #15
"Cor Ligthert[MVP]" <no************@planet.nlschrieb:
It checks for most things normal users enter, even exponents.

I thought I had set in my messages, that if there would be decimals to use
CDouble, I used Cint to show how simple it was.
Well, all I wanted to say is that your solution can result in runtime errors
depending on what the user enters.

--
M S Herfried K. Wagner
M V P <URL:http://dotnet.mvps.org/>
V B <URL:http://dotnet.mvps.org/dotnet/faqs/>

Mar 12 '08 #16

"Herfried K. Wagner [MVP]" <hi***************@gmx.atschreef in bericht
news:ul**************@TK2MSFTNGP06.phx.gbl...
"Cor Ligthert[MVP]" <no************@planet.nlschrieb:
>It checks for most things normal users enter, even exponents.

I thought I had set in my messages, that if there would be decimals to
use CDouble, I used Cint to show how simple it was.

Well, all I wanted to say is that your solution can result in runtime
errors depending on what the user enters.
All I wanted to show was that you were leaving your old habbit to use
forever Microsoft.VisualBasic commands while there were better System.Net
ones. (Which is not forever, don't understand that wrong).

Cor

Mar 13 '08 #17
"enrico via DotNetMonster.com" <u41845@uwewrote in message
news:8105406ea25cf@uwe...
how can i do this:
textbox1 + textbox2 = textbox3

(the two fields are given and the last field is automatically calculated.)

--
Message posted via DotNetMonster.com
http://www.dotnetmonster.com/Uwe/For...b-net/200803/1
As has been suggested to you elsewhere, turn on Options Strict and Explicit,
then use the generated syntax errors to help you get rid of the bad code.

Mar 13 '08 #18
<Ju********@home.netschrieb:
First, make sure they are both numeric.

if isnumeric(textbox1.text) and isnumeric(textbox2.text) then

'Then simply add the values

textbox3.text = val(textbox1.text) + val(textbox2.text)
'Val' is not culture-sensitive, which means that it recognizes only the
period (".") as a valid decimal separator. In Germany, for example, "," is
used as decimal separator.

--
M S Herfried K. Wagner
M V P <URL:http://dotnet.mvps.org/>
V B <URL:http://dotnet.mvps.org/dotnet/faqs/>

Mar 14 '08 #19

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