Displaying integer part of a decimal value

[kimiraikkonen]

Hi,
Sorry if this is so basic but i wanted to know the correct way of
displaying a value's "only" integer part.

I mean; if i declare a value as integer which is actually a decimal
number, it returns upper value after .51 decimal part.

I mean;
Dim number as integer = 12.51 returns 13.

If i;
Dim number as integer = 12.49 returns 12 as well.

I want to return only the integer part (12) in every case without
depending on whatever decimal part is.

Thanks

[Teemu]

"kimiraikkonen" <ki*************@gmail.comkirjoitti viestissä
news:ab**********************************@l16g2000 hsh.googlegroups.com...

Hi,
Sorry if this is so basic but i wanted to know the correct way of
displaying a value's "only" integer part.

I mean; if i declare a value as integer which is actually a decimal
number, it returns upper value after .51 decimal part.

I mean;
Dim number as integer = 12.51 returns 13.

If i;
Dim number as integer = 12.49 returns 12 as well.

I want to return only the integer part (12) in every case without
depending on whatever decimal part is.

Thanks

Math.Floor for example.

-Teemu

[Armin Zingler]

"kimiraikkonen" <ki*************@gmail.comschrieb

Hi,
Sorry if this is so basic but i wanted to know the correct way of
displaying a value's "only" integer part.

I mean; if i declare a value as integer which is actually a decimal
number, it returns upper value after .51 decimal part.

I mean;
Dim number as integer = 12.51 returns 13.

Option Strict On?
Use
number = cint(int(12.51))
Armin

[Herfried K. Wagner [MVP]]

"kimiraikkonen" <ki*************@gmail.comschrieb:

Sorry if this is so basic but i wanted to know the correct way of
displaying a value's "only" integer part.

'Int', 'Fix', 'Math.Floor', depending on what you want.

--
M S Herfried K. Wagner
M V P <URL:http://dotnet.mvps.org/>
V B <URL:http://dotnet.mvps.org/dotnet/faqs/>

[kimiraikkonen]

On Feb 13, 7:26 pm, "Teemu" <[e-mail]:

"kimiraikkonen" <[e-mail] viestissänews:ab********************************** @l16g2000hsh.googlegroups.com...

Hi,
Sorry if this is so basic but i wanted to know the correct way of
displaying a value's "only" integer part.

I mean; if i declare a value as integer which is actually a decimal
number, it returns upper value after .51 decimal part.

I mean;
Dim number as integer = 12.51 returns 13.

If i;
Dim number as integer = 12.49 returns 12 as well.

I want to return only the integer part (12) in every case without
depending on whatever decimal part is.

Thanks

Math.Floor for example.

-Teemu

Thanks all. Much ways there were.

[kimiraikkonen]

On Feb 13, 9:43 pm, kimiraikkonen <[e-mail]:

On Feb 13, 7:26 pm, "Teemu" <[e-mail]:

"kimiraikkonen" <[e-mail] viestissänews:ab********************************** @l16g2000hsh.googlegroups.com...

Hi,
Sorry if this is so basic but i wanted to know the correct way of
displaying a value's "only" integer part.

I mean; if i declare a value as integer which is actually a decimal
number, it returns upper value after .51 decimal part.

I mean;
Dim number as integer = 12.51 returns 13.

If i;
Dim number as integer = 12.49 returns 12 as well.

I want to return only the integer part (12) in every case without
depending on whatever decimal part is.

Thanks

Math.Floor for example.

-Teemu

Thanks all. Much ways there were.

As last, i'd like to know how get these functions work with the value
in textbox?

if i type 12.51(dot) in textbox1 and use that code;
Dim number As Integer = TextBox1.Text
MsgBox(Math.Floor(number))

i get: 1251

and if i type 12,51 (comma) in textbox1 and use that code;
Dim number As Integer = TextBox1.Text
MsgBox(Math.Floor(number))

i get: 13 instead of 12

Behaviour is same also with FIX function...

Thanks!

[Armin Zingler]

"kimiraikkonen" <ki*************@gmail.comschrieb

Thanks Armin, a shorter way i thought :-)

If TextBox1.Text.Contains(".") = True Then
TextBox1.Text = TextBox1.Text.Replace(".", ",")
End If

You'll get an exception if you enter "1.234,56" and the "," is the
decimal seperator as soon as you try to convert it to a number because
two "," are not allowed.
Armin