What is wrong with this mutex code

[Academia]

I build the solution.

In the bin folder I run the .exe

Twice

It runs each time.

Why doesn't the below code abort the second run?

Thanks

Shared Function Main(ByVal cmdArgs() As String) As Integer

Dim mutexWasCreated As Boolean

Using mutx As New Mutex(True, "TestJunk", mutexWasCreated)

If Not mutexWasCreated Then Return 1

End Using

Try

Application.EnableVisualStyles()

Application.Run(New FormStudioMdi)

Catch ex As Exception

[Stephany Young]

Becaue you are releasing of the mutex way too early.

If you're going to have your Application.Run(...) in a Try/Catch/End Try
block then extend it to include a Finally section and release it there.
"Academia" <ac************@a-znet.comwrote in message
news:uG**************@TK2MSFTNGP03.phx.gbl...

>I build the solution.

In the bin folder I run the .exe

Twice

It runs each time.

Why doesn't the below code abort the second run?

Thanks

Shared Function Main(ByVal cmdArgs() As String) As Integer

Dim mutexWasCreated As Boolean

Using mutx As New Mutex(True, "TestJunk", mutexWasCreated)

If Not mutexWasCreated Then Return 1

End Using

Try

Application.EnableVisualStyles()

Application.Run(New FormStudioMdi)

Catch ex As Exception

[kimiraikkonen]

On Jan 2, 5:17 am, "Academia" <[e-mail]:

I build the solution.

In the bin folder I run the .exe

Twice

It runs each time.

Why doesn't the below code abort the second run?

Thanks

Shared Function Main(ByVal cmdArgs() As String) As Integer

Dim mutexWasCreated As Boolean

Using mutx As New Mutex(True, "TestJunk", mutexWasCreated)

If Not mutexWasCreated Then Return 1

End Using

Try

Application.EnableVisualStyles()

Application.Run(New FormStudioMdi)

Catch ex As Exception

"Finally" (optional) and "end try" (required) parts are missing. Also
you've defined "Catch" with no exception display method, you may
throw the exception.

[Herfried K. Wagner [MVP]]

"Academia" <ac************@a-znet.comschrieb:

In the bin folder I run the .exe

Twice

It runs each time.

Why doesn't the below code abort the second run?

<URL:http://www.yoda.arachsys.com/csharp/faq/#one.application.instance>

In VB 2005 and VB 2008 you can make your application single-instance by
enabling the application framework and checking a checkbox in the
application framework properties (available in "My Project").

--
M S Herfried K. Wagner
M V P <URL:http://dotnet.mvps.org/>
V B <URL:http://dotnet.mvps.org/dotnet/faqs/>

[Academia]

I've never used a mutex so I'm going to finish the way I started and then
look at your suggestion.

The site you referenced says I need not release the mutex and also suggest
using a static variable.

Is that what you would do?
Thanks
"Herfried K. Wagner [MVP]" <hi***************@gmx.atwrote in message
news:uG**************@TK2MSFTNGP02.phx.gbl...

"Academia" <ac************@a-znet.comschrieb:

>In the bin folder I run the .exe

Twice

It runs each time.

Why doesn't the below code abort the second run?

<URL:http://www.yoda.arachsys.com/csharp/faq/#one.application.instance>

In VB 2005 and VB 2008 you can make your application single-instance by
enabling the application framework and checking a checkbox in the
application framework properties (available in "My Project").

--
M S Herfried K. Wagner
M V P <URL:http://dotnet.mvps.org/>
V B <URL:http://dotnet.mvps.org/dotnet/faqs/>

[Academia]

"Stephany Young" <noone@localhostwrote in message
news:e4**************@TK2MSFTNGP05.phx.gbl...

Becaue you are releasing of the mutex way too early.

If you're going to have your Application.Run(...) in a Try/Catch/End Try
block then extend it to include a Finally section and release it there.

I moved the End Using. Is that a good way?

Also, does it make sense to have the two message boxes.

I don't know a lot about the difference between two exceptions.

The revised code is below.

Thanks for the help

Shared Function Main(ByVal cmdArgs() As String) As Integer

Dim mutexWasCreated As Boolean

Using mutx As New Mutex(True, "TestJunk", mutexWasCreated)

If Not mutexWasCreated Then Return 1

Try

Application.EnableVisualStyles()

Application.Run(New FormStudioMdi)

Catch ex As Exception

Utility.WriteStackTrace(ex)

If ex.InnerException IsNot Nothing Then
MessageBox.Show(ex.InnerException.Message, " Experienced An Unhandled Inner
Error And Must Exit", MessageBoxButtons.OK)

If ex.GetBaseException IsNot Nothing Then
MessageBox.Show(ex.GetBaseException.Message, " Experienced A BaseException
And Must Exit", MessageBoxButtons.OK)

Return 1

End Try

Return 0

End Using

End Function

[Academia]

I should have sent
Catch ex As Exception ..snip...
There is code I didn't show.
Maybe you could comment on my reply to Stephany Young which shows all the
code.

Thanks

>
"Finally" (optional) and "end try" (required) parts are missing. Also
you've defined "Catch" with no exception display method, you may
throw the exception.

[Herfried K. Wagner [MVP]]

"Academia" <ac************@a-znet.comschrieb:

The site you referenced says I need not release the mutex and also suggest
using a static variable.

Is that what you would do?

Yes.

--
M S Herfried K. Wagner
M V P <URL:http://dotnet.mvps.org/>
V B <URL:http://dotnet.mvps.org/dotnet/faqs/>

[Academia]

thanks
"Herfried K. Wagner [MVP]" <hi***************@gmx.atwrote in message
news:uw**************@TK2MSFTNGP02.phx.gbl...

"Academia" <ac************@a-znet.comschrieb:

>The site you referenced says I need not release the mutex and also
suggest using a static variable.

Is that what you would do?

Yes.

--
M S Herfried K. Wagner
M V P <URL:http://dotnet.mvps.org/>
V B <URL:http://dotnet.mvps.org/dotnet/faqs/>