Option strict question.

[Bob]

I got a bit of code that launches Word and opens a file, as follows
Private sub OpenWord(Byval Fname as string)

Dim MyWord As New Microsoft.Office.Interop.Word.Application

Dim doc As Microsoft.Office.Interop.Word.Document

doc = MyWord.Documents.Open(Fname)

doc.activate()

MyWord.visible = true

end sub

When my project properties has Option strict On (which is what I want) I get
a blue underline in the IDE under the variable Fname (string type) and it
tells me that the string type can not be converted to object implicitly. I
do look at the intellisense of the Open method and I see the parameter
filename is of type object.

What do I need to do to be able to use my passed parameter Fname in the Open
method?

Thanks for any help

Bob

[AMDRIT]

I cannot use office interop, however if the input is an object of a string,
could you simply use cObj(somestring)?

"Bob" <bd*****@sgiims.comwrote in message
news:%2****************@TK2MSFTNGP04.phx.gbl...

>I got a bit of code that launches Word and opens a file, as follows
Private sub OpenWord(Byval Fname as string)

Dim MyWord As New Microsoft.Office.Interop.Word.Application

Dim doc As Microsoft.Office.Interop.Word.Document

doc = MyWord.Documents.Open(Fname)

doc.activate()

MyWord.visible = true

end sub

When my project properties has Option strict On (which is what I want) I
get a blue underline in the IDE under the variable Fname (string type) and
it tells me that the string type can not be converted to object
implicitly. I do look at the intellisense of the Open method and I see the
parameter filename is of type object.

What do I need to do to be able to use my passed parameter Fname in the
Open method?

Thanks for any help

Bob

[Cor Ligthert [MVP]]

Bob,

Did you try it explicitly
dim oFname as object = Fname
doc = MyWord.Documents.Open(oFname)

or just cast it
doc = MyWord.Documents.Open(DirectCast(Fname,object))

Office interop is not my favorite kind of sport therefore just a gues.

Cor

"Bob" <bd*****@sgiims.comschreef in bericht
news:%2****************@TK2MSFTNGP04.phx.gbl...

>I got a bit of code that launches Word and opens a file, as follows
Private sub OpenWord(Byval Fname as string)

Dim MyWord As New Microsoft.Office.Interop.Word.Application

Dim doc As Microsoft.Office.Interop.Word.Document

doc = MyWord.Documents.Open(Fname)

doc.activate()

MyWord.visible = true

end sub

When my project properties has Option strict On (which is what I want) I
get a blue underline in the IDE under the variable Fname (string type) and
it tells me that the string type can not be converted to object
implicitly. I do look at the intellisense of the Open method and I see the
parameter filename is of type object.

What do I need to do to be able to use my passed parameter Fname in the
Open method?

Thanks for any help

Bob

[Chris Dunaway]

Bob wrote:

I got a bit of code that launches Word and opens a file, as follows
Private sub OpenWord(Byval Fname as string)

Dim MyWord As New Microsoft.Office.Interop.Word.Application

Dim doc As Microsoft.Office.Interop.Word.Document

doc = MyWord.Documents.Open(Fname)

doc.activate()

MyWord.visible = true

end sub

Do you need to control the Word session? Why not use the Process
class:

Process.Start(Fname)

That should automatically start Word with that document.

[Jim Wooley]

Process.Start seems to be a much simpler solution if it meets the OP's needs.
I would second it. The big trick with the PIA's (primary interop assemblies)
is that they're a PIA. This is particularly true if you deploy to clients
who have differing versions of office installed as the PIA's are targeted
to individual office versions.

Jim Wooley
http://devauthority.com/blogs/jwooley/default.aspx

Bob wrote:

>I got a bit of code that launches Word and opens a file, as follows
Private sub OpenWord(Byval Fname as string)

Dim MyWord As New Microsoft.Office.Interop.Word.Application

Dim doc As Microsoft.Office.Interop.Word.Document

doc = MyWord.Documents.Open(Fname)

doc.activate()

MyWord.visible = true

end sub

Do you need to control the Word session? Why not use the Process
class:

Process.Start(Fname)

That should automatically start Word with that document.

[Bob]

Yeah I tried that and it works, thanks Cor
Bob
"Cor Ligthert [MVP]" <no************@planet.nlwrote in message
news:uD**************@TK2MSFTNGP03.phx.gbl...

Bob,

Did you try it explicitly
dim oFname as object = Fname
doc = MyWord.Documents.Open(oFname)

or just cast it
doc = MyWord.Documents.Open(DirectCast(Fname,object))

Office interop is not my favorite kind of sport therefore just a gues.

Cor

"Bob" <bd*****@sgiims.comschreef in bericht
news:%2****************@TK2MSFTNGP04.phx.gbl...

>>I got a bit of code that launches Word and opens a file, as follows
Private sub OpenWord(Byval Fname as string)

Dim MyWord As New Microsoft.Office.Interop.Word.Application

Dim doc As Microsoft.Office.Interop.Word.Document

doc = MyWord.Documents.Open(Fname)

doc.activate()

MyWord.visible = true

end sub

When my project properties has Option strict On (which is what I want) I
get a blue underline in the IDE under the variable Fname (string type)
and it tells me that the string type can not be converted to object
implicitly. I do look at the intellisense of the Open method and I see
the parameter filename is of type object.

What do I need to do to be able to use my passed parameter Fname in the
Open method?

Thanks for any help

Bob

[Bob]

Thanks I will try the process ,
I was having a problem with the distributed test app that would not start
Word, so you may have saved me anoter problem. Thanks again
Bob
"Chris Dunaway" <du******@gmail.comwrote in message
news:11*********************@m79g2000cwm.googlegro ups.com...

Bob wrote:

>I got a bit of code that launches Word and opens a file, as follows
Private sub OpenWord(Byval Fname as string)

Dim MyWord As New Microsoft.Office.Interop.Word.Application

Dim doc As Microsoft.Office.Interop.Word.Document

doc = MyWord.Documents.Open(Fname)

doc.activate()

MyWord.visible = true

end sub

Do you need to control the Word session? Why not use the Process
class:

Process.Start(Fname)

That should automatically start Word with that document.