I need to be able to do a Regex.split on a csv file ignoring the comma
if it is inside a single quote. I have the regular expression working
in the RegexDesigner tool, but when I use it within vb.net it adds an
extra split on each of the commas as well.
Example:
Reg Ex = ,(?=([^']*'[^']*')*(?![^']*'))
String to split = " '1A', 9, 2884, 'Sally, is late', 'nothing'
Works fine in the designer but output in vb.net looks like
element(0) = '1A'
element(1) = ,
element(2) = 9
element(3) = ,
etc...
Any help will be greatly appreciated!!
Thanks,
zdrakec 2 2220
Despite the common thinking, regex's do not work for csv's. Even if you
find a regex that is somewhat close to handling what you need, it will
be slower than even the simplest string manipulation. If you're doing
this for production code, I would strongly recommend that you use one
of the several production level csv parsers available on the net.
Bruce Dunwiddie http://www.csvreader.com
zdrakec wrote: I need to be able to do a Regex.split on a csv file ignoring the comma if it is inside a single quote. I have the regular expression working in the RegexDesigner tool, but when I use it within vb.net it adds an extra split on each of the commas as well.
Example: Reg Ex = ,(?=([^']*'[^']*')*(?![^']*')) String to split = " '1A', 9, 2884, 'Sally, is late', 'nothing'
Works fine in the designer but output in vb.net looks like element(0) = '1A' element(1) = , element(2) = 9 element(3) = ,
etc...
Any help will be greatly appreciated!!
Thanks, zdrakec
Thank you sir!
Cheers,
zdrakec This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics
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