My application (a VB.NET 2003 WinApp) currently has first an OpenFileDialog
(asking for an input file to the process I'm working on), and then once the
user selects that, it brings up a FolderBrowserDialog box (asking for a
destination for the output files from the process to be saved).
The OpenFileDialog works beautifully.
The problem is, after the user selects the input file from the
OpenFileDialog, when it opens the FolderBrowserDialog, it opens up behind
the application, and the user has to alt-TAB to get to it.
How can I force the FolderBrowserDialog to come to the front (at least
initially - if they choose to click on another application, I don't mind it
going behind then)?
Thanks!
-Scott
5  7323 
Are you using the overloaded ShowDialog function that receives the parent
IWin32Window?
--
Best regards,
Carlos J. Quintero
MZ-Tools: Productivity add-ins for Visual Studio .NET, VB6, VB5 and VBA
You can code, design and document much faster.
Free resources for add-in developers: http://www.mztools.com
"Scott M. Lyon" <sc******************@rapistan.BLUE.com> escribió en el
mensaje news:%2****************@TK2MSFTNGP14.phx.gbl... My application (a VB.NET 2003 WinApp) currently has first an
OpenFileDialog (asking for an input file to the process I'm working on),
and then once the user selects that, it brings up a FolderBrowserDialog
box (asking for a destination for the output files from the process to be
saved).
The OpenFileDialog works beautifully.
The problem is, after the user selects the input file from the
OpenFileDialog, when it opens the FolderBrowserDialog, it opens up behind
the application, and the user has to alt-TAB to get to it.
How can I force the FolderBrowserDialog to come to the front (at least
initially - if they choose to click on another application, I don't mind
it going behind then)?
Thanks!
-Scott
This is probably a stupid question, but here goes anyways:
The code for calling the ShowDialog function is in the code behind my main
form. How do I determine the IWin32Window value for the calling form?
Thanks!
-Scott
"Carlos J. Quintero [VB MVP]" <ca*****@NOSPAMsogecable.com> wrote in message
news:Oy**************@TK2MSFTNGP10.phx.gbl... Are you using the overloaded ShowDialog function that receives the parent
IWin32Window?
--
Best regards,
Carlos J. Quintero
MZ-Tools: Productivity add-ins for Visual Studio .NET, VB6, VB5 and VBA
You can code, design and document much faster.
Free resources for add-in developers:
http://www.mztools.com
"Scott M. Lyon" <sc******************@rapistan.BLUE.com> escribió en el
mensaje news:%2****************@TK2MSFTNGP14.phx.gbl... My application (a VB.NET 2003 WinApp) currently has first an
OpenFileDialog (asking for an input file to the process I'm working on),
and then once the user selects that, it brings up a FolderBrowserDialog
box (asking for a destination for the output files from the process to be
saved).
The OpenFileDialog works beautifully.
The problem is, after the user selects the input file from the
OpenFileDialog, when it opens the FolderBrowserDialog, it opens up behind
the application, and the user has to alt-TAB to get to it.
How can I force the FolderBrowserDialog to come to the front (at least
initially - if they choose to click on another application, I don't mind
it going behind then)?
Thanks!
-Scott
Ah, that might be it. No, I was using the ShowDialog function that doesn't
pass any parameters.
I'll try the other, and see if that works better.
Thanks!
-Scott
"Carlos J. Quintero [VB MVP]" <ca*****@NOSPAMsogecable.com> wrote in message
news:Oy**************@TK2MSFTNGP10.phx.gbl... Are you using the overloaded ShowDialog function that receives the parent
IWin32Window?
--
Best regards,
Carlos J. Quintero
MZ-Tools: Productivity add-ins for Visual Studio .NET, VB6, VB5 and VBA
You can code, design and document much faster.
Free resources for add-in developers:
http://www.mztools.com
"Scott M. Lyon" <sc******************@rapistan.BLUE.com> escribió en el
mensaje news:%2****************@TK2MSFTNGP14.phx.gbl... My application (a VB.NET 2003 WinApp) currently has first an
OpenFileDialog (asking for an input file to the process I'm working on),
and then once the user selects that, it brings up a FolderBrowserDialog
box (asking for a destination for the output files from the process to be
saved).
The OpenFileDialog works beautifully.
The problem is, after the user selects the input file from the
OpenFileDialog, when it opens the FolderBrowserDialog, it opens up behind
the application, and the user has to alt-TAB to get to it.
How can I force the FolderBrowserDialog to come to the front (at least
initially - if they choose to click on another application, I don't mind
it going behind then)?
Thanks!
-Scott
I am not sure if I understand the question, but the
System.Windows.Forms.Form class already implements the IWin32Window
interface, so you only need to pass the form that is showing the dialog.
--
Best regards,
Carlos J. Quintero
MZ-Tools: Productivity add-ins for Visual Studio .NET, VB6, VB5 and VBA
You can code, design and document much faster.
Free resources for add-in developers: http://www.mztools.com
"Scott M. Lyon" <sc******************@rapistan.BLUE.com> escribió en el
mensaje news:OG****************@TK2MSFTNGP09.phx.gbl... This is probably a stupid question, but here goes anyways:
The code for calling the ShowDialog function is in the code behind my main
form. How do I determine the IWin32Window value for the calling form?
Thanks!
-Scott
That was it! Geez, I should have thought of that! :)
Thanks, Carlos!
-Scott
"Carlos J. Quintero [VB MVP]" <ca*****@NOSPAMsogecable.com> wrote in message
news:%2****************@TK2MSFTNGP09.phx.gbl... I am not sure if I understand the question, but the
System.Windows.Forms.Form class already implements the IWin32Window
interface, so you only need to pass the form that is showing the dialog.
--
Best regards,
Carlos J. Quintero
MZ-Tools: Productivity add-ins for Visual Studio .NET, VB6, VB5 and VBA
You can code, design and document much faster.
Free resources for add-in developers:
http://www.mztools.com
"Scott M. Lyon" <sc******************@rapistan.BLUE.com> escribió en el
mensaje news:OG****************@TK2MSFTNGP09.phx.gbl... This is probably a stupid question, but here goes anyways:
The code for calling the ShowDialog function is in the code behind my
main form. How do I determine the IWin32Window value for the calling
form?
Thanks!
-Scott
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