Two quick Questions

[JoeCoolOH]

can some one tell me what the mod function does when you use a non
integer I am away from my vb pc.
Ex 19 Mod 6.7 =?
Would VB round or truncate the 6.7?

The other is

When compiling your ap into native code which option should you not use
if your code passes arguments by reference

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[Herfried K. Wagner [MVP]]

<JoeCoolOH> schrieb:

can some one tell me what the mod function does when you use a non
integer I am away from my vb pc.
Ex 19 Mod 6.7 =?
Would VB round or truncate the 6.7?

The other is

When compiling your ap into native code which option should you not use
if your code passes arguments by reference

VB6 or VB.NET?

--
M S Herfried K. Wagner
M V P <URL:http://dotnet.mvps.org/>
V B <URL:http://classicvb.org/petition/>

[JoeCoolOH]

That would be VB6 Is there a difference?

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[Jason Kendall]

I'm gonna take a guess that it's VB.Net.

Here's the help for the Mod operator.
-------------------------------
Mod OperatorSee Also
Arithmetic Operators | Operator Precedence in Visual Basic | Operators
Listed by Functionality | Arithmetic Operators
Divides two numbers and returns only the remainder.

number1 Mod number2
Parts
number1
Required. Any numeric expression.
number2
Required. Any numeric expression.
Result
The result is the remainder left after division is performed on
number1 and number2.

Supported Types
Byte, Short, Integer, Long, Single, Double, Decimal

Remarks
The Mod operator divides number1 by number2 and returns only the
remainder as result. For example, in the following expression, A
(result) equals 2.

A = 8 Mod 3
If number1 or number2 are floating-point values, then division is
carried out and the floating-point remainder is returned. The data
type of the result is the same as that of the data type with the
greatest range. The order of range, from least to greatest range, is
Byte, Short, Integer, Long, Single, Double, and Decimal.

-----------------------
So, this implies that 19 mod 6.7 = 5.6
-Jason Kendall
Ja**********@hotmail.com

On Fri, 1 Jul 2005 17:56:27 +0200, "Herfried K. Wagner [MVP]"
<hi***************@gmx.at> wrote:

<JoeCoolOH> schrieb:

can some one tell me what the mod function does when you use a non
integer I am away from my vb pc.
Ex 19 Mod 6.7 =?
Would VB round or truncate the 6.7?

The other is

When compiling your ap into native code which option should you not use
if your code passes arguments by reference

VB6 or VB.NET?

[Herfried K. Wagner [MVP]]

<JoeCoolOH> schrieb:

That would be VB6 Is there a difference?

Yes, because the VB.NET compiler doesn't compile native code.

--
M S Herfried K. Wagner
M V P <URL:http://dotnet.mvps.org/>
V B <URL:http://classicvb.org/petition/>

[Cor Ligthert]

Herfried,

That would be VB6 Is there a difference?

Yes, because the VB.NET compiler doesn't compile native code.

Can a VB6 program run withouth a runtimer?

Cor

[Herfried K. Wagner [MVP]]

Cor,

"Cor Ligthert" <no************@planet.nl> schrieb:

That would be VB6 Is there a difference?
Yes, because the VB.NET compiler doesn't compile native code.

Can a VB6 program run withouth a runtimer?

Without additional tools: No.

However, the VB5/6 compiler supports compiling to native code opposed to
P-code.

--
M S Herfried K. Wagner
M V P <URL:http://dotnet.mvps.org/>
V B <URL:http://classicvb.org/petition/>

[Dave Cousineau ( Sahuagin )]

upon running a quick console app:

MsgBox(19 Mod 6.7)

does indeed return 5.6

-----------------------
So, this implies that 19 mod 6.7 = 5.6
-Jason Kendall
Ja**********@hotmail.com