I have a string similar to the following:
" MyString 40 "Hello world" all "
It contains white space that may be spaces or tabs, or a combination, and I
want to produce an array with the following elements
arr(0) = "MyString"
arr(1) = 40
arr(2) = "Hello world"
arr(3) = "all"
Using trim and a regular expression ("\s+"), I can reduce my string to
"MyString 40 "Hello world" all"
and with Split I can get
arr(0) = "MyString"
arr(1) = 40
arr(2) = ""Hello"
arr(3) = "world""
arr(4) = "all"
As you can see, it is not quite what I need. The spaces in "Hello world"
have been reduced to a single space, and Split does not respect the double
quotes, and splits "Hello world" over two elements.
Does anyone have an idea how I could do this? I could process the string
character by character, but I am hoping that there is a straight-forward
technique for doing it, without looping, and using some of the techniques I
already have.
TIA
Charles 16 5834
Charles,
I was looking at the problem, I was thinking will I give my answer because
it is so difficult to describe. Than I saw that it was you. Therefore it
should not be a problem.
In this kind of situations I replace the spaces I will not use for an
absolute unused character.
Do the split
And replace the unused character again back for a space
I assume that this is for you more than enough explanation.
And now you read this you say, I knew that as well.
:-)))
Cor
"Charles Law" <bl***@nowhere.com>
.... I have a string similar to the following:
" MyString 40 "Hello world" all "
It contains white space that may be spaces or tabs, or a combination, and I want to produce an array with the following elements
arr(0) = "MyString" arr(1) = 40 arr(2) = "Hello world" arr(3) = "all"
Using trim and a regular expression ("\s+"), I can reduce my string to
"MyString 40 "Hello world" all"
and with Split I can get
arr(0) = "MyString" arr(1) = 40 arr(2) = ""Hello" arr(3) = "world"" arr(4) = "all"
As you can see, it is not quite what I need. The spaces in "Hello world" have been reduced to a single space, and Split does not respect the double quotes, and splits "Hello world" over two elements.
Does anyone have an idea how I could do this? I could process the string character by character, but I am hoping that there is a straight-forward technique for doing it, without looping, and using some of the techniques I already have.
TIA
Charles
Charles,
I was looking at the problem, I was thinking will I give my answer because
it is so difficult to describe. Than I saw that it was you. Therefore it
should not be a problem.
In this kind of situations I replace the spaces I will not use for an
absolute unused character.
Do the split
And replace the unused character again back for a space
I assume that this is for you more than enough explanation.
And now you read this you say, I knew that as well.
:-)))
Cor
"Charles Law" <bl***@nowhere.com>
.... I have a string similar to the following:
" MyString 40 "Hello world" all "
It contains white space that may be spaces or tabs, or a combination, and I want to produce an array with the following elements
arr(0) = "MyString" arr(1) = 40 arr(2) = "Hello world" arr(3) = "all"
Using trim and a regular expression ("\s+"), I can reduce my string to
"MyString 40 "Hello world" all"
and with Split I can get
arr(0) = "MyString" arr(1) = 40 arr(2) = ""Hello" arr(3) = "world"" arr(4) = "all"
As you can see, it is not quite what I need. The spaces in "Hello world" have been reduced to a single space, and Split does not respect the double quotes, and splits "Hello world" over two elements.
Does anyone have an idea how I could do this? I could process the string character by character, but I am hoping that there is a straight-forward technique for doing it, without looping, and using some of the techniques I already have.
TIA
Charles
Hi Cor
You read my mind ;-)
I had thought of using something like #, as it will never occur in my
string. But then I started to look at how I would know which spaces to
replace with #, and which to leave. Of course, to the human eye it is
obvious that I only replace the spaces between " and ", but now I am back to
processing each part of the string character by character so that I match
double quotes correctly, and this is what I was trying to avoid.
Perhaps there is a regex expression that will match double quotes, or a
method that parses a string taking these into account, but sadly I do not
know it yet.
But please, keep the suggestions flowing.
Charles
"Cor Ligthert" <no************@planet.nl> wrote in message
news:OX**************@TK2MSFTNGP09.phx.gbl... Charles,
I was looking at the problem, I was thinking will I give my answer because it is so difficult to describe. Than I saw that it was you. Therefore it should not be a problem.
In this kind of situations I replace the spaces I will not use for an absolute unused character.
Do the split
And replace the unused character again back for a space
I assume that this is for you more than enough explanation.
And now you read this you say, I knew that as well.
:-)))
Cor
"Charles Law" <bl***@nowhere.com>
...I have a string similar to the following:
" MyString 40 "Hello world" all "
It contains white space that may be spaces or tabs, or a combination, and I want to produce an array with the following elements
arr(0) = "MyString" arr(1) = 40 arr(2) = "Hello world" arr(3) = "all"
Using trim and a regular expression ("\s+"), I can reduce my string to
"MyString 40 "Hello world" all"
and with Split I can get
arr(0) = "MyString" arr(1) = 40 arr(2) = ""Hello" arr(3) = "world"" arr(4) = "all"
As you can see, it is not quite what I need. The spaces in "Hello world" have been reduced to a single space, and Split does not respect the double quotes, and splits "Hello world" over two elements.
Does anyone have an idea how I could do this? I could process the string character by character, but I am hoping that there is a straight-forward technique for doing it, without looping, and using some of the techniques I already have.
TIA
Charles
Hi Cor
You read my mind ;-)
I had thought of using something like #, as it will never occur in my
string. But then I started to look at how I would know which spaces to
replace with #, and which to leave. Of course, to the human eye it is
obvious that I only replace the spaces between " and ", but now I am back to
processing each part of the string character by character so that I match
double quotes correctly, and this is what I was trying to avoid.
Perhaps there is a regex expression that will match double quotes, or a
method that parses a string taking these into account, but sadly I do not
know it yet.
But please, keep the suggestions flowing.
Charles
"Cor Ligthert" <no************@planet.nl> wrote in message
news:OX**************@TK2MSFTNGP09.phx.gbl... Charles,
I was looking at the problem, I was thinking will I give my answer because it is so difficult to describe. Than I saw that it was you. Therefore it should not be a problem.
In this kind of situations I replace the spaces I will not use for an absolute unused character.
Do the split
And replace the unused character again back for a space
I assume that this is for you more than enough explanation.
And now you read this you say, I knew that as well.
:-)))
Cor
"Charles Law" <bl***@nowhere.com>
...I have a string similar to the following:
" MyString 40 "Hello world" all "
It contains white space that may be spaces or tabs, or a combination, and I want to produce an array with the following elements
arr(0) = "MyString" arr(1) = 40 arr(2) = "Hello world" arr(3) = "all"
Using trim and a regular expression ("\s+"), I can reduce my string to
"MyString 40 "Hello world" all"
and with Split I can get
arr(0) = "MyString" arr(1) = 40 arr(2) = ""Hello" arr(3) = "world"" arr(4) = "all"
As you can see, it is not quite what I need. The spaces in "Hello world" have been reduced to a single space, and Split does not respect the double quotes, and splits "Hello world" over two elements.
Does anyone have an idea how I could do this? I could process the string character by character, but I am hoping that there is a straight-forward technique for doing it, without looping, and using some of the techniques I already have.
TIA
Charles
Try
(\s*"([\s\w]*)")|(\s*(\w+))
Then do a Replace on each Match object with
$2$4
This will return either your double qouted string with out the qoutes or the
word token without the whitespace characters depending on which match the
Match object holds.
You just have to love Regular Expressions.
--Robby
"Charles Law" <bl***@nowhere.com> wrote in message
news:OP****************@TK2MSFTNGP11.phx.gbl... Hi Cor
You read my mind ;-)
I had thought of using something like #, as it will never occur in my string. But then I started to look at how I would know which spaces to replace with #, and which to leave. Of course, to the human eye it is obvious that I only replace the spaces between " and ", but now I am back to processing each part of the string character by character so that I match double quotes correctly, and this is what I was trying to avoid.
Perhaps there is a regex expression that will match double quotes, or a method that parses a string taking these into account, but sadly I do not know it yet.
But please, keep the suggestions flowing.
Charles
"Cor Ligthert" <no************@planet.nl> wrote in message news:OX**************@TK2MSFTNGP09.phx.gbl... Charles,
I was looking at the problem, I was thinking will I give my answer because it is so difficult to describe. Than I saw that it was you. Therefore it should not be a problem.
In this kind of situations I replace the spaces I will not use for an absolute unused character.
Do the split
And replace the unused character again back for a space
I assume that this is for you more than enough explanation.
And now you read this you say, I knew that as well.
:-)))
Cor
"Charles Law" <bl***@nowhere.com>
...I have a string similar to the following:
" MyString 40 "Hello world" all "
It contains white space that may be spaces or tabs, or a combination, and I want to produce an array with the following elements
arr(0) = "MyString" arr(1) = 40 arr(2) = "Hello world" arr(3) = "all"
Using trim and a regular expression ("\s+"), I can reduce my string to
"MyString 40 "Hello world" all"
and with Split I can get
arr(0) = "MyString" arr(1) = 40 arr(2) = ""Hello" arr(3) = "world"" arr(4) = "all"
As you can see, it is not quite what I need. The spaces in "Hello world" have been reduced to a single space, and Split does not respect the double quotes, and splits "Hello world" over two elements.
Does anyone have an idea how I could do this? I could process the string character by character, but I am hoping that there is a straight-forward technique for doing it, without looping, and using some of the techniques I already have.
TIA
Charles
Hi Robby
Thanks for the reply. I am not sure that I understand the regular expression (\s*"([\s\w]*)")|(\s*(\w+))
I tried the following, but of course it gives a syntax error because of the
embedded double quotes:
Dim reg As Regex = New Regex("(\s*"([\s\w]*)")|(\s*(\w+))")
So I tried escaping the double quotes, like this
Dim reg As Regex = New Regex("(\s*""([\s\w]*)"")|(\s*(\w+))")
but this cleared my string out to a couple of spaces when I did a replace.
Any chance of a small snippet to get me on the right track, using the Match
object?
Thanks very much.
Charles
"Robby" <ed****@not.my.email.com> wrote in message
news:eC**************@TK2MSFTNGP10.phx.gbl... Try
(\s*"([\s\w]*)")|(\s*(\w+))
Then do a Replace on each Match object with
$2$4
This will return either your double qouted string with out the qoutes or the word token without the whitespace characters depending on which match the Match object holds.
You just have to love Regular Expressions.
--Robby
"Charles Law" <bl***@nowhere.com> wrote in message news:OP****************@TK2MSFTNGP11.phx.gbl... Hi Cor
You read my mind ;-)
I had thought of using something like #, as it will never occur in my string. But then I started to look at how I would know which spaces to replace with #, and which to leave. Of course, to the human eye it is obvious that I only replace the spaces between " and ", but now I am back to processing each part of the string character by character so that I match double quotes correctly, and this is what I was trying to avoid.
Perhaps there is a regex expression that will match double quotes, or a method that parses a string taking these into account, but sadly I do not know it yet.
But please, keep the suggestions flowing.
Charles
"Cor Ligthert" <no************@planet.nl> wrote in message news:OX**************@TK2MSFTNGP09.phx.gbl... Charles,
I was looking at the problem, I was thinking will I give my answer because it is so difficult to describe. Than I saw that it was you. Therefore it should not be a problem.
In this kind of situations I replace the spaces I will not use for an absolute unused character.
Do the split
And replace the unused character again back for a space
I assume that this is for you more than enough explanation.
And now you read this you say, I knew that as well.
:-)))
Cor
"Charles Law" <bl***@nowhere.com>
... I have a string similar to the following:
" MyString 40 "Hello world" all "
It contains white space that may be spaces or tabs, or a combination, and I want to produce an array with the following elements
arr(0) = "MyString" arr(1) = 40 arr(2) = "Hello world" arr(3) = "all"
Using trim and a regular expression ("\s+"), I can reduce my string to
"MyString 40 "Hello world" all"
and with Split I can get
arr(0) = "MyString" arr(1) = 40 arr(2) = ""Hello" arr(3) = "world"" arr(4) = "all"
As you can see, it is not quite what I need. The spaces in "Hello world" have been reduced to a single space, and Split does not respect the double quotes, and splits "Hello world" over two elements.
Does anyone have an idea how I could do this? I could process the string character by character, but I am hoping that there is a straight-forward technique for doing it, without looping, and using some of the techniques I already have.
TIA
Charles
Create a console application
#########################
Imports System.Text.RegularExpressions
Module MainModule
Sub Main()
Dim rePost As New Regex("(\s*""([\s\w]*)"")|(\s*(\w+))")
Dim testString As String = "MyString 40 ""Hello world""
all "
Dim allMatches As MatchCollection = rePost.Matches(testString)
Dim matchPiece As Match
Dim I As Integer
For I = 0 To allMatches.Count - 1
matchPiece = allMatches(I)
Console.WriteLine("Piece {0} -> '{1}'", I,
matchPiece.Result("$2$4"))
Next I
End Sub
End Module
####################
--Robby
"Charles Law" <bl***@nowhere.com> wrote in message
news:eI**************@TK2MSFTNGP11.phx.gbl... Hi Robby
Thanks for the reply. I am not sure that I understand the regular expression
(\s*"([\s\w]*)")|(\s*(\w+))
I tried the following, but of course it gives a syntax error because of the embedded double quotes:
Dim reg As Regex = New Regex("(\s*"([\s\w]*)")|(\s*(\w+))")
So I tried escaping the double quotes, like this
Dim reg As Regex = New Regex("(\s*""([\s\w]*)"")|(\s*(\w+))")
but this cleared my string out to a couple of spaces when I did a replace.
Any chance of a small snippet to get me on the right track, using the Match object?
Thanks very much.
Charles
"Robby" <ed****@not.my.email.com> wrote in message news:eC**************@TK2MSFTNGP10.phx.gbl... Try
(\s*"([\s\w]*)")|(\s*(\w+))
Then do a Replace on each Match object with
$2$4
This will return either your double qouted string with out the qoutes or the word token without the whitespace characters depending on which match the Match object holds.
You just have to love Regular Expressions.
--Robby
"Charles Law" <bl***@nowhere.com> wrote in message news:OP****************@TK2MSFTNGP11.phx.gbl... Hi Cor
You read my mind ;-)
I had thought of using something like #, as it will never occur in my string. But then I started to look at how I would know which spaces to replace with #, and which to leave. Of course, to the human eye it is obvious that I only replace the spaces between " and ", but now I am back to processing each part of the string character by character so that I match double quotes correctly, and this is what I was trying to avoid.
Perhaps there is a regex expression that will match double quotes, or a method that parses a string taking these into account, but sadly I do not know it yet.
But please, keep the suggestions flowing.
Charles
"Cor Ligthert" <no************@planet.nl> wrote in message news:OX**************@TK2MSFTNGP09.phx.gbl... Charles,
I was looking at the problem, I was thinking will I give my answer because it is so difficult to describe. Than I saw that it was you. Therefore it should not be a problem.
In this kind of situations I replace the spaces I will not use for an absolute unused character.
Do the split
And replace the unused character again back for a space
I assume that this is for you more than enough explanation.
And now you read this you say, I knew that as well.
:-)))
Cor
"Charles Law" <bl***@nowhere.com>
... >I have a string similar to the following: > > " MyString 40 "Hello world" all " > > It contains white space that may be spaces or tabs, or a combination, > and I want to produce an array with the following elements > > arr(0) = "MyString" > arr(1) = 40 > arr(2) = "Hello world" > arr(3) = "all" > > Using trim and a regular expression ("\s+"), I can reduce my string to > > "MyString 40 "Hello world" all" > > and with Split I can get > > arr(0) = "MyString" > arr(1) = 40 > arr(2) = ""Hello" > arr(3) = "world"" > arr(4) = "all" > > As you can see, it is not quite what I need. The spaces in "Hello > world" have been reduced to a single space, and Split does not respect > the double quotes, and splits "Hello world" over two elements. > > Does anyone have an idea how I could do this? I could process the > string character by character, but I am hoping that there is a > straight-forward technique for doing it, without looping, and using > some of the techniques I already have. > > TIA > > Charles > >
Hi Robby - me again
I have it now; I just needed to apply a few of those grey cells I have
knocking about.
Cheers.
Charles
"Charles Law" <bl***@nowhere.com> wrote in message
news:eI**************@TK2MSFTNGP11.phx.gbl... Hi Robby
Thanks for the reply. I am not sure that I understand the regular expression
(\s*"([\s\w]*)")|(\s*(\w+))
I tried the following, but of course it gives a syntax error because of the embedded double quotes:
Dim reg As Regex = New Regex("(\s*"([\s\w]*)")|(\s*(\w+))")
So I tried escaping the double quotes, like this
Dim reg As Regex = New Regex("(\s*""([\s\w]*)"")|(\s*(\w+))")
but this cleared my string out to a couple of spaces when I did a replace.
Any chance of a small snippet to get me on the right track, using the Match object?
Thanks very much.
Charles
"Robby" <ed****@not.my.email.com> wrote in message news:eC**************@TK2MSFTNGP10.phx.gbl... Try
(\s*"([\s\w]*)")|(\s*(\w+))
Then do a Replace on each Match object with
$2$4
This will return either your double qouted string with out the qoutes or the word token without the whitespace characters depending on which match the Match object holds.
You just have to love Regular Expressions.
--Robby
"Charles Law" <bl***@nowhere.com> wrote in message news:OP****************@TK2MSFTNGP11.phx.gbl... Hi Cor
You read my mind ;-)
I had thought of using something like #, as it will never occur in my string. But then I started to look at how I would know which spaces to replace with #, and which to leave. Of course, to the human eye it is obvious that I only replace the spaces between " and ", but now I am back to processing each part of the string character by character so that I match double quotes correctly, and this is what I was trying to avoid.
Perhaps there is a regex expression that will match double quotes, or a method that parses a string taking these into account, but sadly I do not know it yet.
But please, keep the suggestions flowing.
Charles
"Cor Ligthert" <no************@planet.nl> wrote in message news:OX**************@TK2MSFTNGP09.phx.gbl... Charles,
I was looking at the problem, I was thinking will I give my answer because it is so difficult to describe. Than I saw that it was you. Therefore it should not be a problem.
In this kind of situations I replace the spaces I will not use for an absolute unused character.
Do the split
And replace the unused character again back for a space
I assume that this is for you more than enough explanation.
And now you read this you say, I knew that as well.
:-)))
Cor
"Charles Law" <bl***@nowhere.com>
... >I have a string similar to the following: > > " MyString 40 "Hello world" all " > > It contains white space that may be spaces or tabs, or a combination, > and I want to produce an array with the following elements > > arr(0) = "MyString" > arr(1) = 40 > arr(2) = "Hello world" > arr(3) = "all" > > Using trim and a regular expression ("\s+"), I can reduce my string to > > "MyString 40 "Hello world" all" > > and with Split I can get > > arr(0) = "MyString" > arr(1) = 40 > arr(2) = ""Hello" > arr(3) = "world"" > arr(4) = "all" > > As you can see, it is not quite what I need. The spaces in "Hello > world" have been reduced to a single space, and Split does not respect > the double quotes, and splits "Hello world" over two elements. > > Does anyone have an idea how I could do this? I could process the > string character by character, but I am hoping that there is a > straight-forward technique for doing it, without looping, and using > some of the techniques I already have. > > TIA > > Charles > >
Charles,
Can you give us an idea at the end how much time it took to find the regex
and how much time the straight forward technique and than as well a test
what will be the less time consuming method.
To get a good idea about the discussions using Regex or Straight forward, I
looked at it, and I think Straight forward should take me probably less than
30 minutes, so for you probably less than 15.
:-)
Cor
"Charles Law" <bl***@nowhere.com> Hi Robby
Thanks for the reply. I am not sure that I understand the regular expression
(\s*"([\s\w]*)")|(\s*(\w+))
I tried the following, but of course it gives a syntax error because of the embedded double quotes:
Dim reg As Regex = New Regex("(\s*"([\s\w]*)")|(\s*(\w+))")
So I tried escaping the double quotes, like this
Dim reg As Regex = New Regex("(\s*""([\s\w]*)"")|(\s*(\w+))")
but this cleared my string out to a couple of spaces when I did a replace.
Any chance of a small snippet to get me on the right track, using the Match object?
Thanks very much.
Charles
"Robby" <ed****@not.my.email.com> wrote in message news:eC**************@TK2MSFTNGP10.phx.gbl... Try
(\s*"([\s\w]*)")|(\s*(\w+))
Then do a Replace on each Match object with
$2$4
This will return either your double qouted string with out the qoutes or the word token without the whitespace characters depending on which match the Match object holds.
You just have to love Regular Expressions.
--Robby
"Charles Law" <bl***@nowhere.com> wrote in message news:OP****************@TK2MSFTNGP11.phx.gbl... Hi Cor
You read my mind ;-)
I had thought of using something like #, as it will never occur in my string. But then I started to look at how I would know which spaces to replace with #, and which to leave. Of course, to the human eye it is obvious that I only replace the spaces between " and ", but now I am back to processing each part of the string character by character so that I match double quotes correctly, and this is what I was trying to avoid.
Perhaps there is a regex expression that will match double quotes, or a method that parses a string taking these into account, but sadly I do not know it yet.
But please, keep the suggestions flowing.
Charles
"Cor Ligthert" <no************@planet.nl> wrote in message news:OX**************@TK2MSFTNGP09.phx.gbl... Charles,
I was looking at the problem, I was thinking will I give my answer because it is so difficult to describe. Than I saw that it was you. Therefore it should not be a problem.
In this kind of situations I replace the spaces I will not use for an absolute unused character.
Do the split
And replace the unused character again back for a space
I assume that this is for you more than enough explanation.
And now you read this you say, I knew that as well.
:-)))
Cor
"Charles Law" <bl***@nowhere.com>
... >I have a string similar to the following: > > " MyString 40 "Hello world" all " > > It contains white space that may be spaces or tabs, or a combination, > and I want to produce an array with the following elements > > arr(0) = "MyString" > arr(1) = 40 > arr(2) = "Hello world" > arr(3) = "all" > > Using trim and a regular expression ("\s+"), I can reduce my string to > > "MyString 40 "Hello world" all" > > and with Split I can get > > arr(0) = "MyString" > arr(1) = 40 > arr(2) = ""Hello" > arr(3) = "world"" > arr(4) = "all" > > As you can see, it is not quite what I need. The spaces in "Hello > world" have been reduced to a single space, and Split does not respect > the double quotes, and splits "Hello world" over two elements. > > Does anyone have an idea how I could do this? I could process the > string character by character, but I am hoping that there is a > straight-forward technique for doing it, without looping, and using > some of the techniques I already have. > > TIA > > Charles > >
Thanks again Robby. I came up with something similar in the end, using For
.... Each to go through the match collection, and reg.Replace instead of
match.Result, but it came down to the same thing.
Charles
"Robby" <ed****@not.my.email.com> wrote in message
news:%2****************@TK2MSFTNGP15.phx.gbl... Create a console application
#########################
Imports System.Text.RegularExpressions
Module MainModule
Sub Main()
Dim rePost As New Regex("(\s*""([\s\w]*)"")|(\s*(\w+))") Dim testString As String = "MyString 40 ""Hello world"" all " Dim allMatches As MatchCollection = rePost.Matches(testString)
Dim matchPiece As Match Dim I As Integer
For I = 0 To allMatches.Count - 1 matchPiece = allMatches(I) Console.WriteLine("Piece {0} -> '{1}'", I, matchPiece.Result("$2$4")) Next I
End Sub
End Module
####################
--Robby
"Charles Law" <bl***@nowhere.com> wrote in message news:eI**************@TK2MSFTNGP11.phx.gbl... Hi Robby
Thanks for the reply. I am not sure that I understand the regular expression
(\s*"([\s\w]*)")|(\s*(\w+))
I tried the following, but of course it gives a syntax error because of the embedded double quotes:
Dim reg As Regex = New Regex("(\s*"([\s\w]*)")|(\s*(\w+))")
So I tried escaping the double quotes, like this
Dim reg As Regex = New Regex("(\s*""([\s\w]*)"")|(\s*(\w+))")
but this cleared my string out to a couple of spaces when I did a replace.
Any chance of a small snippet to get me on the right track, using the Match object?
Thanks very much.
Charles
"Robby" <ed****@not.my.email.com> wrote in message news:eC**************@TK2MSFTNGP10.phx.gbl... Try
(\s*"([\s\w]*)")|(\s*(\w+))
Then do a Replace on each Match object with
$2$4
This will return either your double qouted string with out the qoutes or the word token without the whitespace characters depending on which match the Match object holds.
You just have to love Regular Expressions.
--Robby
"Charles Law" <bl***@nowhere.com> wrote in message news:OP****************@TK2MSFTNGP11.phx.gbl... Hi Cor
You read my mind ;-)
I had thought of using something like #, as it will never occur in my string. But then I started to look at how I would know which spaces to replace with #, and which to leave. Of course, to the human eye it is obvious that I only replace the spaces between " and ", but now I am back to processing each part of the string character by character so that I match double quotes correctly, and this is what I was trying to avoid.
Perhaps there is a regex expression that will match double quotes, or a method that parses a string taking these into account, but sadly I do not know it yet.
But please, keep the suggestions flowing.
Charles
"Cor Ligthert" <no************@planet.nl> wrote in message news:OX**************@TK2MSFTNGP09.phx.gbl... > Charles, > > I was looking at the problem, I was thinking will I give my answer > because it is so difficult to describe. Than I saw that it was you. > Therefore it should not be a problem. > > In this kind of situations I replace the spaces I will not use for an > absolute unused character. > > Do the split > > And replace the unused character again back for a space > > I assume that this is for you more than enough explanation. > > And now you read this you say, I knew that as well. > > :-))) > > Cor > > "Charles Law" <bl***@nowhere.com> > > ... >>I have a string similar to the following: >> >> " MyString 40 "Hello world" all " >> >> It contains white space that may be spaces or tabs, or a combination, >> and I want to produce an array with the following elements >> >> arr(0) = "MyString" >> arr(1) = 40 >> arr(2) = "Hello world" >> arr(3) = "all" >> >> Using trim and a regular expression ("\s+"), I can reduce my string >> to >> >> "MyString 40 "Hello world" all" >> >> and with Split I can get >> >> arr(0) = "MyString" >> arr(1) = 40 >> arr(2) = ""Hello" >> arr(3) = "world"" >> arr(4) = "all" >> >> As you can see, it is not quite what I need. The spaces in "Hello >> world" have been reduced to a single space, and Split does not >> respect the double quotes, and splits "Hello world" over two >> elements. >> >> Does anyone have an idea how I could do this? I could process the >> string character by character, but I am hoping that there is a >> straight-forward technique for doing it, without looping, and using >> some of the techniques I already have. >> >> TIA >> >> Charles >> >> > >
Cor
Do you mean how long does it take to parse the string using RegEx against
parsing it character by character, or how long did it take to come up with
the solution?
I think the RegEx solution is by far the neatest, and most flexible. It is
also fewer lines of code. I do not have a solution parsing
character-by-character, so I cannot measure how long to create or run, but I
think you have it about right.
Charles
"Cor Ligthert" <no************@planet.nl> wrote in message
news:um**************@TK2MSFTNGP10.phx.gbl... Charles,
Can you give us an idea at the end how much time it took to find the regex and how much time the straight forward technique and than as well a test what will be the less time consuming method.
To get a good idea about the discussions using Regex or Straight forward, I looked at it, and I think Straight forward should take me probably less than 30 minutes, so for you probably less than 15.
:-)
Cor
"Charles Law" <bl***@nowhere.com> Hi Robby
Thanks for the reply. I am not sure that I understand the regular expression
(\s*"([\s\w]*)")|(\s*(\w+))
I tried the following, but of course it gives a syntax error because of the embedded double quotes:
Dim reg As Regex = New Regex("(\s*"([\s\w]*)")|(\s*(\w+))")
So I tried escaping the double quotes, like this
Dim reg As Regex = New Regex("(\s*""([\s\w]*)"")|(\s*(\w+))")
but this cleared my string out to a couple of spaces when I did a replace.
Any chance of a small snippet to get me on the right track, using the Match object?
Thanks very much.
Charles
"Robby" <ed****@not.my.email.com> wrote in message news:eC**************@TK2MSFTNGP10.phx.gbl... Try
(\s*"([\s\w]*)")|(\s*(\w+))
Then do a Replace on each Match object with
$2$4
This will return either your double qouted string with out the qoutes or the word token without the whitespace characters depending on which match the Match object holds.
You just have to love Regular Expressions.
--Robby
"Charles Law" <bl***@nowhere.com> wrote in message news:OP****************@TK2MSFTNGP11.phx.gbl... Hi Cor
You read my mind ;-)
I had thought of using something like #, as it will never occur in my string. But then I started to look at how I would know which spaces to replace with #, and which to leave. Of course, to the human eye it is obvious that I only replace the spaces between " and ", but now I am back to processing each part of the string character by character so that I match double quotes correctly, and this is what I was trying to avoid.
Perhaps there is a regex expression that will match double quotes, or a method that parses a string taking these into account, but sadly I do not know it yet.
But please, keep the suggestions flowing.
Charles
"Cor Ligthert" <no************@planet.nl> wrote in message news:OX**************@TK2MSFTNGP09.phx.gbl... > Charles, > > I was looking at the problem, I was thinking will I give my answer > because it is so difficult to describe. Than I saw that it was you. > Therefore it should not be a problem. > > In this kind of situations I replace the spaces I will not use for an > absolute unused character. > > Do the split > > And replace the unused character again back for a space > > I assume that this is for you more than enough explanation. > > And now you read this you say, I knew that as well. > > :-))) > > Cor > > "Charles Law" <bl***@nowhere.com> > > ... >>I have a string similar to the following: >> >> " MyString 40 "Hello world" all " >> >> It contains white space that may be spaces or tabs, or a combination, >> and I want to produce an array with the following elements >> >> arr(0) = "MyString" >> arr(1) = 40 >> arr(2) = "Hello world" >> arr(3) = "all" >> >> Using trim and a regular expression ("\s+"), I can reduce my string >> to >> >> "MyString 40 "Hello world" all" >> >> and with Split I can get >> >> arr(0) = "MyString" >> arr(1) = 40 >> arr(2) = ""Hello" >> arr(3) = "world"" >> arr(4) = "all" >> >> As you can see, it is not quite what I need. The spaces in "Hello >> world" have been reduced to a single space, and Split does not >> respect the double quotes, and splits "Hello world" over two >> elements. >> >> Does anyone have an idea how I could do this? I could process the >> string character by character, but I am hoping that there is a >> straight-forward technique for doing it, without looping, and using >> some of the techniques I already have. >> >> TIA >> >> Charles >> >> > >
Hummm ... It took me two tries to get this Regular Expression. I don't
have the oportunity to use Regex a lot but I quite like them and dive in if
I have a spare moment. I'd say 4 to 6 minutes to solve it. In the old VB6
days I would have done a Find to get my qoute indexes, split with the double
qoute and resplit those outside the double qoute. Then trimmed them. That
would take more time to code and check for errors.
Robby
"Cor Ligthert" <no************@planet.nl> wrote in message
news:um**************@TK2MSFTNGP10.phx.gbl... Charles,
Can you give us an idea at the end how much time it took to find the regex and how much time the straight forward technique and than as well a test what will be the less time consuming method.
To get a good idea about the discussions using Regex or Straight forward, I looked at it, and I think Straight forward should take me probably less than 30 minutes, so for you probably less than 15.
:-)
Cor
"Charles Law" <bl***@nowhere.com> Hi Robby
Thanks for the reply. I am not sure that I understand the regular expression
(\s*"([\s\w]*)")|(\s*(\w+))
I tried the following, but of course it gives a syntax error because of the embedded double quotes:
Dim reg As Regex = New Regex("(\s*"([\s\w]*)")|(\s*(\w+))")
So I tried escaping the double quotes, like this
Dim reg As Regex = New Regex("(\s*""([\s\w]*)"")|(\s*(\w+))")
but this cleared my string out to a couple of spaces when I did a replace.
Any chance of a small snippet to get me on the right track, using the Match object?
Thanks very much.
Charles
"Robby" <ed****@not.my.email.com> wrote in message news:eC**************@TK2MSFTNGP10.phx.gbl... Try
(\s*"([\s\w]*)")|(\s*(\w+))
Then do a Replace on each Match object with
$2$4
This will return either your double qouted string with out the qoutes or the word token without the whitespace characters depending on which match the Match object holds.
You just have to love Regular Expressions.
--Robby
"Charles Law" <bl***@nowhere.com> wrote in message news:OP****************@TK2MSFTNGP11.phx.gbl... Hi Cor
You read my mind ;-)
I had thought of using something like #, as it will never occur in my string. But then I started to look at how I would know which spaces to replace with #, and which to leave. Of course, to the human eye it is obvious that I only replace the spaces between " and ", but now I am back to processing each part of the string character by character so that I match double quotes correctly, and this is what I was trying to avoid.
Perhaps there is a regex expression that will match double quotes, or a method that parses a string taking these into account, but sadly I do not know it yet.
But please, keep the suggestions flowing.
Charles
"Cor Ligthert" <no************@planet.nl> wrote in message news:OX**************@TK2MSFTNGP09.phx.gbl... > Charles, > > I was looking at the problem, I was thinking will I give my answer > because it is so difficult to describe. Than I saw that it was you. > Therefore it should not be a problem. > > In this kind of situations I replace the spaces I will not use for an > absolute unused character. > > Do the split > > And replace the unused character again back for a space > > I assume that this is for you more than enough explanation. > > And now you read this you say, I knew that as well. > > :-))) > > Cor > > "Charles Law" <bl***@nowhere.com> > > ... >>I have a string similar to the following: >> >> " MyString 40 "Hello world" all " >> >> It contains white space that may be spaces or tabs, or a combination, >> and I want to produce an array with the following elements >> >> arr(0) = "MyString" >> arr(1) = 40 >> arr(2) = "Hello world" >> arr(3) = "all" >> >> Using trim and a regular expression ("\s+"), I can reduce my string >> to >> >> "MyString 40 "Hello world" all" >> >> and with Split I can get >> >> arr(0) = "MyString" >> arr(1) = 40 >> arr(2) = ""Hello" >> arr(3) = "world"" >> arr(4) = "all" >> >> As you can see, it is not quite what I need. The spaces in "Hello >> world" have been reduced to a single space, and Split does not >> respect the double quotes, and splits "Hello world" over two >> elements. >> >> Does anyone have an idea how I could do this? I could process the >> string character by character, but I am hoping that there is a >> straight-forward technique for doing it, without looping, and using >> some of the techniques I already have. >> >> TIA >> >> Charles >> >> > >
Charles and Robby,
I was meaning "thinking, writing and performance".
Because I had said it, I had the idea I should do it.
This is the first time I see a regex faster than a straight foreward loop.
Imports System.Text.RegularExpressions
Public Class Hello
Public Shared Sub main()
Dim start As Integer = Environment.TickCount
For y As Integer = 0 To 10000
Dim mystring As String = _
" MyString 40 ""Hello world"" all"
Dim myarrlist As New ArrayList
Dim endWord As Integer
For i As Integer = 0 To mystring.Length - 1
If mystring.Substring(i, 1) <> " " Then
If mystring.Substring(i, 1) = """" Then
endWord = mystring.Substring(i + 1).IndexOf("""") +
1
myarrlist.Add(mystring.Substring(i + 1, endWord -
1))
i = i + endWord
Else
endWord = mystring.Substring(i).IndexOf(" ")
If endWord = -1 Then endWord = mystring.Length - i
myarrlist.Add(mystring.Substring(i, endWord))
i = i + endWord
End If
End If
Next
Next
Console.WriteLine((Environment.TickCount - start).ToString)
'Regex
start = Environment.TickCount
For y As Integer = 0 To 10000
Dim testString As String = "MyString 40 ""Hello world""
all "
Dim rePost As New Regex("(\s*""([\s\w]*)"")|(\s*(\w+))")
Dim allMatches As MatchCollection = rePost.Matches(testString)
Next
Console.WriteLine((Environment.TickCount - start).ToString)
End Sub
End Class
///
The speed is for me about 3:2 where I did not really study to get the loop
faster, because is should be done in a short time as I said.
So Charles next time you have to message "Robby can you help me again?"
Because it is of course a wonderfull thing done with Regex what Robby did.
:-)
Cor
"Charles Law" <bl***@nowhere.com> Cor
Do you mean how long does it take to parse the string using RegEx against parsing it character by character, or how long did it take to come up with the solution?
I think the RegEx solution is by far the neatest, and most flexible. It is also fewer lines of code. I do not have a solution parsing character-by-character, so I cannot measure how long to create or run, but I think you have it about right.
Charles
"Cor Ligthert" <no************@planet.nl> wrote in message news:um**************@TK2MSFTNGP10.phx.gbl... Charles,
Can you give us an idea at the end how much time it took to find the regex and how much time the straight forward technique and than as well a test what will be the less time consuming method.
To get a good idea about the discussions using Regex or Straight forward, I looked at it, and I think Straight forward should take me probably less than 30 minutes, so for you probably less than 15.
:-)
Cor
"Charles Law" <bl***@nowhere.com> Hi Robby
Thanks for the reply. I am not sure that I understand the regular expression
(\s*"([\s\w]*)")|(\s*(\w+))
I tried the following, but of course it gives a syntax error because of the embedded double quotes:
Dim reg As Regex = New Regex("(\s*"([\s\w]*)")|(\s*(\w+))")
So I tried escaping the double quotes, like this
Dim reg As Regex = New Regex("(\s*""([\s\w]*)"")|(\s*(\w+))")
but this cleared my string out to a couple of spaces when I did a replace.
Any chance of a small snippet to get me on the right track, using the Match object?
Thanks very much.
Charles
"Robby" <ed****@not.my.email.com> wrote in message news:eC**************@TK2MSFTNGP10.phx.gbl...
Try
(\s*"([\s\w]*)")|(\s*(\w+))
Then do a Replace on each Match object with
$2$4
This will return either your double qouted string with out the qoutes or the word token without the whitespace characters depending on which match the Match object holds.
You just have to love Regular Expressions.
--Robby
"Charles Law" <bl***@nowhere.com> wrote in message news:OP****************@TK2MSFTNGP11.phx.gbl... > Hi Cor > > You read my mind ;-) > > I had thought of using something like #, as it will never occur in my > string. But then I started to look at how I would know which spaces to > replace with #, and which to leave. Of course, to the human eye it is > obvious that I only replace the spaces between " and ", but now I am > back to processing each part of the string character by character so > that I match double quotes correctly, and this is what I was trying to > avoid. > > Perhaps there is a regex expression that will match double quotes, or > a method that parses a string taking these into account, but sadly I > do not know it yet. > > But please, keep the suggestions flowing. > > Charles > > > "Cor Ligthert" <no************@planet.nl> wrote in message > news:OX**************@TK2MSFTNGP09.phx.gbl... >> Charles, >> >> I was looking at the problem, I was thinking will I give my answer >> because it is so difficult to describe. Than I saw that it was you. >> Therefore it should not be a problem. >> >> In this kind of situations I replace the spaces I will not use for an >> absolute unused character. >> >> Do the split >> >> And replace the unused character again back for a space >> >> I assume that this is for you more than enough explanation. >> >> And now you read this you say, I knew that as well. >> >> :-))) >> >> Cor >> >> "Charles Law" <bl***@nowhere.com> >> >> ... >>>I have a string similar to the following: >>> >>> " MyString 40 "Hello world" all " >>> >>> It contains white space that may be spaces or tabs, or a >>> combination, and I want to produce an array with the following >>> elements >>> >>> arr(0) = "MyString" >>> arr(1) = 40 >>> arr(2) = "Hello world" >>> arr(3) = "all" >>> >>> Using trim and a regular expression ("\s+"), I can reduce my string >>> to >>> >>> "MyString 40 "Hello world" all" >>> >>> and with Split I can get >>> >>> arr(0) = "MyString" >>> arr(1) = 40 >>> arr(2) = ""Hello" >>> arr(3) = "world"" >>> arr(4) = "all" >>> >>> As you can see, it is not quite what I need. The spaces in "Hello >>> world" have been reduced to a single space, and Split does not >>> respect the double quotes, and splits "Hello world" over two >>> elements. >>> >>> Does anyone have an idea how I could do this? I could process the >>> string character by character, but I am hoping that there is a >>> straight-forward technique for doing it, without looping, and using >>> some of the techniques I already have. >>> >>> TIA >>> >>> Charles >>> >>> >> >> > >
Robby
I have just come across a valid (in my context) string that is split into
too many matches. The string is
"PartA PartB PartC(plus) PartD"
The regex breaks it into
PartA
PartB
PartC
plus
PartD
Can you see a refinement for the regular expression to keep PartC(plus) as
one element?
Charles
"Robby" <ed****@not.my.email.com> wrote in message
news:eC**************@TK2MSFTNGP10.phx.gbl... Try
(\s*"([\s\w]*)")|(\s*(\w+))
Then do a Replace on each Match object with
$2$4
This will return either your double qouted string with out the qoutes or the word token without the whitespace characters depending on which match the Match object holds.
You just have to love Regular Expressions.
--Robby
"Charles Law" <bl***@nowhere.com> wrote in message news:OP****************@TK2MSFTNGP11.phx.gbl... Hi Cor
You read my mind ;-)
I had thought of using something like #, as it will never occur in my string. But then I started to look at how I would know which spaces to replace with #, and which to leave. Of course, to the human eye it is obvious that I only replace the spaces between " and ", but now I am back to processing each part of the string character by character so that I match double quotes correctly, and this is what I was trying to avoid.
Perhaps there is a regex expression that will match double quotes, or a method that parses a string taking these into account, but sadly I do not know it yet.
But please, keep the suggestions flowing.
Charles
"Cor Ligthert" <no************@planet.nl> wrote in message news:OX**************@TK2MSFTNGP09.phx.gbl... Charles,
I was looking at the problem, I was thinking will I give my answer because it is so difficult to describe. Than I saw that it was you. Therefore it should not be a problem.
In this kind of situations I replace the spaces I will not use for an absolute unused character.
Do the split
And replace the unused character again back for a space
I assume that this is for you more than enough explanation.
And now you read this you say, I knew that as well.
:-)))
Cor
"Charles Law" <bl***@nowhere.com>
... I have a string similar to the following:
" MyString 40 "Hello world" all "
It contains white space that may be spaces or tabs, or a combination, and I want to produce an array with the following elements
arr(0) = "MyString" arr(1) = 40 arr(2) = "Hello world" arr(3) = "all"
Using trim and a regular expression ("\s+"), I can reduce my string to
"MyString 40 "Hello world" all"
and with Split I can get
arr(0) = "MyString" arr(1) = 40 arr(2) = ""Hello" arr(3) = "world"" arr(4) = "all"
As you can see, it is not quite what I need. The spaces in "Hello world" have been reduced to a single space, and Split does not respect the double quotes, and splits "Hello world" over two elements.
Does anyone have an idea how I could do this? I could process the string character by character, but I am hoping that there is a straight-forward technique for doing it, without looping, and using some of the techniques I already have.
TIA
Charles
Also, despite what I said earlier to Cor, # could appear in my string, and
it also causes a split when I don't want it to. In fact, the only characters
that should cause a split (outside matched double quotes) are
space, tab, CR, LF, FF, or other control characters
Any ideas?
Charles
"Robby" <ed****@not.my.email.com> wrote in message
news:eC**************@TK2MSFTNGP10.phx.gbl... Try
(\s*"([\s\w]*)")|(\s*(\w+))
Then do a Replace on each Match object with
$2$4
This will return either your double qouted string with out the qoutes or the word token without the whitespace characters depending on which match the Match object holds.
You just have to love Regular Expressions.
--Robby
"Charles Law" <bl***@nowhere.com> wrote in message news:OP****************@TK2MSFTNGP11.phx.gbl... Hi Cor
You read my mind ;-)
I had thought of using something like #, as it will never occur in my string. But then I started to look at how I would know which spaces to replace with #, and which to leave. Of course, to the human eye it is obvious that I only replace the spaces between " and ", but now I am back to processing each part of the string character by character so that I match double quotes correctly, and this is what I was trying to avoid.
Perhaps there is a regex expression that will match double quotes, or a method that parses a string taking these into account, but sadly I do not know it yet.
But please, keep the suggestions flowing.
Charles
"Cor Ligthert" <no************@planet.nl> wrote in message news:OX**************@TK2MSFTNGP09.phx.gbl... Charles,
I was looking at the problem, I was thinking will I give my answer because it is so difficult to describe. Than I saw that it was you. Therefore it should not be a problem.
In this kind of situations I replace the spaces I will not use for an absolute unused character.
Do the split
And replace the unused character again back for a space
I assume that this is for you more than enough explanation.
And now you read this you say, I knew that as well.
:-)))
Cor
"Charles Law" <bl***@nowhere.com>
... I have a string similar to the following:
" MyString 40 "Hello world" all "
It contains white space that may be spaces or tabs, or a combination, and I want to produce an array with the following elements
arr(0) = "MyString" arr(1) = 40 arr(2) = "Hello world" arr(3) = "all"
Using trim and a regular expression ("\s+"), I can reduce my string to
"MyString 40 "Hello world" all"
and with Split I can get
arr(0) = "MyString" arr(1) = 40 arr(2) = ""Hello" arr(3) = "world"" arr(4) = "all"
As you can see, it is not quite what I need. The spaces in "Hello world" have been reduced to a single space, and Split does not respect the double quotes, and splits "Hello world" over two elements.
Does anyone have an idea how I could do this? I could process the string character by character, but I am hoping that there is a straight-forward technique for doing it, without looping, and using some of the techniques I already have.
TIA
Charles
I think I have it. I have changed the pattern to
(\s*""([\s\w\x23\x28\x29]*)"")|(\s*([\w\x23\x28\x29]+))
which seems to do the trick, unless anyone can spot a flaw in this.
Charles
"Charles Law" <bl***@nowhere.com> wrote in message
news:en**************@TK2MSFTNGP11.phx.gbl... Also, despite what I said earlier to Cor, # could appear in my string, and it also causes a split when I don't want it to. In fact, the only characters that should cause a split (outside matched double quotes) are
space, tab, CR, LF, FF, or other control characters
Any ideas?
Charles
"Robby" <ed****@not.my.email.com> wrote in message news:eC**************@TK2MSFTNGP10.phx.gbl... Try
(\s*"([\s\w]*)")|(\s*(\w+))
Then do a Replace on each Match object with
$2$4
This will return either your double qouted string with out the qoutes or the word token without the whitespace characters depending on which match the Match object holds.
You just have to love Regular Expressions.
--Robby
"Charles Law" <bl***@nowhere.com> wrote in message news:OP****************@TK2MSFTNGP11.phx.gbl... Hi Cor
You read my mind ;-)
I had thought of using something like #, as it will never occur in my string. But then I started to look at how I would know which spaces to replace with #, and which to leave. Of course, to the human eye it is obvious that I only replace the spaces between " and ", but now I am back to processing each part of the string character by character so that I match double quotes correctly, and this is what I was trying to avoid.
Perhaps there is a regex expression that will match double quotes, or a method that parses a string taking these into account, but sadly I do not know it yet.
But please, keep the suggestions flowing.
Charles
"Cor Ligthert" <no************@planet.nl> wrote in message news:OX**************@TK2MSFTNGP09.phx.gbl... Charles,
I was looking at the problem, I was thinking will I give my answer because it is so difficult to describe. Than I saw that it was you. Therefore it should not be a problem.
In this kind of situations I replace the spaces I will not use for an absolute unused character.
Do the split
And replace the unused character again back for a space
I assume that this is for you more than enough explanation.
And now you read this you say, I knew that as well.
:-)))
Cor
"Charles Law" <bl***@nowhere.com>
... >I have a string similar to the following: > > " MyString 40 "Hello world" all " > > It contains white space that may be spaces or tabs, or a combination, > and I want to produce an array with the following elements > > arr(0) = "MyString" > arr(1) = 40 > arr(2) = "Hello world" > arr(3) = "all" > > Using trim and a regular expression ("\s+"), I can reduce my string to > > "MyString 40 "Hello world" all" > > and with Split I can get > > arr(0) = "MyString" > arr(1) = 40 > arr(2) = ""Hello" > arr(3) = "world"" > arr(4) = "all" > > As you can see, it is not quite what I need. The spaces in "Hello > world" have been reduced to a single space, and Split does not respect > the double quotes, and splits "Hello world" over two elements. > > Does anyone have an idea how I could do this? I could process the > string character by character, but I am hoping that there is a > straight-forward technique for doing it, without looping, and using > some of the techniques I already have. > > TIA > > Charles > >
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Hi,
I just want to parse a character string as below
Char * c=abcsyd"loddggg"kjskjdfsdf;
I need to stripe out loddgg from c (inside ""). How can i do this in
c?
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