You could always take the easy (simplest algorition) way out:
sum = 0
for i = 1 to 01A6DC6B07262F69H
sum = sum+1
end for
<G>
Perhaps there's a clue to the algorithm in the source of the problem and the
signifigance of the inputs.
Tom Rethard
UT Arlington
"Herfried K. Wagner [MVP]" <hi***************@gmx.at> wrote in message
news:c6************@ID-208219.news.uni-berlin.de...
* "Federico Babelis" <fe******@gazum.com> scripsit: Any could help my find how to create the code for the following
algorythm:
In1: 10000000
In2: 00000000000
the algorythm runs and this is the output:
01A6DC6B07262F69
I think it's impossible to find the code, except this solution:
\\\
Public Function Foo(ByVal In1 As String, ByVal In2 As String) As String
If In1 = "10000000" And In2 = ... Then
Return "01A6..."
Else
...
End If
End Function
///
SCNR
--
Herfried K. Wagner [MVP]
<URL:http://dotnet.mvps.org/>