Replace a letter in a string

[Dinko Deranja]

Suppose that you have a string e.g. "delicious" and an integer e.g. 5. How
to
replace the character at position 5 with next character (in position 6) so
that "delicious" becomes "deliicous" ?

[NM]

I suggest that :

Dim myWord As String = "delicious"

Dim myWordInChar As Char() = myWord.ToCharArray()

Dim tmp As Char = myWordInChar(4)

myWordInChar(4) = myWordInChar(5)

myWordInChar(5) = tmp

myWord = New String(myWordInChar)

"Dinko Deranja" <dd******@public.srce.hr> a écrit dans le message de
news:%2****************@tk2msftngp13.phx.gbl...

Suppose that you have a string e.g. "delicious" and an integer e.g. 5. How
to
replace the character at position 5 with next character (in position 6) so
that "delicious" becomes "deliicous" ?

[NM]

I suggest that :

Dim myWord As String = "delicious"

Dim myWordInChar As Char() = myWord.ToCharArray()

Dim tmp As Char = myWordInChar(4)

myWordInChar(4) = myWordInChar(5)

myWordInChar(5) = tmp

myWord = New String(myWordInChar)

"Dinko Deranja" <dd******@public.srce.hr> a écrit dans le message de
news:%2****************@tk2msftngp13.phx.gbl...

Suppose that you have a string e.g. "delicious" and an integer e.g. 5. How
to
replace the character at position 5 with next character (in position 6) so
that "delicious" becomes "deliicous" ?

[Cor]

I go for

dim a as string = "delicious"
dim b as string = a.substring(0,4) & a.substring(3)

Cor

Suppose that you have a string e.g. "delicious" and an integer e.g. 5. How
to
replace the character at position 5 with next character (in position 6) so
that "delicious" becomes "deliicous" ?

[Cor]

I go for

dim a as string = "delicious"
dim b as string = a.substring(0,4) & a.substring(3)

Cor

Suppose that you have a string e.g. "delicious" and an integer e.g. 5. How
to
replace the character at position 5 with next character (in position 6) so
that "delicious" becomes "deliicous" ?