I have written a VB.Net program. This program has a ConetxtMenu1.
ContextMenu1 is very big and has many levels. There are so many procedures
and depending upon the logic many times a menu item would be visible or
hidden.
I have noticed that in one procedure I am setting the value of a menuitem's
visible property as TRUE but still it is invisible in the Menu.
I have even tested by putting the last statement of the procedure which
executes (opens) the contextmenu as menuitem15.visible = true. So to
understand the structure of the code is :
Button1_Click()
code line 1
code line 2
....
....
....
code line 100
me.contextmenu.show(me.button1, new point(0,0) ------------------- this is
second last line of the code
menuitem15.visible = 15 ----------------- this last line of the code
---------
So the menus opens but still the menutime15 is not visible. Whatever might
be written in the code between line 1 to line 100 (i.e. whether menutime15
is set to visilble or hidden) it should be visible becaue the last line of
the code make it visible.)
I have spent 10 hours in solving this..........................whether this
is a bug?
Thanks in advace! 9 1971
* "I_AM_DON_AND_YOU?" <us**@domain.com> scripsit: I have noticed that in one procedure I am setting the value of a menuitem's visible property as TRUE but still it is invisible in the Menu.
I have even tested by putting the last statement of the procedure which executes (opens) the contextmenu as menuitem15.visible = true. So to understand the structure of the code is :
Button1_Click()
code line 1 code line 2 ... ... ... code line 100
me.contextmenu.show(me.button1, new point(0,0) ------------------- this is second last line of the code menuitem15.visible = 15 ----------------- this last line of the code
You will have to make the menu item visible before showing the context menu.
--
Herfried K. Wagner
MVP · VB Classic, VB.NET
<http://www.mvps.org/dotnet>
i did that "before" , "after", "left", "right", "up", "down" everywhere.
"Herfried K. Wagner [MVP]" <hi***************@gmx.at> wrote in message
news:bn************@ID-208219.news.uni-berlin.de... * "I_AM_DON_AND_YOU?" <us**@domain.com> scripsit: I have noticed that in one procedure I am setting the value of a
menuitem's visible property as TRUE but still it is invisible in the Menu.
I have even tested by putting the last statement of the procedure which executes (opens) the contextmenu as menuitem15.visible = true. So to understand the structure of the code is :
Button1_Click()
code line 1 code line 2 ... ... ... code line 100
me.contextmenu.show(me.button1, new point(0,0) ------------------- this
is second last line of the code menuitem15.visible = 15 ----------------- this last line of the code You will have to make the menu item visible before showing the context
menu. -- Herfried K. Wagner MVP · VB Classic, VB.NET <http://www.mvps.org/dotnet>
....and you know what i also have written (before and after showing the
contextmenu statement):
msgbox menuitem15.visible
and message box shows "TRUE". That means menuitem15.visible = True but
still menuitem15 is not visible.
"Herfried K. Wagner [MVP]" <hi***************@gmx.at> wrote in message
news:bn************@ID-208219.news.uni-berlin.de... * "I_AM_DON_AND_YOU?" <us**@domain.com> scripsit: I have noticed that in one procedure I am setting the value of a
menuitem's visible property as TRUE but still it is invisible in the Menu.
I have even tested by putting the last statement of the procedure which executes (opens) the contextmenu as menuitem15.visible = true. So to understand the structure of the code is :
Button1_Click()
code line 1 code line 2 ... ... ... code line 100
me.contextmenu.show(me.button1, new point(0,0) ------------------- this
is second last line of the code menuitem15.visible = 15 ----------------- this last line of the code You will have to make the menu item visible before showing the context
menu. -- Herfried K. Wagner MVP · VB Classic, VB.NET <http://www.mvps.org/dotnet>
I_AM_DON_AND_YOU,
In addition to Herfried's comments.
Can you post the form you are having problems with?
Which version of VS.NET?
Which OS?
Does this occur only while debugging or in release builds also?
Does it occur on other machines, or just your machine?
Hope this helps
Jay
"I_AM_DON_AND_YOU?" <us**@domain.com> wrote in message
news:O1**************@TK2MSFTNGP11.phx.gbl... I have written a VB.Net program. This program has a ConetxtMenu1. ContextMenu1 is very big and has many levels. There are so many procedures and depending upon the logic many times a menu item would be visible or hidden.
I have noticed that in one procedure I am setting the value of a
menuitem's visible property as TRUE but still it is invisible in the Menu.
I have even tested by putting the last statement of the procedure which executes (opens) the contextmenu as menuitem15.visible = true. So to understand the structure of the code is :
Button1_Click()
code line 1 code line 2 ... ... ... code line 100
me.contextmenu.show(me.button1, new point(0,0) ------------------- this is second last line of the code menuitem15.visible = 15 ----------------- this last line of the code
---------
So the menus opens but still the menutime15 is not visible. Whatever might be written in the code between line 1 to line 100 (i.e. whether
menutime15 is set to visilble or hidden) it should be visible becaue the last line of the code make it visible.)
I have spent 10 hours in solving this..........................whether
this is a bug?
Thanks in advace!
On Tue, 21 Oct 2003 14:49:14 -0700, "I_AM_DON_AND_YOU?"
<us**@domain.com> wrote: i did that "before" , "after", "left", "right", "up", "down" everywhere.
This works:
Private Sub Whatever()
Dim oMenu As New ContextMenu()
oMenu.MenuItems.Add("Test 1")
oMenu.MenuItems.Add("Test 2")
oMenu.MenuItems.Add("Test 3")
oMenu.MenuItems.Add("Test 4").Visible = False
Me.ContextMenu = oMenu
Me.ContextMenu.Show(Button1, New Point(0, 0))
End Sub
So what are you doing differently?
"Herfried K. Wagner [MVP]" <hi***************@gmx.at> wrote in message news:bn************@ID-208219.news.uni-berlin.de... * "I_AM_DON_AND_YOU?" <us**@domain.com> scripsit: > I have noticed that in one procedure I am setting the value of amenuitem's > visible property as TRUE but still it is invisible in the Menu. > > I have even tested by putting the last statement of the procedure which > executes (opens) the contextmenu as menuitem15.visible = true. So to > understand the structure of the code is : > > Button1_Click() > > code line 1 > code line 2 > ... > ... > ... > code line 100 > > > me.contextmenu.show(me.button1, new point(0,0) ------------------- thisis > second last line of the code > menuitem15.visible = 15 ----------------- this last line of the code
You will have to make the menu item visible before showing the context menu. -- Herfried K. Wagner MVP · VB Classic, VB.NET <http://www.mvps.org/dotnet>
Hi Don,
If you could zip up the project (forget the setup one) and post it then we
can have a go. Include everything that we'll need (eg, including a copy of the
notepad file) but not the obj or bin directories (which will be recreated).
Then we can all be talking about the same thing.
Regards,
Fergus
On Tue, 21 Oct 2003 15:48:22 -0700, "I_AM_DON_AND_YOU?"
<us**@domain.com> wrote: Ok, post the code for the button_click function. But quickly to confirm: you are adding to a ContextMenu object, then applying the ContextMenu to the form, and then showing it. Yes?
Yes.
Ok. So here is the code written in the button. When for the first time I click this button it shows the menuitem GLS10. However when I when some values are changed in the mymenu.txt then it doesn't display. However the last-line of the code is setting the value of GLS10 as visible = true. The message box shows "TRUE". But the GLS10 doesn't show-up. (I have delete most of the code which I think would have any impact on overall procedure)
That code works for me. I hard-coded the value of the textbox as:
TextBox1.Text = vbCrLf & "11111111" & vbCrLf & "1"
In my implementation (I snipped some of the menu items). I don't
suppose this is anything to do with the first blank line?
(TextBox1.Lines(index) - index starts at zero). The menu items toggle
quite happily with my replacing 1 with 0 anywhere...
So what's this other code you snipped? Just more menu items?
Hi Don,
It would be nice to make that menu code generic rather than have
hard-coded character positions against hard-coded menu items!! Change one and,
'oh, boy - what a lot of editing to be done'. This is prone to error too. ;-)
Even if you don't do that, you can at least shorten your code.
This
If row1.Substring(2, 1) = "1" Then
AR.Visible = True
Else
AR.Visible = False
End If
could be done as:
AR.Visible = (row1.Substring(2, 1) = "1")
If you post your project then it can be tested.
Regards,
Fergus
Don,
As Fergus stated, zip the entire project with the form you are having
problems with. We do not need the setup project. The cut & paste code in
your other post is not enough to see what is going on. If we see what is
going on, we can offer better advice on what is wrong. Does it occur on other machines, or just your machine? Not tested (because still in development)
By including the entire form, we can run the form as is on different
versions of .NET & different OSs to help track down where the problem is. As
the problem may be an OS version or .NET version specific issue. Which version of VS.NET? (Visual Studio.Net (.Net Framework 1.0))
I was asking if you are using VS.NET 2002 or VS.NET 2003, it sounds like you
are using VS.NET 2002.
Hope this helps
Jay
"I_AM_DON_AND_YOU?" <us**@domain.com> wrote in message
news:OO**************@TK2MSFTNGP11.phx.gbl... Can you post the form you are having problems with? It's a solution with 2 projects. First project 3 form. Second Project is a setup project.
Which version of VS.NET? (Visual Studio.Net (.Net Framework 1.0))
Which OS? Windows 2000 Server (SP3)
Does this occur only while debugging or in release builds also? Both.
Does it occur on other machines, or just your machine? Noted tested (because still in development)
Hope this helps ????
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