Bash Process Substitution

[tanvalley]

In this sequence at the command prompt

$ x=()
$ { while read;  do  x+=("$REPLY"); done; } <<<"$(ls)"
$ printf 'count=%d\n' ${#x[@]}
count=432
$ wc -l <(ls)
     432 /dev/fd/63
$ 
$ 
$ { while read;  do  x+=("$REPLY"); done; } <(ls)
-bash: syntax error near unexpected token `<(ls)'
 

what causes the error noted?

Doing

$ x=()
$ ls | { while read; do x+=("$REPLY"); done }
$  printf 'count=%d\n' ${#x[@]}
count=0
$
$

runs without error, but executes the loop in a subprocess, losing the results on termination
BASH 3.2.57(1)-release on OS X 10.10.5

[numberwhun]

Have you tried adding a $ before the (ls), like so:

{ while read;  do  x+=("$REPLY"); done; } < $(ls)