Scott Levine from Atlanta?
Here's an example that might help, depending on your exact definition of
"transposed". This query finds rows with exactly the same digits in any
order.
CREATE TABLE SomeTable (x INTEGER NOT NULL)
/* Sample data */
INSERT INTO SomeTable (x) VALUES (3412)
INSERT INTO SomeTable (x) VALUES (4567)
INSERT INTO SomeTable (x) VALUES (4321)
SELECT T1.x
FROM SomeTable AS T1
JOIN SomeTable AS T2
ON
REPLICATE('0',LEN(T1.x)-LEN(REPLACE(T1.x,'0','')))
+REPLICATE('1',LEN(T1.x)-LEN(REPLACE(T1.x,'1','')))
+REPLICATE('2',LEN(T1.x)-LEN(REPLACE(T1.x,'2','')))
+REPLICATE('3',LEN(T1.x)-LEN(REPLACE(T1.x,'3','')))
+REPLICATE('4',LEN(T1.x)-LEN(REPLACE(T1.x,'4','')))
+REPLICATE('5',LEN(T1.x)-LEN(REPLACE(T1.x,'5','')))
+REPLICATE('6',LEN(T1.x)-LEN(REPLACE(T1.x,'6','')))
+REPLICATE('7',LEN(T1.x)-LEN(REPLACE(T1.x,'7','')))
+REPLICATE('8',LEN(T1.x)-LEN(REPLACE(T1.x,'8','')))
+REPLICATE('9',LEN(T1.x)-LEN(REPLACE(T1.x,'9','')))
=
REPLICATE('0',LEN(T2.x)-LEN(REPLACE(T2.x,'0','')))
+REPLICATE('1',LEN(T2.x)-LEN(REPLACE(T2.x,'1','')))
+REPLICATE('2',LEN(T2.x)-LEN(REPLACE(T2.x,'2','')))
+REPLICATE('3',LEN(T2.x)-LEN(REPLACE(T2.x,'3','')))
+REPLICATE('4',LEN(T2.x)-LEN(REPLACE(T2.x,'4','')))
+REPLICATE('5',LEN(T2.x)-LEN(REPLACE(T2.x,'5','')))
+REPLICATE('6',LEN(T2.x)-LEN(REPLACE(T2.x,'6','')))
+REPLICATE('7',LEN(T2.x)-LEN(REPLACE(T2.x,'7','')))
+REPLICATE('8',LEN(T2.x)-LEN(REPLACE(T2.x,'8','')))
+REPLICATE('9',LEN(T2.x)-LEN(REPLACE(T2.x,'9','')))
AND T1.x<>T2.x
--
David Portas
SQL Server MVP
--