I need to replace a portion of a url in a column as a result of
changing servers. Is there a SELECT/REPLACE/UPDATE combination query
that can do this. The table has close to a thousand entries and would
be nice if a query can be set to do this. Tried the REPLACE example
in the BOOKS ONLINE but it creates syntax error, apparently because it
does not like the characters in the url and/or wildcards. I don't need
to replace the entire url, only the portion before ".com". Thanks in
anticipation of your help.
Pradip Sagdeo 3 8344
Pradip,
This statement:
select replace('http://www.technicalvideos.net','s.net','s14.net')
seems to work OK, so, perhaps you could give your exact update and the exact
error along with some sample data.
Best regards,
Chuck Conover www.TechnicalVideos.net
"Pradip Sagdeo" <pr*************@pfizer.com> wrote in message
news:8d*************************@posting.google.co m... I need to replace a portion of a url in a column as a result of changing servers. Is there a SELECT/REPLACE/UPDATE combination query that can do this. The table has close to a thousand entries and would be nice if a query can be set to do this. Tried the REPLACE example in the BOOKS ONLINE but it creates syntax error, apparently because it does not like the characters in the url and/or wildcards. I don't need to replace the entire url, only the portion before ".com". Thanks in anticipation of your help.
Pradip Sagdeo
Thanks. I will try again. Must have made a typing mistake.
Pradip
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Pradip Sagdeo (pr*************@pfizer.com) writes: I need to replace a portion of a url in a column as a result of changing servers. Is there a SELECT/REPLACE/UPDATE combination query that can do this. The table has close to a thousand entries and would be nice if a query can be set to do this. Tried the REPLACE example in the BOOKS ONLINE but it creates syntax error, apparently because it does not like the characters in the url and/or wildcards. I don't need to replace the entire url, only the portion before ".com". Thanks in anticipation of your help.
Unfortunately, the replace() function does not support wildcards, so
if you need to use that, you have to be creative. Or descend to use
some client code to handle it.
--
Erland Sommarskog, SQL Server MVP, so****@algonet.se
Books Online for SQL Server SP3 at http://www.microsoft.com/sql/techinf...2000/books.asp This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics
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