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table(name,age)

need to find top 2 that are distinct by age.
error check: if two names are the same go to next top age).

table(name,age)
A 17
A 17 <<error
B 14
C 16
D 16

got a table like that and
select distinct top 2 age from table, returns:

A 17
A 17


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Sent by 3 from yahoo subdomain of com
This is a spam protected message. Please answer with reference header.
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Jul 20 '05 #1
9 2815
How about this:

Select top 2 name, age
from temptable
group by name, age

"al********@yahoo.com" <u1********@spawnkill.ip-mobilphone.net> wrote in
message news:l.*********************@[63.127.215.130]...
table(name,age)

need to find top 2 that are distinct by age.
error check: if two names are the same go to next top age).

table(name,age)
A 17
A 17 <<error
B 14
C 16
D 16

got a table like that and
select distinct top 2 age from table, returns:

A 17
A 17


--
Sent by 3 from yahoo subdomain of com
This is a spam protected message. Please answer with reference header.
Posted via http://www.usenet-replayer.com

Jul 20 '05 #2
You can also do it as:

SELECT DISTINCT TOP 2 Name, Age FROM YourTable


"al********@yahoo.com" <u1********@spawnkill.ip-mobilphone.net> wrote in
message news:l.*********************@[63.127.215.130]...
table(name,age)

need to find top 2 that are distinct by age.
error check: if two names are the same go to next top age).

table(name,age)
A 17
A 17 <<error
B 14
C 16
D 16

got a table like that and
select distinct top 2 age from table, returns:

A 17
A 17


--
Sent by 3 from yahoo subdomain of com
This is a spam protected message. Please answer with reference header.
Posted via http://www.usenet-replayer.com

Jul 20 '05 #3
If you only want to eliminate duplicate records, you can use DISTINCT:

select distinct top 2 Name, Age

from YourTable

which returns:

A 17

B 14

But if you want to find two oldest people you have to return 3 records,
because B and C are the same age. In this case you can use WITH TIES:

select distinct top 2 with ties Name, Age

from YourTable

which returns:

A 17

C 16

D 16

Shervin
"al********@yahoo.com" <u1********@spawnkill.ip-mobilphone.net> wrote in
message news:l.*********************@[63.127.215.130]...
table(name,age)

need to find top 2 that are distinct by age.
error check: if two names are the same go to next top age).

table(name,age)
A 17
A 17 <<error
B 14
C 16
D 16

got a table like that and
select distinct top 2 age from table, returns:

A 17
A 17


--
Sent by 3 from yahoo subdomain of com
This is a spam protected message. Please answer with reference header.
Posted via http://www.usenet-replayer.com

Jul 20 '05 #4
The .."WITH TIES" statement you wrote wouldn't return the result you wrote.

In this case:

select distinct top 2 with ties Name, Age
from YourTable

WILL NOT RETURN

A 17
C 16
D 16

(also order by is required when you use WITH TIES )

I think WITH TIES return when (n+1), (n+2),..... rows are EXACTLY similar to
n(th) row (when you sepcify TOP n). Here in this case

2nd row ---> C 16
3rd row ---> D 16

aren't EXACTLY same.


"Shervin Shapourian" <Sh**********@hotmail.com> wrote in message
news:O4pkb.3855$i92.2803@clgrps13...
If you only want to eliminate duplicate records, you can use DISTINCT:

select distinct top 2 Name, Age

from YourTable

which returns:

A 17

B 14

But if you want to find two oldest people you have to return 3 records,
because B and C are the same age. In this case you can use WITH TIES:

select distinct top 2 with ties Name, Age

from YourTable

which returns:

A 17

C 16

D 16

Shervin
"al********@yahoo.com" <u1********@spawnkill.ip-mobilphone.net> wrote in
message news:l.*********************@[63.127.215.130]...
table(name,age)

need to find top 2 that are distinct by age.
error check: if two names are the same go to next top age).

table(name,age)
A 17
A 17 <<error
B 14
C 16
D 16

got a table like that and
select distinct top 2 age from table, returns:

A 17
A 17


--
Sent by 3 from yahoo subdomain of com
This is a spam protected message. Please answer with reference header.
Posted via http://www.usenet-replayer.com


Jul 20 '05 #5
Oops! Yes you are right, I forgot to add ORDER BY. Use this:

select distinct top 2 with ties Name, Age
from YourTable
order by Age

Now the result is:

A 17
C 16
D 16

In WITH TIES records need to have EXACTLY the same values for the fields
that are listed in ORDER BY clause, not all the fields. In this example C
and D have same value for Age.

Shervin

"I_AM_DON_AND_YOU?" <us**@domain.com> wrote in message
news:eX**************@tk2msftngp13.phx.gbl...
The .."WITH TIES" statement you wrote wouldn't return the result you wrote.
In this case:

select distinct top 2 with ties Name, Age
from YourTable

WILL NOT RETURN

A 17
C 16
D 16

(also order by is required when you use WITH TIES )

I think WITH TIES return when (n+1), (n+2),..... rows are EXACTLY similar to n(th) row (when you sepcify TOP n). Here in this case

2nd row ---> C 16
3rd row ---> D 16

aren't EXACTLY same.


"Shervin Shapourian" <Sh**********@hotmail.com> wrote in message
news:O4pkb.3855$i92.2803@clgrps13...
If you only want to eliminate duplicate records, you can use DISTINCT:

select distinct top 2 Name, Age

from YourTable

which returns:

A 17

B 14

But if you want to find two oldest people you have to return 3 records,
because B and C are the same age. In this case you can use WITH TIES:

select distinct top 2 with ties Name, Age

from YourTable

which returns:

A 17

C 16

D 16

Shervin
"al********@yahoo.com" <u1********@spawnkill.ip-mobilphone.net> wrote in
message news:l.*********************@[63.127.215.130]...
table(name,age)

need to find top 2 that are distinct by age.
error check: if two names are the same go to next top age).

table(name,age)
A 17
A 17 <<error
B 14
C 16
D 16

got a table like that and
select distinct top 2 age from table, returns:

A 17
A 17


--
Sent by 3 from yahoo subdomain of com
This is a spam protected message. Please answer with reference header.
Posted via http://www.usenet-replayer.com



Jul 20 '05 #6
Oh shoooooot! I really need to run my scripts before posting them!!!
The order by must be descending :-)

select distinct top 2 with ties Name, Age
from YourTable
order by Age desc

Sorry for that.

Shervin
"Shervin Shapourian" <Sh**********@hotmail.com> wrote in message
news:OHpkb.4150$i92.1865@clgrps13...
Oops! Yes you are right, I forgot to add ORDER BY. Use this:

select distinct top 2 with ties Name, Age
from YourTable
order by Age

Now the result is:

A 17
C 16
D 16

In WITH TIES records need to have EXACTLY the same values for the fields
that are listed in ORDER BY clause, not all the fields. In this example C
and D have same value for Age.

Shervin

"I_AM_DON_AND_YOU?" <us**@domain.com> wrote in message
news:eX**************@tk2msftngp13.phx.gbl...
The .."WITH TIES" statement you wrote wouldn't return the result you wrote.

In this case:

select distinct top 2 with ties Name, Age
from YourTable

WILL NOT RETURN

A 17
C 16
D 16

(also order by is required when you use WITH TIES )

I think WITH TIES return when (n+1), (n+2),..... rows are EXACTLY

similar to
n(th) row (when you sepcify TOP n). Here in this case

2nd row ---> C 16
3rd row ---> D 16

aren't EXACTLY same.


"Shervin Shapourian" <Sh**********@hotmail.com> wrote in message
news:O4pkb.3855$i92.2803@clgrps13...
If you only want to eliminate duplicate records, you can use DISTINCT:

select distinct top 2 Name, Age

from YourTable

which returns:

A 17

B 14

But if you want to find two oldest people you have to return 3 records, because B and C are the same age. In this case you can use WITH TIES:

select distinct top 2 with ties Name, Age

from YourTable

which returns:

A 17

C 16

D 16

Shervin
"al********@yahoo.com" <u1********@spawnkill.ip-mobilphone.net> wrote in message news:l.*********************@[63.127.215.130]...
> table(name,age)
>
> need to find top 2 that are distinct by age.
> error check: if two names are the same go to next top age).
>
> table(name,age)
> A 17
> A 17 <<error
> B 14
> C 16
> D 16
>
> got a table like that and
> select distinct top 2 age from table, returns:
>
> A 17
> A 17
>
>
>
>
>
>
> --
> Sent by 3 from yahoo subdomain of com
> This is a spam protected message. Please answer with reference header. > Posted via http://www.usenet-replayer.com



Jul 20 '05 #7
u r right.
"Shervin Shapourian" <Sh**********@hotmail.com> wrote in message
news:OHpkb.4150$i92.1865@clgrps13...
Oops! Yes you are right, I forgot to add ORDER BY. Use this:

select distinct top 2 with ties Name, Age
from YourTable
order by Age

Now the result is:

A 17
C 16
D 16

In WITH TIES records need to have EXACTLY the same values for the fields
that are listed in ORDER BY clause, not all the fields. In this example C
and D have same value for Age.

Shervin

"I_AM_DON_AND_YOU?" <us**@domain.com> wrote in message
news:eX**************@tk2msftngp13.phx.gbl...
The .."WITH TIES" statement you wrote wouldn't return the result you wrote.

In this case:

select distinct top 2 with ties Name, Age
from YourTable

WILL NOT RETURN

A 17
C 16
D 16

(also order by is required when you use WITH TIES )

I think WITH TIES return when (n+1), (n+2),..... rows are EXACTLY

similar to
n(th) row (when you sepcify TOP n). Here in this case

2nd row ---> C 16
3rd row ---> D 16

aren't EXACTLY same.


"Shervin Shapourian" <Sh**********@hotmail.com> wrote in message
news:O4pkb.3855$i92.2803@clgrps13...
If you only want to eliminate duplicate records, you can use DISTINCT:

select distinct top 2 Name, Age

from YourTable

which returns:

A 17

B 14

But if you want to find two oldest people you have to return 3 records, because B and C are the same age. In this case you can use WITH TIES:

select distinct top 2 with ties Name, Age

from YourTable

which returns:

A 17

C 16

D 16

Shervin
"al********@yahoo.com" <u1********@spawnkill.ip-mobilphone.net> wrote in message news:l.*********************@[63.127.215.130]...
> table(name,age)
>
> need to find top 2 that are distinct by age.
> error check: if two names are the same go to next top age).
>
> table(name,age)
> A 17
> A 17 <<error
> B 14
> C 16
> D 16
>
> got a table like that and
> select distinct top 2 age from table, returns:
>
> A 17
> A 17
>
>
>
>
>
>
> --
> Sent by 3 from yahoo subdomain of com
> This is a spam protected message. Please answer with reference header. > Posted via http://www.usenet-replayer.com



Jul 20 '05 #8
Alexqa,

Try query in following example

--sample table / records

create table tb (name char(1), age int)
insert into tb
select 'A', 17 union all
select 'A', 17 union all
select 'B', 14 union all
select 'C', 16 union all
select 'D', 16

--query
select name,age from
(select name,age,
(select count(distinct age) from tb b
where a.age <= b.age) rank
from tb a) X
where rank <= 2
--
-Vishal
Jul 20 '05 #9
Your query gives the following output:

name age
---- -----------
A 17
A 17
C 16
D 16

But this is not what Alexqa want.
"Vishal Parkar" <_v*******@yahoo.co.in> wrote in message
news:%2****************@TK2MSFTNGP10.phx.gbl...
Alexqa,

Try query in following example

--sample table / records

create table tb (name char(1), age int)
insert into tb
select 'A', 17 union all
select 'A', 17 union all
select 'B', 14 union all
select 'C', 16 union all
select 'D', 16

--query
select name,age from
(select name,age,
(select count(distinct age) from tb b
where a.age <= b.age) rank
from tb a) X
where rank <= 2
--
-Vishal

Jul 20 '05 #10

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