show number of values as % of total records..?

[Otto]

Hi
I'm migrating from Access til MySQL.
Works fine so far - but one thing is nearly killing me:

I got the count of total records in a variabel - (antalRecords)
I got the count for the Field Q1 where the value value is = 'nej'
Now I just need to calculate how many % of my records have the value 'nej'
I access this worked very fine - but with MySQL ( and ASP) I just cant get
it right!!! I go crazy ....

My code looks like this :

strSQL="SELECT COUNT(Q1) AS Q1_nej FROM Tbl_evaluering " &_
"WHERE Q1 = 'NEJ' "
set RS = connection.Execute(strSQL)
antal_nej = RS("Q1_nej")
procent_nej = formatNumber((antal_nej),2)/antalrecords * 100

Hope ...praying for help ...Please ;-)
best wishes -Otto - Copenhagen

[Erland Sommarskog]

Otto (ot********@tele.dk) writes:

I'm migrating from Access til MySQL.

Over MS SQL Server, or are you in the wrong newsgroup?

I got the count of total records in a variabel - (antalRecords)
I got the count for the Field Q1 where the value value is = 'nej'
Now I just need to calculate how many % of my records have the value 'nej'
I access this worked very fine - but with MySQL ( and ASP) I just cant get
it right!!! I go crazy ....

SELECT cast(100.0 * SUM (CASE Q1 WHEN 'nej' THEN 1 ELSE 0 END) / COUNT(*)
as decimal(5,2)
FROM tbl

This works on my SQL Server. I cannot promise that it works on YourSQL,
though. but at least it's ANSI.


--
Erland Sommarskog, SQL Server MVP, es****@sommarskog.se

Books Online for SQL Server 2005 at
http://www.microsoft.com/technet/pro...ads/books.mspx
Books Online for SQL Server 2000 at
http://www.microsoft.com/sql/prodinf...ons/books.mspx

[Otto]

"Erland Sommarskog" <es****@sommarskog.seskrev i en meddelelse >

SELECT cast(100.0 * SUM (CASE Q1 WHEN 'nej' THEN 1 ELSE 0 END) / COUNT(*)
as decimal(5,2)) FROM tbl

Hi erland - thanks for your response- the code works in the way that I dont
get an error - but I dont really know how to get the number of records (in
Field Q1) and the % of these who have the value 'nej' out from this
code..:-(

You can see my Access version of webpage on
http://www.gymnasiereform.dk/svar_q12.asp
here it works fien - but I cant make it work with MY SQL which I'm trying t
migrate to.
Best wishe s- Otto

[Erland Sommarskog]

Otto (ot********@tele.dk) writes:

"Erland Sommarskog" <es****@sommarskog.seskrev i en meddelelse >

SELECT cast(100.0 * SUM (CASE Q1 WHEN 'nej' THEN 1 ELSE 0 END) / COUNT(*)
as decimal(5,2)) FROM tbl

Hi erland - thanks for your response- the code works in the way that I
dont get an error - but I dont really know how to get the number of
records (in Field Q1) and the % of these who have the value 'nej' out
from this code..:-(

That code gives you the percentage who said no. COUNT(*) gives you the
the total number of rows.

SELECT COUNT(*) AS total
cast(100.0 * SUM (CASE Q1 WHEN 'nej' THEN 1 ELSE 0 END) /
COUNT(*) as decimal(5,2)) AS percent_that_said_no
FROM tbl

If Q1 can be NULL, and you only want to count non-NULL rows, replace
COUNT(*) with COUNT(Q1).
--
Erland Sommarskog, SQL Server MVP, es****@sommarskog.se

Books Online for SQL Server 2005 at
http://www.microsoft.com/technet/pro...ads/books.mspx
Books Online for SQL Server 2000 at
http://www.microsoft.com/sql/prodinf...ons/books.mspx