Hello everybody,
-------------------------------------------------
CREATE TABLE [T1] (
[IDX] [numeric](18, 0) IDENTITY (1, 1) NOT NULL ,
[DateEvt] [datetime] NOT NULL,
[Value] [varchar] (10) NOT NULL ,
[DataX] [varchar] (10) NULL ,
CONSTRAINT [PK_T1] PRIMARY KEY CLUSTERED
(
[IDX]
) WITH FILLFACTOR = 90 ON [PRIMARY]
) ON [PRIMARY]
GO
insert into T1 (DateEvt,Value, DataX) values('2004.10.10 10:00:00',
'0000000001', 'AAAAAAAAAA')
insert into T1 (DateEvt,Value, DataX) values('2004.10.10 10:00:01',
'0000000002', 'AAAAAAAAAA')
insert into T1 (DateEvt,Value, DataX) values('2004.10.10 10:00:02',
'0000000003', 'AAAAAAAAAA')
insert into T1 (DateEvt,Value, DataX) values('2004.10.10 10:01:00',
'0000000001', 'BBBBBBBBBB')
insert into T1 (DateEvt,Value, DataX) values('2004.10.10 10:02:00',
'0000000001', 'CCCCCCCCCC')
insert into T1 (DateEvt,Value, DataX) values('2004.10.10 10:03:00',
'0000000001', 'DDDDDDDDDD')
GO
-------------------------------------------------
and the question is:
In which fastes and best for the preformance way, get the last IDX of
specified Value.
I could do this like this:
-------------------------------------------------
declare @nIDX numeric
declare @sValue varchar(10)
select top 1 @nIDX = IDX from T1
where Value = @sValue
order by DateEVT desc
-------------------------------------------------
But I know, this is not fast (even if I have index on DateEVT field),
and I'm quite sure, that there is better way to get this IDX.
Anyway, this table can be big (like 20 milions records).
I could take the max of IDX, but is it a sure way?
Any help? Thanks in advance
Matik 1 2414
> declare @nIDX numeric declare @sValue varchar(10)
select top 1 @nIDX = IDX from T1 where Value = @sValue order by DateEVT desc
To optimize this query, consider creating a non-clustered index on Value and
using MAX. This index will cover the query becuase the clustered index
value (IDX) is also stored in the non-clustered index.
DECLARE @nIDX numeric
DECLARE @sValue varchar(10)
SELECT @nIDX = MAX(IDX)
FROM T1
WHERE Value = @sValue
Also, if you are using SQL 2000, consider bigint instead of numeric(18, 0).
This will save a little space.
--
Hope this helps.
Dan Guzman
SQL Server MVP
"Matik" <ma****@sauron.xo.pl> wrote in message
news:11*********************@f14g2000cwb.googlegro ups.com... Hello everybody,
-------------------------------------------------
CREATE TABLE [T1] ( [IDX] [numeric](18, 0) IDENTITY (1, 1) NOT NULL , [DateEvt] [datetime] NOT NULL, [Value] [varchar] (10) NOT NULL , [DataX] [varchar] (10) NULL , CONSTRAINT [PK_T1] PRIMARY KEY CLUSTERED ( [IDX] ) WITH FILLFACTOR = 90 ON [PRIMARY] ) ON [PRIMARY] GO
insert into T1 (DateEvt,Value, DataX) values('2004.10.10 10:00:00', '0000000001', 'AAAAAAAAAA') insert into T1 (DateEvt,Value, DataX) values('2004.10.10 10:00:01', '0000000002', 'AAAAAAAAAA') insert into T1 (DateEvt,Value, DataX) values('2004.10.10 10:00:02', '0000000003', 'AAAAAAAAAA') insert into T1 (DateEvt,Value, DataX) values('2004.10.10 10:01:00', '0000000001', 'BBBBBBBBBB') insert into T1 (DateEvt,Value, DataX) values('2004.10.10 10:02:00', '0000000001', 'CCCCCCCCCC') insert into T1 (DateEvt,Value, DataX) values('2004.10.10 10:03:00', '0000000001', 'DDDDDDDDDD') GO
-------------------------------------------------
and the question is: In which fastes and best for the preformance way, get the last IDX of specified Value.
I could do this like this:
------------------------------------------------- declare @nIDX numeric declare @sValue varchar(10)
select top 1 @nIDX = IDX from T1 where Value = @sValue order by DateEVT desc -------------------------------------------------
But I know, this is not fast (even if I have index on DateEVT field), and I'm quite sure, that there is better way to get this IDX. Anyway, this table can be big (like 20 milions records).
I could take the max of IDX, but is it a sure way? Any help? Thanks in advance
Matik This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics
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