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how/what should be the query for this result

I have 1 table "Progress"

P_no b_no status build_date
----------------------------------------------------------------
25 1 First_slab 2006/4/5
25 1 second slab 2006/5/6
25 2 first slab 2006/1/2
25 2 third slab 2006/2/3

o/p should be as
Pno,bno, status, max(build_date)

sample o/p can be as below
25 1 second slab 2006/5/6
25 2 third slab 2006/2/3

Thanks in Advance.

Jun 28 '06 #1
4 1005
(ch*********@gm ail.com) writes:
I have 1 table "Progress"

P_no b_no status build_date
----------------------------------------------------------------
25 1 First_slab 2006/4/5
25 1 second slab 2006/5/6
25 2 first slab 2006/1/2
25 2 third slab 2006/2/3

o/p should be as
Pno,bno, status, max(build_date)

sample o/p can be as below
25 1 second slab 2006/5/6
25 2 third slab 2006/2/3


SELECT a.pno, a.bno, a.status, a.build_date
FROM progress a
JOIN (SELECT pno, bno, build_date = MAX(build_date)
FROM progress
GROUP BY BY pno, bno) AS b ON a.pno = b.pno
AND a.bno = p.bno
AND a.build_date = b.build_date
--
Erland Sommarskog, SQL Server MVP, es****@sommarsk og.se

Books Online for SQL Server 2005 at
http://www.microsoft.com/technet/pro...ads/books.mspx
Books Online for SQL Server 2000 at
http://www.microsoft.com/sql/prodinf...ons/books.mspx
Jun 28 '06 #2
Modifying Erland's query a little bit, on SQL 2005 only (untested):

SELECT t.pno, t.bno, t.status, t.build_date
FROM (
SELECT a.pno, a.bno, a.status, a.build_date,
row_number() over(partition by pno, bno order by build_date desc) rn
from
progress a
) t
where rn = 1

Jun 28 '06 #3
Thanks a lot to both of you.. it worked

Jun 29 '06 #4
Thanks a lot to both of you.. it worked

~Madhav

Jun 29 '06 #5

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