Jython output help (beginner question)

[od11kd]

Hey guys!

So I am trying to do a program, and for the most part I have it down except for 1 part of it.

Basically, I want my function to continue to prompt a user to enter an integer number between 1 and 100 inclusive, until the user enters a invalid integer.

I have the program here:

def assign2PartB(): 
x = 0 
while x <= 100: 
x = input ("Enter a number between 1 and 100 to continue: ") 
printNow ("The number you entered was: " + str(x)) 
if x <=0: 
printNow ("The number you entered (" + str(x) + ") was not between 1 and 100. Try again, please!") 

And the output is as followed:
>>> assign2PartB()
Enter a number between 1 and 100 to continue: 19
The number you entered was: 19
Enter a number between 1 and 100 to continue: 99
The number you entered was: 99
Enter a number between 1 and 100 to continue: 0
The number you entered was: 0
The number you entered (0) was not between 1 and 100. Try again, please!

My question is, when I enter "0" how do I get my program to not show "The number you entered was: 0" but only show "The number you entered (0) was not between 1 and 100. Try again, please!"

Thanks so much in advance guys, I appreciate your help!

[bvdet]

You need to put "printNow ("The number you entered was: " + str(x))" in an if/elif/else block. Example:

def assign2PartB(): 
    while True: 
        x = input("Enter a number between 1 and 100 to continue:") 
        if x < 1: 
            print "The number you entered (%s) was not between 1 and 100. Try again, please!" % (x)
        elif x > 100:
            print "The number you entered was: %s" % (x)
            print "Exiting!"
            return
        else:
            print "The number you entered was: %s" % (x)
 
assign2PartB()
 

[od11kd]

Thank you so much! Appreciate it