How to return matrix index

[AnneTanne]

I have a dictionary which is made pretty as a matrix:

Dictionary:
{'1': {'3': 0, '2': 1, '5': 1, '4': 0, '6': 29},
'3': {'1': 0, '2': 0, '5': 0, '4': 1, '6': 1},
'2': {'1': 13, '3': 1, '5': 21, '4': 0, '6': 0},
'5': {'1': 39, '3': 0, '2': 1, '4': 0, '6': 14},
'4': {'1': 1, '3': 1, '2': 17, '5': 2, '6': 0},
'6': {'1': 0, '3': 43, '2': 0, '5': 0, '4': 1}}

The information as a matrix:

    1    2    3    4    5    6    
1    -    1    0    0    1    29   
2    13   -    1    0    21   0    
3    0    0    -    1    0    1    
4    1    17   1    -    2    0    
5    39   1    0    0    -    14   
6    0    0    43   1    0    -   

From the matrix i can see that the column number 4 has the lowest numbers.
I want to write a function findFristFread(overlaps) that takes the dictionary as argument and returns '4' because that is the column with lowest numbers.

How do i get the function to 'understand' that i want the lowest numbers?

Can anybody get me started?

[ADezii]

You can start by passing to your Function a 2-Dimensional Array containing the Elements of the Matrix.

[bvdet]

You can create a 2D array from the dictionary like this:

m = [[0 for _ in range(6)] for _ in range(6)]
for key in dd:
    for subkey in dd[key]:
        m[int(key)-1][int(subkey)-1] = dd[key][subkey]

It looks like this:

>>> m
[[0, 1, 0, 0, 1, 29], [13, 0, 1, 0, 21, 0], [0, 0, 0, 1, 0, 1], [1, 17, 1, 0, 2, 0], [39, 1, 0, 0, 0, 14], [0, 0, 43, 1, 0, 0]]
>>>

From there, you can sum each column to determine which one has the lowest sum.