Syntax error in python 2.3.4

[akilasekaran]

i am new to the python codes.. i just started out hello world.. i ended up getting an "invalid syntax" error... but i was able to run a TCP server program from the very same version of python which is python 2.3.4

Iam perplexed !!

[cemyildiz]

Can you share your code here?

[bvdet]

It could be something as simple as missing quotes.

>>> print hello world
Traceback (  File "<interactive input>", line 1
    print hello world
                    ^
SyntaxError: invalid syntax
>>> print "hello world"
hello world
>>> 

[akilasekaran]

D:\Python23>python hii.py
File "hii.py", line 1
Python 2.3.3 (#51, Dec 18 2003, 20:22:39) [MSC v.1200 32 bit (Intel)] on win
32
^
SyntaxError: invalid syntax


I got this when i tried to run the program from cmd line.

[cemyildiz]

try to put quatos after print inside of hii.py:

print "hello world"

[akilasekaran]

i still get the same error :-(

[bvdet]

Please post the code you are using.

[akilasekaran]

>>> h="hello world"
>>> print h
hello world

[bvdet]

Remove the ">" characters and leading spaces. Your file should contain only:

h="hello world"
print h

[akilasekaran]

not only this program , but in other basic programs also i get the same syntax error.. but no error comes in a this one.. i wonder how..

#Python 2.7.2 (default, Jun 12 2011, 15:08:59) [MSC v.1500 32 bit (Intel)] on win32
#Type "copyright", "credits" or "license()" for more information.
#import socket module
from socket import *    
serverSocket = socket(AF_INET, SOCK_STREAM)
#Prepare a sever socket
host=gethostbyname(gethostname())
print host
port=1234
serverSocket.bind((host,port))
while True:
  print 'Ready to serve...'
  serverSocket.listen(1)
  connectionSocket,addr=serverSocket.accept()
  try:
    message = connectionSocket.recv(4096)   
    filename = message.split()[1]  
    f = open(filename[1:])  
        outputdata = f.read()
    #Send one HTTP header line into socket
    #Fill in start
        connectionSocket.send("200 OK") 
    #Fill in end  
    #Send the content of the requested file to the client
        for i in range(0, len(outputdata)):  
           connectionSocket.send(outputdata[i])
        connectionSocket.close()
  except IOError:
     #Send response message for file not found
     #Fill in start
     connectionSocket.send("404 file not found")
     #Fill in end
     #Close client socket
     #Fill in start
     connectionSocket.close()
     #Fill in end  
serverSocket.close()

[akilasekaran]

when i type in the python GUI i am unable to remove the >>>

may b am troublin u a lot.. :-D

[bvdet]

">>> " belongs in the interactive window but not in the file being executed.

It's strange that the code you posted works. It has several indentation errors.

[akilasekaran]

actually the hello world program worked successfull when i did it without >>> .Thanks a lot.. but now another problem..

This program i wrote for server.

from socket import *
s = socket(AF_INET,SOCK_STREAM) 
h=gethostbyname(gethostname())
print'host is ',h
s.bind((h,9000))
s.listen(1)
while 1:
    try:
    client, address = s.accept()
    print'connection from',address
    data = client.recv(1024)
    if not data:break 
        client.send(data) 
    client.close()
 
    except IOError:
        print'IOError is there !'
        client.close()

i get this following error :

D:\Python23>python serv.py
File "serv.py", line 10
print"connection from",address
^
SyntaxError: invalid syntax

[bvdet]

Please use code tags when posting code. See "Need help with Bytes? (FAQ)"

[bvdet]

Your code is not indented properly. The interpreter expects an indentation after a try statement.

[akilasekaran]

oh sorry.. i am new to the forum.. ll use code tag :)

[akilasekaran]

i tried using indentation.. but the error comes in the print line following the client accept code. i.e 2nd line from try. :(

[bvdet]

No problem. Code formatting does not display properly unless code tags are used. You can easily add them by selecting the text you want to wrap in tags and picking the "#" button at the top of the reply widget.

[akilasekaran]

i rectified the error myself :) thanku sooo much.. :)

[akilasekaran]

the error was all about indentation and proper port mentioning :-)

[bvdet]

I suspect it is still an indentation problem. Your indentation should look like this:

from socket import *
s = socket(AF_INET,SOCK_STREAM) 
h=gethostbyname(gethostname())
print 'host is ',h
s.bind((h,9000))
s.listen(1)
while 1:
    try:
        client, address = s.accept()
        print 'connection from', address
        data = client.recv(1024)
        if not data:
            break 
        client.send(data) 
        client.close()
 
    except IOError:
        print'IOError is there !'
        client.close()

Note that the number of spaces representing an indentation is a matter of preference but should be consistent. I prefer 4 spaces. Also note it is bad practice to mix spaces and tabs.

[akilasekaran]

oh okays :) got it :)