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# How to get data between two values in a set?

 P: 4 just a quick question here. i need to write a function written in python that receives a list of numbers and two values and returns the number of items between those two values. for example if the list is [1,2,3,4] and the two values are 2 and 4 then the function would return 3. all i have so far is the very beginning def main(): listdata = raw_input("please enter a string of numbers") surroundnum = raw_input("enter two values in the list") May 17 '11 #1
6 Replies

 Expert 100+ P: 621 A hint: Expand|Select|Wrap|Line Numbers test_list = [1, 2, 4, 5, 7, 10] for location in range(len(test_list)):      print location, test_list[location]  May 17 '11 #2

 P: 4 im not really sure how that helps.... i mean i dont understand how that gets the number in between two given numbers in the list. all i get when i use that code is sets of numbers from the list divided into pairs May 18 '11 #3

 100+ P: 332 It is a hint that was given to you Jake :) But I have a question for you. What do you mean by between. There are two scenarios. 1. Give me all numbers that are greater than 2 and smaller than 4 in the given list. Or 2. Give me all numbers that are physically located between numbers 2 and 4 in the given list. Example: [6, 2, 5, 4] would return 5. Given scenario 2, that would be why dwblas is refering to location in the list... May 18 '11 #4

 P: 4 i meant the physical location im just not sure how the hint applies. i mean i get the list,and the two numbers. i just dont know how to get the two to interact and then pull the number between them May 18 '11 #5

 P: 4 and i didnt mean to sound ungrateful any help i get at this point is greatly appreciated May 18 '11 #6

 100+ P: 332 Once you found the locations, you basically have a lower and upper limit. You should read about slicing a list as well as the index property of a list. Some more hints: Expand|Select|Wrap|Line Numbers test_list=[6, 2, 5, 4] x=test_list.index("2") y=test_list.index("4") z=test_list[x:y] #or probably x+1 and y-1...  may need some validation   May 19 '11 #7