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How to use Environment Variables to set location of file in Python?

P: 16
Hello there,
I want to create a txt in system32, but I want to do that using an environment variable.
I want to use an environment variable instead of this:
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  1. file = open("C:\\Windows\\system32\\asdfasdf.txt","w")
Because many pc's don't have their %SYSTEMDRIVE% in C:

So, which would be the correct form?
Thank you
Dec 6 '10 #1
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3 Replies

Expert Mod 2.5K+
P: 2,851
You can determine the value of SYSTEMDRIVE from os.environ['SYSTEMDRIVE'].
Dec 6 '10 #2

P: 16
And how it would be?
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  1. import os
  2. file = open("os.environ['SYSTEMDRIVE']\\Windows\\system32\\asdfasdf.txt","w")
Dec 6 '10 #3

Expert Mod 2.5K+
P: 2,851
I would use:
os.path.join(os.environ['SYSTEMDRIVE'], "Windows/system32/asdfasdf.txt")
Dec 7 '10 #4

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