[Python] Read .txt file and analayze

[thaking]

Hello all;

I'm working huffman coding of any .txt file, so first I need to analyse this text file. I need to read it, then analyse.
I need "exit" like table:
****************************
letter frequency(how many times same latter repeated) Huffman code(this will come later)

************************

I started with:

f = open('test.txt', 'r')    #open test.tx
    for lines in f:
        print lines          #to ensure if all work...
 

Can anyone help me?

[Sean Pedersen]

def countLetters(line, letter):
    ret = 0
    for character in line:
        if character == letter: ret += 1
    return ret
 
for line in open("file.txt"):
    line = line.strip()
    print line
    print "Has", countLetters(line, "a"), "of letter a."
    print "Has", countLetters(line, "e"), "of letter e."
    print "Has", countLetters(line, "i"), "of letter i."
    print "Has", countLetters(line, "o"), "of letter o."
    print "Has", countLetters(line, "u"), "of letter u."
    print "Has", countLetters(line, "y"), "of letter y."
    print

[twohot]

Modifying Sean's Code:

#!/bin/python3
 
def countLetters(line, letter):
   ret = 0
   for character in line:
      if character == letter: ret += 1
   return ret
 
alphabet = 'abcdefghijklmnopqrstuvwxyz'
#you can automate this using ascii codes too
 
for line in open("file.txt",'r'):
   line = line.strip() #remove trailing spaces
   print (line)
   for letter in alphabet:
      print ('Has {0} of letter {1}'.\
      format(str(countLetters(line,letter)),letter))

output:
gbfchjwshfcjkwhndfnxh;iquw;qemiziqmeuzngyegbfyewgy bqgzeqzydglndhlqhd;jkjnenjcejnrcjercbvvbdbggngnjmm nmsnvsdmsnfsfcsf>mNmvbmsdbfluaheregnctfbaxzmasqojm wqi;htrugttgp
Has 3 of letter a
Has 9 of letter b
Has 7 of letter c
Has 7 of letter d
Has 10 of letter e
Has 9 of letter f
Has 12 of letter g
Has 8 of letter h
Has 4 of letter i
Has 9 of letter j
Has 2 of letter k
Has 3 of letter l
Has 11 of letter m
Has 13 of letter n
Has 1 of letter o
Has 1 of letter p
Has 8 of letter q
Has 4 of letter r
Has 8 of letter s
Has 4 of letter t
Has 4 of letter u
Has 4 of letter v
Has 5 of letter w
Has 2 of letter x
Has 4 of letter y
Has 5 of letter z

[Michael Colon]

#-------------------------------------------------#
# Set Variables                                   #
#-------------------------------------------------#
 
input = open("file.txt")
whitelist = ('a','b','c','d','e','f','g') # whitelist of letters
letters = {}
 
#-------------------------------------------------#
#  Functions                                      #
#-------------------------------------------------#
 
def count_letter(c):
  if c in letters:
    letters[c] += 1  # if letter in letters add one
  else:
    letters[c] = 1   # if letter not in letters set add letter to dictionary object
 
 
def print_letters(letters):
 
  for k,v in letters.items():
    if k in whitelist:
      print "Has %s of letter %s" % (v,k) # print out count for each letter
 
 
#-------------------------------------------------#
#  Run code                                       #
#-------------------------------------------------#
 
 
for line in input:          # for each line in input file
  for letter in line:       # for each letter in line
    count_letter(letter)    # tally a count of each letter
 
print_letters(letters)
 

Here I use a more pythonic syntax, which means less lines of code. If you count everything and whitelist the characters your concerned with then your code can be easily modified in the future.

Hope this helps!

[twohot]

Very neat Michael