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How to divide file into separate lists?

P: 2
How can I divide a file with emails divided with headers like this:

Sent: 7th aprill 2099

email text

...into separate lists in one big list containing the email and the header?

the point is that im supposed to check each email for spam words and give points for each spam word... and then put the spam emails from the email file into a spam email list and file.. and all of the normal emails from the email file into a file as well as list for normal emails...


i attached what i ve done so far. You can ignore the ## comments.. it's just stuff i've done and decided to ignore
Attached Files
File Type: txt spam.txt (2.9 KB, 359 views)
Nov 24 '10 #1
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2 Replies

Expert 100+
P: 624
Append the records to a list. Everytime the "From:" record is found, send the list to a function to process the previous group any way you want, and re-declare the list as empty. Pseudo-code:
Expand|Select|Wrap|Line Numbers
  1. def process_group(list_in, normal_fp, spammer_fp):
  2.     if len(list_in):      ## Why do we want this line?
  3.         spammer = False
  4.         print list_in
  5.         if spam:
  6.             spammer = True
  8.         ## all records processed
  9.         if spammer:
  10.             ## write records to spammer file
  11.         else:
  12.             ## write records to normal file
  14. normal_fp = open("normal.txt", "w")
  15. spammer_fp = open("spammer.txt", "w")
  17. group_list = []
  18. for rec in fname:
  19.     if rec.strip().startswith("From:"):
  20.         process_group(group_list, normal_fp, spammer_fp)
  21.         group_list = []
  22.     group_list.append(rec)
  24. process_group(group_list, normal_fp, spammer_fp)     ## process final group 
Nov 24 '10 #2

P: 2
thank u very much 4 replying
I dont get one thing though. where does the startswith() function come from ? in line 19
and what does the process_group() function do ?
I'm sorry if i seem a bit lost im new to this
Nov 24 '10 #3

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