How to divide file into separate lists?

[Amanda Ahl]

How can I divide a file with emails divided with headers like this:

From: [e-mail]
Sent: 7th aprill 2099
To: [e-mail]

email text

...into separate lists in one big list containing the email and the header?

the point is that im supposed to check each email for spam words and give points for each spam word... and then put the spam emails from the email file into a spam email list and file.. and all of the normal emails from the email file into a file as well as list for normal emails...

HELP ANYONE ?? :D :D :D

i attached what i ve done so far. You can ignore the ## comments.. it's just stuff i've done and decided to ignore

[dwblas]

Append the records to a list. Everytime the "From:" record is found, send the list to a function to process the previous group any way you want, and re-declare the list as empty. Pseudo-code:

def process_group(list_in, normal_fp, spammer_fp):
    if len(list_in):      ## Why do we want this line?
        spammer = False
        print list_in
        if spam:
            spammer = True
 
        ## all records processed
        if spammer:
            ## write records to spammer file
        else:
            ## write records to normal file
 
normal_fp = open("normal.txt", "w")
spammer_fp = open("spammer.txt", "w")
 
group_list = []
for rec in fname:
    if rec.strip().startswith("From:"):
        process_group(group_list, normal_fp, spammer_fp)
        group_list = []
    group_list.append(rec)
 
process_group(group_list, normal_fp, spammer_fp)     ## process final group 

[Amanda Ahl]

thank u very much 4 replying
I dont get one thing though. where does the startswith() function come from ? in line 19
and what does the process_group() function do ?
I'm sorry if i seem a bit lost im new to this