Syntax error on filename

[joydeepdg]

>>> python WavHeader.py hello.wav
File "<stdin>", line 1
python WavHeader.py hello.wav
^(this arrow mark is actually below 'r' of WavHeader.py)
SyntaxError : invalid syntax

[bvdet]

I tested your script from the Command Prompt without a hitch. At the python prompt, use the import statement. This worked for me:

>>> import WaveHeader
>>> WaveHeader.PrintWavHeader("sample.wav")
Subchunks Found:
fmt ,  data,
 
Data Chunk located at offset [36] of data length [15022108] bytes
BitsPerSample:  16
NumChannels:  2
ChunkSize:  15022144
Format:  WAVE
Filename:  sample.wav
ByteRate:  176400
Subchunk1Size:  16
AudioFormat:  1
BlockAlign:  4
SampleRate:  44100
>>> 

[joydeepdg]

i'm still facing the same problem. i'm new to this python thing. is thr something wrong with some other configuration? as in computer's? or what?
and in the IDLE when i'm doing with the import..
this is what i get:
>>> import WavHeader
Traceback (most recent call last):
File "<pyshell#0>", line 1, in <module>
import WavHeader
ImportError: No module named WavHeader

>>> WavHeader.PrintWavHeader("hello.wav")
Traceback (most recent call last):
File "<pyshell#1>", line 1, in <module>
WavHeader.PrintWavHeader("hello.wav")
NameError: name 'WavHeader' is not defined


reply from your end is eagerly awaited.

[bvdet]

In IDLE, import the os module and set the current working directory to the directory containing WaveHeader.py. If the WAV file is in another directory, use the full path in the argument.

import os
os.chdir("XX:/directory_name")

[bvdet]

An alternative: import sys and append the path to the directory to sys.path.

import sys
sys.path.append("XX:/directory_name")

You may have to create a file named "__init__.py" and place it in the same directory as WaveHeader.py. It need not have anything in it.

[joydeepdg]

I am facing some wierd problems here.I deleted the first few lines of the code from the IDLE including the ">>>" sign till so that the first line read
"# WavHeader.py
#Extract .....
"
Now I start the python command line and at the >>> promt I give the following command:

>>> import os
>>> os.system("python WavHeader.py hello.wav")
Now the earlier error,i.e. the syntax error disappears but a new error appears as:

File "WavHeader.py", line 17
print "%s:" % (key), structHeaderFields[key]

Now I really dont know why I am having all these errors and amreally feeling low because I was expecting the code to run without a hitch as you did.But still I am stuck.
Please help me out with this one.
Awaiting your response.

[bvdet]

Open the file in Idle. This sets the current working directory to the location of the module. At the Python prompt of the shell window:

>>> import WaveHeader
>>> WaveHeader.PrintWavHeader("sample.wav")
Subchunks Found: 
fmt ,  data,  
 
Data Chunk located at offset [36] of data length [15022108] bytes
BitsPerSample:  16
NumChannels:  2
ChunkSize:  15022144
Format:  WAVE
Filename:  sample.wav
ByteRate:  176400
Subchunk1Size:  16
AudioFormat:  1
BlockAlign:  4
SampleRate:  44100
>>> 

Keep trying, you are bound to hit it eventually. :)

[joydeepdg]

i do as above and i get the following:

>>> import WavHeader
Traceback (most recent call last):
File "<pyshell#0>", line 1, in <module>
import WavHeader
File "E:\Python31\WavHeader.py", line 17
print "%s: " % (key), structHeaderFields[key]
^
SyntaxError: invalid syntax

[joydeepdg]

^ is below the second "

[bvdet]

What version of Python are you using? If it's 3.0 or 3.1, print is a function whereas it was a statement in 2.X.

[joydeepdg]

it's Python 3.1

help me out, bro.

[bvdet]

@joydeepdg
You can find the proper usage for the built-in function print() here.

[joydeepdg]

which version of python are u using?

[bvdet]

I am using 2.3 because that is the version embedded in the software I use for my work. I have 2.6 installed when I want to try something new.

[Domi]

I'm running into this exact same error and I can't for the life of me figure out what is going wrong. I'm doing the Python tutorials made by google

Using the following code

#!/usr/bin/python -tt
# Copyright 2010 Google Inc.
# Licensed under the Apache License, Version 2.0
# http://www.apache.org/licenses/LICENSE-2.0
 
# Google's Python Class
# http://code.google.com/edu/languages/google-python-class/
 
"""A tiny Python program to check that Python is working.
Try running this program from the command line like this:
  python hello.py
  python hello.py Alice
That should print:
  Hello World -or- Hello Alice
Try changing the 'Hello' to 'Howdy' and run again.
Once you have that working, you're ready for class -- you can edit
and run Python code; now you just need to learn Python!
"""
 
import sys
 
# Define a main() function that prints a little greeting.
def main():
  # Get the name from the command line, using 'World' as a fallback.
  if len(sys.argv) >= 2:
    name = sys.argv[1]
  else:
    name = 'World'
  print 'Hello', name
 
# This is the standard boilerplate that calls the main() function.
if __name__ == '__main__':
  main()

The most irritating thing is, using the shell, I can open the module and run it (f5) and it prints Hello World, but every time I navigate over to the directory and try running it through the command line interface (import hello, python hello.py) it keeps giving me this error. Sorry to the OP about pseudo hijacking your thread here :P but maybe this might shed more light on the issue. I'm using python 2.6

[Domi]

On further inspection, it doesn't seem to be noticing the command "python". I get the exact same error when I do something random like:

>>>asdfranom hello.py

when I do >>>python it says that it is not defined. :S Is this supposed to happen?

[bvdet]

When you are at the python command prompt, import the module then execute the function as in:

>>> import math
>>> math.sqrt(9376)
96.829747495281637
>>> 

Modules define a variable, __name__, that contains the module name. When you run the opened file in Idle (F5), it becomes the top-level module of the interpreter, and __name__ is assigned to "__main__". The code:

if __name__ == '__main__':
    main()

therefore executes the function main().

Try this - assuming your module is named "modulename.py":

import modulename
modulename.main()