parse log file to obtain IP's with failed attempts

[DjPal]

I am trying to parse through a log file to obtain the IP addresses with >5 failed
login attempts, firstly I'm trying to get the IP addresses but there seems to be something wrong with the regular expression I think. would be good to export the addresses to another text file, does anyone have any ideas where to go from here?

Thank you.

 
#!/usr/local/bin/python
file = open(location) 
for line in file: 
 
                ips = ("(\d{1,3}\.){3}\d{1,3}")  ## get IPs
                print 'the ip addresses are ', ips
 
 

[bvdet]

Apparently you do not understand re. You begin by importing the module.

import re

You created a pattern. Now you need use that pattern in a statement involving a function defined in re. This can get pretty complicated and is beyond the scope of my abilities, so I will suggest that you go through this excellent tutorial.

I might go about it like this:

import re
s = r"(%s)" % ("\.".join(['(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)']*4))
patt = re.compile(s)
fn = "ip.txt"
s = open(fn).read()
i = 0
results = []
while True:
    m = patt.search(s, i)
    if m:
        results.append(m.group(1))
        i = m.end()+1
    else:
        break
print results

Below is the example file contents and output using the above code:

"""other text127.1.1.125other text
other text192.168.1.1other text
fhhsdjkasls
er992rosdf
fjfrj234i
llwefkkssedllother text'255.255.255.255
4885.4556.455.4599
asdfl;ojwerpo['j4t2"""
 
>>> ['127.1.1.125', '192.168.1.1', '255.255.255.255']

[DjPal]

thanks a lot for setting me in the right direction!
I now have;

 
s = r"(%s)" % ("\.".join(['(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)']*4))
patt = re.compile(s)
fn = "file"
s = open(fn).read()
i = 0
 
results = []
while True:
    m = patt.search(s, i)
    if m:
        results.append(m.group(1))
        i = m.end()+1
    else:
        break
 
criteria = ['Failed password', 'Invalid user']
criteria_count={}
count=0
 
for item in results:
    if criteria_count.has_key(item):
        count = criteria_count[item]
        count = count+1
        criteria_count[item]=count
 
        if count>10:
            for dItem in criteria_count.keys():
                print dItem
        else:
            break
 
    else:
        criteria_count[item]=1
 
 

I'm trying to list the IPs which appear more than 10 times and have the 'criteria',
but am slightly confused at this point!

[bvdet]

This little bit of code should do what you want (untested):

ipDict = {}
 
for item in results:
    ipDict[item] = ipDict.get(item, 0) + 1
 
# print IPs with count > 10
for key in ipDict:
    if ipDict[key] > 10:
        print key
 
# create a list of IPs with count > 10
[key for key in ipDict if ipDict[key] > 10]