No such file or directory:

[iamfletch]

Ok i think it is the way i am telling the function what the path is. im guessing this only doesnt work because im on a windows machine (on python 2.5)

f = open('files\test.txt', 'r')
for line in f:
    print line

ive tried changing the string in all obvious ways

'files\\test.txt'
r'files\test.txt'
'files/test.txt'
'c:\....\files\test.py'
'c:\\...\files\test.py' (for the c:\ bug i tried c:\\)
 

Ok what am i missing here? ive been coding for years and this has stumped me. Google doesnt even have an answer. do people just not open files out of there directories in windows?

[bvdet]

Look what happens when a string with a backslash character is evaluated:

>>> print 'abcdef\thrt'
abcdef    hrt
>>> print r'abcdef\thrt'
abcdef\thrt
>>> 

Characters "\t" are evaluated as a tab character. Escape the backslash characters for a path as in:
'D:\\SD\\plugins\\Embed\\Defaults\\EmbedPL.txt'

or use the forward slash as in:
'D:/SD/plugins/Embed/Defaults/EmbedPL.txt'

or use a raw string as in:
r'D:\SD\plugins\Embed\Defaults\EmbedPL.txt'

If the file is in your current working directory (os.getcwd()), you can omit the full path as in:
'EmbedPL.txt'

To read a file in the directory just above the CWD:
open("..\\EmbedPL.txt").read()

To read a file in a directory just below the CWD:
open("subdir_name\\EmbedPL.txt").read()

[iamfletch]

thanks for the reply, turns out i miss typed the file when making it. to text.txt. but i got it working now thanks, one question though. if the file is dynamic eg
filename from sys.

f=open('files/'.filename,'r')
 

will this work for any value of filename, where filename is just a file (not a path) and the file exists.

[bvdet]

iamfletch:

Look at the glob module. Usage:

glob.glob(pathname) or glob.glob1(dirname, pattern)

From help(glob):
Returns a list of paths matching a pathname pattern. The pattern may contain simple shell-style wildcards a la fnmatch.

You may be referring to a file name stored in a variable. You can use string formatting. Example:

var = "filenameXYX.txt"
open("dir1/dir2/%s" % (var))

[iamfletch]

Yup, that's all clear now. Thanks a lot, fast and helpful forums here.