shutil module (directory input from terminal)

klia

hello folks

i am trying to tweak the current codes so that later when i call it from the terminal i can provide sourcefile and the destination file rather being fixed in the code. because now i have to specify the sourcefile and the destinationfile in codes and not left to be specified from the terminal. i want to be able to do this.

python shutil_copy.py sourcefile, destinationfile

thanks

Jan 27 '09 #1

bvdet

The arguments passed to the script on the command line are available in list object sys.argv. Example at command prompt:
Output:

Jan 27 '09 #2

klia

@bvdet

hey man, thanks for replay

i did the following

and i got the following error, for the record i am trying to copy files from one directory to another one

waseem@Linux:~/Project2$ python copying_photos.py '/home/waseem/My Pictures/yemen 2008/2008/1' '/home/waseem/h'
Traceback (most recent call last):
File "copying_photos.py", line 4, in <module>
shutil.copytree(sys.argv[0], sys.argv[1] )
File "/usr/lib/python2.5/shutil.py", line 109, in copytree
names = os.listdir(src)
OSError: [Errno 20] Not a directory: 'copying_photos.py'

Jan 28 '09 #3

kaarthikeyapreyan

@klia
What u should do is modify the line
to
Make sure that the source is a directory, an existing one and the destination is a non-existent directory name.

Jan 28 '09 #4

klia

Thank you very much.

it worked perfectly

Jan 28 '09 #5