compare string

[ndoe]

how to compare string in file i mean compare that string content digit or alphabet,and 1 question more can we count that line if first line variable = 1,if read second line variable = 2 and so on thanks
e.g

i have file with name data.txt with file like this

123456




abcdef
456897
asdffg


789654

gfdsah


the question how to compare that file and i now that string with content alphabet or number
and i want make make new file data2.txt from data.txt like this


123456 456897 789654 123456 abcdef 123456 asdffg gfdsah

[bvdet]

You could do something like this:

>>> line1 = '12345648737276488'
>>> line2 = 'abcdef'
>>> import string
>>> numbers = set('1234567890')
>>> alpha = set(string.ascii_letters)
>>> set(line1).issubset(numbers)
True
>>> set(line2).issubset(alpha)
True
>>> set(line2).issubset(numbers)
False
>>> 

[ndoe]

hmmm,not like that,i mean how to write to file and we read that string from file to thanks for your help

[bvdet]

By what criteria are you reordering the data to write to another file?

[nishi2rock]

If your problem is about reading from and into files...

FileObj = open(Filename,mode) eg:f = open("tmp.txt","w")

read and readlines can be used to read data from file
eg: FileData = f.read() reads all the data of file into FileData

write and writelines can be used to write

coming to your string manipulations

someString = 'A string'

someString.isalpha() = True
someString.isalnum() = True
someString.isdigit() = Flase

someString = '123456'

someString.isalpha() = False
someString.isalnum() = True
someString.isdigit() = True

may be if you explain your sorting criteria it would be more explanatory