Hi all,
I am using python version 2.3.in a program ,
I have called the sort function.Wherein,
a.sort(reverse=True)
is giving the following error:
TypeError: sort() takes no keyword arguments.
It works in python 2.4,What can be the alternative in python 2.3
Thanks ,
Gaurav 2 2524
gaurav kashyap wrote:
Hi all,
I am using python version 2.3.in a program ,
I have called the sort function.Wherein,
a.sort(reverse=True)
is giving the following error:
TypeError: sort() takes no keyword arguments.
It works in python 2.4,What can be the alternative in python 2.3
Thanks ,
Gaurav
You could try:
>>a.sort() a = a[::-1]
Aidan <aw****@gmail.comwrote:
gaurav kashyap wrote:
>Hi all, I am using python version 2.3.in a program , I have called the sort function.Wherein, a.sort(reverse=True) is giving the following error:
TypeError: sort() takes no keyword arguments.
It works in python 2.4,What can be the alternative in python 2.3
Thanks , Gaurav
You could try:
>a.sort() a = a[::-1]
You could, but you should also be aware that there is a subtle difference.
The 'reverse' keyword argument gives a stable reverse sort, sorting and
then reversing something is not stable. e.g.
>>data = [(1, 'zzz'), (1, 'abc'), (2, 'def'), (1, 'pqr'), (2, 'jkl')] a = data[:] a.sort(lambda p,q: cmp(p[0],q[0]), reverse=True) a
[(2, 'def'), (2, 'jkl'), (1, 'zzz'), (1, 'abc'), (1, 'pqr')]
>>a = data[:] a.sort(lambda p,q: cmp(p[0],q[0])) a[::-1]
[(2, 'jkl'), (2, 'def'), (1, 'pqr'), (1, 'abc'), (1, 'zzz')]
--
Duncan Booth http://kupuguy.blogspot.com This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics
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