removing quotes from a list print out

[Thekid]

How can you take a list and get rid of the quotes when it prints out?
if you have this:
>>list = ["123", "456", "789"]
>>print list
['123','456','789']

but want it to print out like this:
[123,456,789]
or just
123,456,789

I tried .split or .replace but it says list has no attribute split or replace

[bvdet]

Here's some options:

>>> lst = ["123", "456", "789"]
>>> print ','.join(lst)
123,456,789
>>> print "[%s]" % (','.join(lst))
[123,456,789]
>>> print [int(i) for i in lst]
[123, 456, 789]
>>> 

[Thekid]

Those work great, thanks. One more question...what if the list contains something other than integers as well but I just need the integers without quotes? Example:

lst = ["hat", "3", "5", "8"]
["hat", 3, 5, 8]

I tried the last suggestion you posted with [int ( i ) for i in lst] but it gives an error message.

[boxfish]

I'm sure bvdet can give you something better, but

lst = ["hat", "3", "5", "8"]
lst_4_print = []
for i in lst:
    try:
        lst_4_print.append(int(i))
    except ValueError:
        lst_4_print.append(i)
print lst_4_print
 

[bvdet]

I'm sure bvdet can give you something better, but

lst = ["hat", "3", "5", "8"]
lst_4_print = []
for i in lst:
    try:
        lst_4_print.append(int(i))
    except ValueError:
        lst_4_print.append(i)
print lst_4_print
 

This is not necessarily better, just slightly different:

>>> lst = ["hat", "3", "5", "8"]
>>> lst_4_print = []
>>> for i in lst:
...     if i.isdigit():
...         lst_4_print.append(int(i))
...     else:
...         lst_4_print.append(i)
...         
>>> lst_4_print
['hat', 3, 5, 8]
>>> 

[Thekid]

Thank you both for your suggestions!