subprocess.Popen(..., cwd=...) and Makefile $(PWD) don't play nice

[Miki]

Hello All,

Can anybody explain why Makefile $(PWD) does show the right directory
when running under subprocess.Popen(..., cwd=...)

For example:
[18:07] tmp $cat /tmp/p/Makefile
all:
@echo $(PWD)
[18:07] tmp $cat t
#!/usr/bin/env python

from subprocess import Popen
Popen(["make"], cwd="/tmp/p")

[18:07] tmp $./t
/tmp

The output of the "make" command should have been "/tmp/p" and not "/
tmp"

TIA,
--
Miki <mi*********@gmail.com>
http://pythonwise.blogspot.com

[Gabriel Genellina]

En Mon, 06 Oct 2008 13:09:26 -0300, Miki <mi*********@gmail.comescribió:

Can anybody explain why Makefile $(PWD) does show the right directory
when running under subprocess.Popen(..., cwd=...)

For example:
[18:07] tmp $cat /tmp/p/Makefile
all:
@echo $(PWD)
[18:07] tmp $cat t
#!/usr/bin/env python

from subprocess import Popen
Popen(["make"], cwd="/tmp/p")

[18:07] tmp $./t
/tmp

The output of the "make" command should have been "/tmp/p" and not "/
tmp"

I've tried the equivalent version on Windows and it worked fine.
And I can't see how make could find the Makefile at /tmp/p if the current
directory were another one... (?)

--
Gabriel Genellina

[Miki]

The problem is, he is not printing the name of the current working

directory; he is printing the value of the variable $PWD. *That is
likely set from the environment by the shell he started the Python
program from, but Python does *not* update to reflect changes to
the working directory.

Should I see it as a bug? Should subprocess change this?

Use '@pwd' instead of '@echo $(PWD)'.

I'm using '$(shell pwd)', just wondered why $PWD didn't work.

Thanks for the explanation.
--
Miki <mi*********@gmail.com>
http://pythonwise.blogspot.com