Search for a word from a text file and count

[frozz85]

I need to search through the file and look for lines that begin with "From". I need to parse the From line and print out the second word for each From line and then also count the number of From lines and print out a count at the end. I'm not sure what to do. Any help is appreciated.

import string
fname = raw_input("Enter a file name: ")
 
try:
   infile = open(fname, "r")
except:
   print "File not found:", fname
   exit()
 
x = 0
for line in infile:
 
   words = string.split(line)
   print len(words), words
 
   if ( words[0] == 'From' ) :
      x = x + 1
      print x, words[1]
   elif (words[0] == ""):
      x = x
      continue
print "There were",x,"lines in the file with From as the first word"

[shreyask]

import string
import sys
 
if len(sys.argv) < 3:
    print "USAGE:", sys.argv[0], " <filename> <keyword>"
    sys.exit()
else:
    filename = sys.argv[1]
    keyword = sys.argv[2]
 
try:
    file = open(filename)
except:
    print "File not found:", filename
    sys.exit()
 
counter = 0
 
for line in file.readlines():
    split_line = string.split(line)
 
    if len(split_line) > 0:
        if string.upper(split_line[0]) == string.upper(keyword):
            if len(split_line) > 1:
                print split_line[1]
 
            counter = counter + 1
 
print "total number of occurances of", keyword, "-", counter
 

[frozz85]

Thank you so much!! :) I'm just a beginner, so I don't know the library sys yet. But it helps! Thank you!

import string
import sys
 
if len(sys.argv) < 3:
    print "USAGE:", sys.argv[0], " <filename> <keyword>"
    sys.exit()
else:
    filename = sys.argv[1]
    keyword = sys.argv[2]
 
try:
    file = open(filename)
except:
    print "File not found:", filename
    sys.exit()
 
counter = 0
 
for line in file.readlines():
    split_line = string.split(line)
 
    if len(split_line) > 0:
        if string.upper(split_line[0]) == string.upper(keyword):
            if len(split_line) > 1:
                print split_line[1]
 
            counter = counter + 1
 
print "total number of occurances of", keyword, "-", counter
 

[bvdet]

There is no need to use the string module. Following is an example using a file on my system.

>>> f = open(r'D:\SDS2_7.1C\jobs\620_Caldwell\macro\620_Caldwell_Grids.txt', 'r')
>>> output = []
>>> for line in f:
...     if line.lower().startswith('recall'):
...         output.append(line)
...         
>>> f.close()
>>> print 'The keyword occurred %d times.' % len(output)
The keyword occurred 9 times.
>>> print 'Words following the keywords: \n%s' % '\n'.join([w.strip().split()[1] for w in output])
Words following the keywords: 
20
17
21
X
Q
S
Z
21
3
>>>