Syntax Problem with strptime in Python 2.4

[W. eWatson]

Apparently, use of strptime of datetime needs a workaround in Python 2.4 to
work properly. The workaround is d =
datetime.datetime(*(time.strptime(date_string, format)[0:5])). However, when
I try to use it, or even use it the regular way, it fails with
AttributeError: type object 'datetime.datetime' has no attribute 'datetime'.
From the following code code segment:

format = '%Y%m%d_%H%M%S'
#d=datetime.strptime('20080321_113405', format)-- typical use
print time.strptime('20080321_113405', format)[0:5]
d = datetime.datetime(*time.strptime('20080321_113405' , format)[0:5])

Does anyone know how to make this work in 2.4? If not, is there a way to
achieve the same result?
--
W. eWatson

(121.015 Deg. W, 39.262 Deg. N) GMT-8 hr std. time)
Obz Site: 39° 15' 7" N, 121° 2' 32" W, 2700 feet

Web Page: <www.speckledwithstars.net/>

[skip]

>Apparently, use of strptime of datetime needs a workaround in Python
2.4 to work properly. The workaround is d =
datetime.datetime(*(time.strptime(date_string,
format)[0:5])). However, when I try to use it, or even use it the
regular way, it fails with AttributeError: type object
'datetime.datetime' has no attribute 'datetime'.

Works for me:

>>import datetime
format = '%Y%m%d_%H%M%S'
import time
print time.strptime('20080321_113405', format)[0:5]

(2008, 3, 21, 11, 34)

>>d = datetime.datetime(*time.strptime('20080321_113405' , format)[0:5])
d

datetime.datetime(2008, 3, 21, 11, 34)

Python 2.4.4, Mac OS X 10.5.4.

Skip

[Diez B. Roggisch]

W. eWatson wrote:

Apparently, use of strptime of datetime needs a workaround in Python 2.4
to work properly. The workaround is d =
datetime.datetime(*(time.strptime(date_string, format)[0:5])). However,
when I try to use it, or even use it the regular way, it fails with
AttributeError: type object 'datetime.datetime' has no attribute
'datetime'.
From the following code code segment:

format = '%Y%m%d_%H%M%S'
#d=datetime.strptime('20080321_113405', format)-- typical use
print time.strptime('20080321_113405', format)[0:5]
d = datetime.datetime(*time.strptime('20080321_113405' , format)[0:5])

Does anyone know how to make this work in 2.4? If not, is there a way to
achieve the same result?

This is not what you think it is. All your problem is that you do

from datetime import datetime

which imports the datetime-class, but then try to access

datetime.datetime

as if you had done

import datetime.
This actually is a wart in the datetime-module - it would be better if the
classes in there would follow PEP-8.

Diez

[W. eWatson]

Diez B. Roggisch wrote:

W. eWatson wrote:

>Apparently, use of strptime of datetime needs a workaround in Python 2.4
to work properly. The workaround is d =
datetime.datetime(*(time.strptime(date_string, format)[0:5])). However,
when I try to use it, or even use it the regular way, it fails with
AttributeError: type object 'datetime.datetime' has no attribute
'datetime'.
From the following code code segment:

format = '%Y%m%d_%H%M%S'
#d=datetime.strptime('20080321_113405', format)-- typical use
print time.strptime('20080321_113405', format)[0:5]
d = datetime.datetime(*time.strptime('20080321_113405' , format)[0:5])

Does anyone know how to make this work in 2.4? If not, is there a way to
achieve the same result?

This is not what you think it is. All your problem is that you do

from datetime import datetime

which imports the datetime-class, but then try to access

datetime.datetime

as if you had done

import datetime.
This actually is a wart in the datetime-module - it would be better if the
classes in there would follow PEP-8.

Diez

That's it. Thanks.

--
W. eWatson

(121.015 Deg. W, 39.262 Deg. N) GMT-8 hr std. time)
Obz Site: 39° 15' 7" N, 121° 2' 32" W, 2700 feet

Web Page: <www.speckledwithstars.net/>