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int((9.2-9.0)*10) is 1, int((9.21-9.0)*10) is 2, why?

bcm
Python 2.5.2 (r252:60911, Feb 21 2008, 13:11:45) [MSC v.1310 32 bit
(Intel)] on win32
The following line of code describes an funny question$B!'(B
>>int((9.2-9.0)*10)
1
>>int((9.21-9.0)*10)
2
>>int((9.1-9.0)*10)
0
>>int((9.11-9.0)*10)
1
>>int((8.2-8.0)*10)
1
>>int((8.23-8.0)*10)
2

why? anybody can explain it?
Sep 5 '08 #1
2 1269
On Sep 5, 11:12 pm, bcm <bluecrysta...@gmail.comwrote:
Python 2.5.2 (r252:60911, Feb 21 2008, 13:11:45) [MSC v.1310 32 bit
(Intel)] on win32
The following line of code describes an funny question$B!'(B>>int((9.2-9.0)*10)
1
>int((9.21-9.0)*10)
2
>int((9.1-9.0)*10)
0
>int((9.11-9.0)*10)
1
>int((8.2-8.0)*10)
1
>int((8.23-8.0)*10)

2

why? anybody can explain it?

Try looking one step at a time:
>>9.2
9.1999999999999993

That wasn't hard, was it? Do you need any further explanation? If so,
look here:
http://docs.python.org/tut/node16.html
Sep 5 '08 #2
bcm
On Sep 5, 9:29 pm, John Machin <sjmac...@lexicon.netwrote:
On Sep 5, 11:12 pm, bcm <bluecrysta...@gmail.comwrote:
Python 2.5.2 (r252:60911, Feb 21 2008, 13:11:45) [MSC v.1310 32 bit
(Intel)] on win32
The following line of code describes an funny question$B!'(B>>int((9.2-9.0)*10)
1
>>int((9.21-9.0)*10)
2
>>int((9.1-9.0)*10)
0
>>int((9.11-9.0)*10)
1
>>int((8.2-8.0)*10)
1
>>int((8.23-8.0)*10)
2
why? anybody can explain it?

Try looking one step at a time:>>9.2

9.1999999999999993

That wasn't hard, was it? Do you need any further explanation? If so,
look here:http://docs.python.org/tut/node16.html
thanks a lot, i am really really stupid ~*v*~
Sep 5 '08 #3

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