Re: path slashes cleaning

[Francesco Guerrieri]

On Thu, Sep 4, 2008 at 3:25 PM, Mathieu Prevot <ma************@gmail.comwrote:

Hi,

for scripts that take arguments, I would like to remove the trailing
slash if it's present.

Is there something else than:

a='/usr/local/lib/'
if a[-1] == '/':
a = list(a)
a.pop()
''.join(a)

Thanks,
Mathieu

a.rstrip('/') does the job.

bye,
Francesco

[Jason Scheirer]

On Sep 4, 6:32*am, "Francesco Guerrieri" <[e-mail]>
wrote:

On Thu, Sep 4, 2008 at 3:25 PM, Mathieu Prevot <[e-mail]>wrote:

Hi,

for scripts that take arguments, I would like to remove the trailing
slash if it's present.

Is there something else than:

a='/usr/local/lib/'
if a[-1] == '/':
*a = list(a)
*a.pop()
*''.join(a)

Thanks,
Mathieu

a.rstrip('/') does the job.

bye,
Francesco

[1]: import os.path
[2]: os.path.normpath('/usr/bin')
'/usr/bin'
[3]: os.path.normpath('/usr/bin/')
'/usr/bin'

And on windows:
[1]: import os.path
[2]: os.path.normpath(r'c:\data')
'c:\\data'
[3]: os.path.normpath('c:\\data\\')
'c:\\data'

Use the functions provided in os.path.