generate list of strings

[ss30]

Hi,

I'm trying to generate a list of random digits with no repeats. So far i have:

a = random.sample(range(0, 1), n)

which generates a list of random digits in a list with no repeat such as [1, 3, 5, 9] where n is 4.

However, i need it to produce a list of string of digits with no repeats, such as ['1', '3', '5', '9']. Is there any simple way to do this?

Thankyou for reading.

[realin]

i could get this result

'[10, 0, 5, 1]'
outta this code 
>>> str(random.sample(range(0,11),4))
 

i know that may be different, but this is what i learnt today cause i just started with python :)

cheers !!

[Laharl]

If you want to make each element a string, the simplest way is to generate the list of digits the way you did and then use a list comprehension or loop to convert each to a string.

a = [str(elem) for elem in a] #list comprehension, I'm not going to type out the loop version, as it's almost identical
 

[Thekid]

This will print out 4 random numbers in the range(1,44). It's easy to adjust as well:

import random
randlist=[]
while (randlist.__len__() <= 4):
  b =random.randint(1,44)
  if not b in randlist:
     randlist.append(b)
print randlist
 

Credit to kaarthikeyapreyan for that code: http://bytes.com/forum/thread827473.html

Or is it that you need the answer to print out with quotes around each number?