Re: Get current class namespace.

[Fredrik Lundh]

Robert Rawlins wrote:

What’s the simplest way to access a classes namespace from within
itself. I want to use it in a custom __repr__() method so it prints the
current namespace for the class like package.module.class.

Name or namespace? You can access the class name from an instance via
the __class__ attribute:

>>class foo:

.... def __repr__(self):
.... return "<%s instance at %x>" % (
.... self.__class__.__name__, id(self)
.... )
....

>>foo()

<foo instance at c714e0>

The module the class was defined in is also available:

>>class foo:

.... def __repr__(self):
.... return "<%s.%s instance at %x>" % (
.... self.__class__.__module__, self.__class__.__name__,
.... id(self)
.... )
....

>>foo()

<__main__.foo instance at c9fbc0>

To get the namespace (that is, the collection of (name, value)
pairs that make up the class' contents), use vars(self.__class__)
(or vars(self), if you want the full instance).

</F>