468,458 Members | 1,793 Online
Bytes | Developer Community
New Post

Home Posts Topics Members FAQ

Post your question to a community of 468,458 developers. It's quick & easy.

creating yaml without tags using pyyaml

hello

I have a situation where I have quite a large python object which I
want to convert to yaml so I can then send it to a flex application
using pyamf.

I've managed to create a yaml document using the python object
(http://flashbsm.googlecode.com/svn/t...st/tester.yaml)
(using pyyaml)

however when I send the result of decoding the python object to yaml
to the flex app, the flex app complains about expecting a block end,
but not getting one.

I have come to the conclusion that this is the fault of the tags (for
example, !!python/tuple) as getting rid of them gets rid of the
errors.

So I'm wondering if there is an option to YAML.decode that will create
a yaml document without the tags?

Thankyou

Regards
Stephen
Jun 27 '08 #1
0 1010

This discussion thread is closed

Replies have been disabled for this discussion.

Similar topics

3 posts views Thread by Peter Maas | last post: by
2 posts views Thread by Wilk | last post: by
reply views Thread by Jane Austine | last post: by
30 posts views Thread by Reinhold Birkenfeld | last post: by
reply views Thread by Phlip | last post: by
reply views Thread by Kirill Simonov | last post: by
reply views Thread by Kirill Simonov | last post: by
reply views Thread by Matthew Wilson | last post: by
2 posts views Thread by sshub | last post: by
reply views Thread by NPC403 | last post: by
By using this site, you agree to our Privacy Policy and Terms of Use.