|
Hi Everyone,
i have another question. What if i wanted to make n tuples, each with
a list of coordinates. For example :
coords = list()
for h in xrange(1,11,1):
for i in xrange(1, 5, 1) :
for j in xrange(1, 5, 1) :
for k in xrange(1,2,1) :
coords.append((i,j,k))
lista+str(h)= tuple coords
print tuple(coords)
so that i will have tuple1, tuple2,..., tupleN, etc. I am trying to do
it the way i show you above but it is not working properly. I wish you
could help me with that. Thanks again, | |
Share:
|
victor.hera...@gmail.com:
Do you mean something like this? (notice the many formatting
differences, use a formatting similar to this one in your code)
coords = []
for i in xrange(1, 5):
for j in xrange(1, 5):
for k in xrange(1, 2):
coords.append( (i, j, k) )
coords *= 10
print coords
Bye,
bearophile | | |
On 5 ÉÀÎ, 01:57, "victor.hera...@gmail.com" <victor.hera...@gmail.com>
wrote:
Hi Everyone,
i have another question. What if i wanted to make n tuples, each with
a list of coordinates. For example :
coords = list()
for h in xrange(1,11,1):
for i in xrange(1, 5, 1) :
for j in xrange(1, 5, 1) :
for k in xrange(1,2,1) :
coords.append((i,j,k))
lista+str(h)= tuple coords
print tuple(coords)
so that i will have tuple1, tuple2,..., tupleN, etc. I am trying to do
it the way i show you above but it is not working properly. I wish you
could help me with that. Thanks again,
>>from itertools import repeat, izip coords = tuple((i,j,k) for i in xrange(1,5) for j in xrange(1,5) for kin xrange(1,2)) locals().update(("tuple%s" % i, coord) for i, coord in izip(xrange(1,11), repeat(coords))) tuple1
((1, 1, 1), (1, 2, 1), (1, 3, 1), (1, 4, 1), (2, 1, 1), (2, 2, 1), (2,
3, 1), (2
, 4, 1), (3, 1, 1), (3, 2, 1), (3, 3, 1), (3, 4, 1), (4, 1, 1), (4, 2,
1), (4, 3
, 1), (4, 4, 1))
Does this help?
But I don't understand why you need this?
Ivan | | |
On Jun 5, 3:49 pm, Ivan Illarionov <ivan.illario...@gmail.comwrote:
On 5 ÉÀÎ, 01:57, "victor.hera...@gmail.com" <victor.hera...@gmail.com>
wrote:
Hi Everyone,
i have another question. What if i wanted to make n tuples, each with
a list of coordinates. For example :
coords = list()
for h in xrange(1,11,1):
for i in xrange(1, 5, 1) :
for j in xrange(1, 5, 1) :
for k in xrange(1,2,1) :
coords.append((i,j,k))
lista+str(h)= tuple coords
print tuple(coords)
so that i will have tuple1, tuple2,..., tupleN, etc. I am trying to do
it the way i show you above but it is not working properly. I wish you
could help me with that. Thanks again,
>from itertools import repeat, izip coords = tuple((i,j,k) for i in xrange(1,5) for j in xrange(1,5) fork in xrange(1,2)) locals().update(("tuple%s" % i, coord) for i, coord in izip(xrange(1,11), repeat(coords))) tuple1
((1, 1, 1), (1, 2, 1), (1, 3, 1), (1, 4, 1), (2, 1, 1), (2, 2, 1), (2,
3, 1), (2
, 4, 1), (3, 1, 1), (3, 2, 1), (3, 3, 1), (3, 4, 1), (4, 1, 1), (4, 2,
1), (4, 3
, 1), (4, 4, 1))
Does this help?
But I don't understand why you need this?
Ivan
Hi,
What i need is, for example:
tuple 1=((1, 1, 1), (1, 2, 1), (1, 3, 1), (1, 4, 1))
tuple 2=((2, 1, 1), (2, 2, 1), (2, 3, 1), (2, 4, 1))
tuple 3=((3, 1, 1), (3, 2, 1), (3, 3, 1), (3, 4, 1))
and so on. Please help me and sorry for not taking the time to post my
questions properly.
Victor | | |
On 5 июн, 18:19, "victor.hera...@gmail.com" <victor.hera...@gmail.com>
wrote:
On Jun 5, 3:49 pm, Ivan Illarionov <ivan.illario...@gmail.comwrote:
On 5 ÉÀÎ, 01:57, "victor.hera...@gmail.com" <victor.hera....@gmail.com>
wrote:
Hi Everyone,
i have another question. What if i wanted to make n tuples, each with
a list of coordinates. For example :
coords = list()
for h in xrange(1,11,1):
for i in xrange(1, 5, 1) :
for j in xrange(1, 5, 1) :
for k in xrange(1,2,1) :
coords.append((i,j,k))
lista+str(h)= tuple coords
print tuple(coords)
so that i will have tuple1, tuple2,..., tupleN, etc. I am trying to do
it the way i show you above but it is not working properly. I wish you
could help me with that. Thanks again,
>>from itertools import repeat, izip
>>coords = tuple((i,j,k) for i in xrange(1,5) for j in xrange(1,5) for k in xrange(1,2))
>>locals().update(("tuple%s" % i, coord) for i, coord in izip(xrange(1,11), repeat(coords)))
>>tuple1
((1, 1, 1), (1, 2, 1), (1, 3, 1), (1, 4, 1), (2, 1, 1), (2, 2, 1), (2,
3, 1), (2
, 4, 1), (3, 1, 1), (3, 2, 1), (3, 3, 1), (3, 4, 1), (4, 1, 1), (4, 2,
1), (4, 3
, 1), (4, 4, 1))
Does this help?
But I don't understand why you need this?
Ivan
Hi,
What i need is, for example:
tuple 1=((1, 1, 1), (1, 2, 1), (1, 3, 1), (1, 4, 1))
tuple 2=((2, 1, 1), (2, 2, 1), (2, 3, 1), (2, 4, 1))
tuple 3=((3, 1, 1), (3, 2, 1), (3, 3, 1), (3, 4, 1))
and so on. Please help me and sorry for not taking the time to post my
questions properly.
Victor
>>coords = [(i, tuple((i,j,k) for j in range(1,5) for k in range(1,2))) for i in range(1,5)] locals().update(("tuple_%s" % i, coord) for i, coord in coords) tuple_1
((1, 1, 1), (1, 2, 1), (1, 3, 1), (1, 4, 1))
>>tuple_2
((2, 1, 1), (2, 2, 1), (2, 3, 1), (2, 4, 1))
>>tuple_3
((3, 1, 1), (3, 2, 1), (3, 3, 1), (3, 4, 1))
Is this what you want?
Ivan | | |
On 5 июн, 18:19, "victor.hera...@gmail.com" <victor.hera...@gmail.com>
wrote:
On Jun 5, 3:49 pm, Ivan Illarionov <ivan.illario...@gmail.comwrote:
On 5 ÉÀÎ, 01:57, "victor.hera...@gmail.com" <victor.hera....@gmail.com>
wrote:
Hi Everyone,
i have another question. What if i wanted to make n tuples, each with
a list of coordinates. For example :
coords = list()
for h in xrange(1,11,1):
for i in xrange(1, 5, 1) :
for j in xrange(1, 5, 1) :
for k in xrange(1,2,1) :
coords.append((i,j,k))
lista+str(h)= tuple coords
print tuple(coords)
so that i will have tuple1, tuple2,..., tupleN, etc. I am trying to do
it the way i show you above but it is not working properly. I wish you
could help me with that. Thanks again,
>>from itertools import repeat, izip
>>coords = tuple((i,j,k) for i in xrange(1,5) for j in xrange(1,5) for k in xrange(1,2))
>>locals().update(("tuple%s" % i, coord) for i, coord in izip(xrange(1,11), repeat(coords)))
>>tuple1
((1, 1, 1), (1, 2, 1), (1, 3, 1), (1, 4, 1), (2, 1, 1), (2, 2, 1), (2,
3, 1), (2
, 4, 1), (3, 1, 1), (3, 2, 1), (3, 3, 1), (3, 4, 1), (4, 1, 1), (4, 2,
1), (4, 3
, 1), (4, 4, 1))
Does this help?
But I don't understand why you need this?
Ivan
Hi,
What i need is, for example:
tuple 1=((1, 1, 1), (1, 2, 1), (1, 3, 1), (1, 4, 1))
tuple 2=((2, 1, 1), (2, 2, 1), (2, 3, 1), (2, 4, 1))
tuple 3=((3, 1, 1), (3, 2, 1), (3, 3, 1), (3, 4, 1))
and so on. Please help me and sorry for not taking the time to post my
questions properly.
Victor
Or even so:
locals().update(("tuple_%s" % i, tuple((i,j,k) for j in range(1,5) for
k in range(1,2))) for i in range(1,5))
Ivan | | |
On 5 июн, 18:56, Ivan Illarionov <ivan.illario...@gmail.comwrote:
On 5 июн, 18:19, "victor.hera...@gmail.com" <victor.hera...@gmail.com>
wrote:
On Jun 5, 3:49 pm, Ivan Illarionov <ivan.illario...@gmail.comwrote:
On 5 ÉÀÎ, 01:57, "victor.hera...@gmail.com" <victor.hera...@gmail.com>
wrote:
Hi Everyone,
i have another question. What if i wanted to make n tuples, each with
a list of coordinates. For example :
coords = list()
for h in xrange(1,11,1):
for i in xrange(1, 5, 1) :
for j in xrange(1, 5, 1) :
for k in xrange(1,2,1) :
coords.append((i,j,k))
lista+str(h)= tuple coords
print tuple(coords)
so that i will have tuple1, tuple2,..., tupleN, etc. I am trying to do
it the way i show you above but it is not working properly. I wish you
could help me with that. Thanks again,
>from itertools import repeat, izip
>coords = tuple((i,j,k) for i in xrange(1,5) for j in xrange(1,5)for k in xrange(1,2))
>locals().update(("tuple%s" % i, coord) for i, coord in izip(xrange(1,11), repeat(coords)))
>tuple1
((1, 1, 1), (1, 2, 1), (1, 3, 1), (1, 4, 1), (2, 1, 1), (2, 2, 1), (2,
3, 1), (2
, 4, 1), (3, 1, 1), (3, 2, 1), (3, 3, 1), (3, 4, 1), (4, 1, 1), (4, 2,
1), (4, 3
, 1), (4, 4, 1))
Does this help?
But I don't understand why you need this?
Ivan
Hi,
What i need is, for example:
tuple 1=((1, 1, 1), (1, 2, 1), (1, 3, 1), (1, 4, 1))
tuple 2=((2, 1, 1), (2, 2, 1), (2, 3, 1), (2, 4, 1))
tuple 3=((3, 1, 1), (3, 2, 1), (3, 3, 1), (3, 4, 1))
and so on. Please help me and sorry for not taking the time to post my
questions properly.
Victor
Or even so:
locals().update(("tuple_%s" % i, tuple((i,j,k) for j in range(1,5) for
k in range(1,2))) for i in range(1,5))
Ivan
Tried to make it readable:
def iter_coords(i):
for j in xrange(1,5):
for k in xrange(1,2):
yield i, j, k
def iter_vars():
for i in xrange(1, 5):
yield "tuple_%s" % i, tuple(iter_coords(i))
locals().update(dict(iter_vars()))
>>tuple_1
((1, 1, 1), (1, 2, 1), (1, 3, 1), (1, 4, 1))
>>tuple_2
((2, 1, 1), (2, 2, 1), (2, 3, 1), (2, 4, 1))
>>tuple_3
((3, 1, 1), (3, 2, 1), (3, 3, 1), (3, 4, 1))
>>tuple_4
((4, 1, 1), (4, 2, 1), (4, 3, 1), (4, 4, 1))
Ivan | | |
On Jun 5, 11:21 am, Ivan Illarionov <ivan.illario...@gmail.comwrote:
On 5 июн, 18:56, Ivan Illarionov <ivan.illario...@gmail.comwrote:
On 5 июн, 18:19, "victor.hera...@gmail.com" <victor.hera....@gmail.com>
wrote:
On Jun 5, 3:49 pm, Ivan Illarionov <ivan.illario...@gmail.comwrote:
On 5 ÉÀÎ, 01:57, "victor.hera...@gmail.com" <victor.hera...@gmail.com>
wrote:
Hi Everyone,
i have another question. What if i wanted to make n tuples, each with
a list of coordinates. For example :
coords = list()
for h in xrange(1,11,1):
for i in xrange(1, 5, 1) :
for j in xrange(1, 5, 1) :
for k in xrange(1,2,1) :
coords.append((i,j,k))
lista+str(h)= tuple coords
print tuple(coords)
so that i will have tuple1, tuple2,..., tupleN, etc. I am trying to do
it the way i show you above but it is not working properly. I wishyou
could help me with that. Thanks again,
>>from itertools import repeat, izip
>>coords = tuple((i,j,k) for i in xrange(1,5) for j in xrange(1,5) for k in xrange(1,2))
>>locals().update(("tuple%s" % i, coord) for i, coord in izip(xrange(1,11), repeat(coords)))
>>tuple1
((1, 1, 1), (1, 2, 1), (1, 3, 1), (1, 4, 1), (2, 1, 1), (2, 2, 1), (2,
3, 1), (2
, 4, 1), (3, 1, 1), (3, 2, 1), (3, 3, 1), (3, 4, 1), (4, 1, 1), (4, 2,
1), (4, 3
, 1), (4, 4, 1))
Does this help?
But I don't understand why you need this?
Ivan
Hi,
What i need is, for example:
tuple 1=((1, 1, 1), (1, 2, 1), (1, 3, 1), (1, 4, 1))
tuple 2=((2, 1, 1), (2, 2, 1), (2, 3, 1), (2, 4, 1))
tuple 3=((3, 1, 1), (3, 2, 1), (3, 3, 1), (3, 4, 1))
and so on. Please help me and sorry for not taking the time to post my
questions properly.
Victor
Or even so:
locals().update(("tuple_%s" % i, tuple((i,j,k) for j in range(1,5) for
k in range(1,2))) for i in range(1,5))
Ivan
Tried to make it readable:
def iter_coords(i):
for j in xrange(1,5):
for k in xrange(1,2):
yield i, j, k
def iter_vars():
for i in xrange(1, 5):
yield "tuple_%s" % i, tuple(iter_coords(i))
locals().update(dict(iter_vars()))
locals().update() works by accident here because it's in global scope;
it doesn't work within a function.
Use a proper data structure, like a dict or a list, and access each
tuple list as 'tuples[n]' instead of 'tuple_n'.
George | | |
On 5 июн, 19:38, George Sakkis <george.sak...@gmail.comwrote:
On Jun 5, 11:21 am, Ivan Illarionov <ivan.illario...@gmail.comwrote:
On 5 июн, 18:56, Ivan Illarionov <ivan.illario...@gmail.comwrote:
On 5 июн, 18:19, "victor.hera...@gmail.com" <victor.hera...@gmail.com>
wrote:
On Jun 5, 3:49 pm, Ivan Illarionov <ivan.illario...@gmail.comwrote:
On 5 ÉÀÎ, 01:57, "victor.hera...@gmail.com" <victor..hera...@gmail.com>
wrote:
Hi Everyone,
i have another question. What if i wanted to make n tuples, eachwith
a list of coordinates. For example :
coords = list()
for h in xrange(1,11,1):
for i in xrange(1, 5, 1) :
for j in xrange(1, 5, 1) :
for k in xrange(1,2,1) :
coords.append((i,j,k))
lista+str(h)= tuple coords
print tuple(coords)
so that i will have tuple1, tuple2,..., tupleN, etc. I am tryingto do
it the way i show you above but it is not working properly. I wish you
could help me with that. Thanks again,
>from itertools import repeat, izip
>coords = tuple((i,j,k) for i in xrange(1,5) for j in xrange(1,5) for k in xrange(1,2))
>locals().update(("tuple%s" % i, coord) for i, coord in izip(xrange(1,11), repeat(coords)))
>tuple1
((1, 1, 1), (1, 2, 1), (1, 3, 1), (1, 4, 1), (2, 1, 1), (2, 2, 1),(2,
3, 1), (2
, 4, 1), (3, 1, 1), (3, 2, 1), (3, 3, 1), (3, 4, 1), (4, 1, 1), (4, 2,
1), (4, 3
, 1), (4, 4, 1))
Does this help?
But I don't understand why you need this?
Ivan
Hi,
What i need is, for example:
tuple 1=((1, 1, 1), (1, 2, 1), (1, 3, 1), (1, 4, 1))
tuple 2=((2, 1, 1), (2, 2, 1), (2, 3, 1), (2, 4, 1))
tuple 3=((3, 1, 1), (3, 2, 1), (3, 3, 1), (3, 4, 1))
and so on. Please help me and sorry for not taking the time to post my
questions properly.
Victor
Or even so:
locals().update(("tuple_%s" % i, tuple((i,j,k) for j in range(1,5) for
k in range(1,2))) for i in range(1,5))
Ivan
Tried to make it readable:
def iter_coords(i):
for j in xrange(1,5):
for k in xrange(1,2):
yield i, j, k
def iter_vars():
for i in xrange(1, 5):
yield "tuple_%s" % i, tuple(iter_coords(i))
locals().update(dict(iter_vars()))
locals().update() works by accident here because it's in global scope;
it doesn't work within a function.
Use a proper data structure, like a dict or a list, and access each
tuple list as 'tuples[n]' instead of 'tuple_n'.
George
OP wanted variables and I showed him how to do this. I agree that a
list or a dict would be better.
Ivan | | |
On Jun 5, 11:48 am, Ivan Illarionov <ivan.illario...@gmail.comwrote:
On 5 июн, 19:38, George Sakkis <george.sak...@gmail.comwrote:
On Jun 5, 11:21 am, Ivan Illarionov <ivan.illario...@gmail.comwrote:
On 5 июн, 18:56, Ivan Illarionov <ivan.illario...@gmail..comwrote:
On 5 июн, 18:19, "victor.hera...@gmail.com" <victor.hera...@gmail.com>
wrote:
On Jun 5, 3:49 pm, Ivan Illarionov <ivan.illario...@gmail.comwrote:
On 5 ÉÀÎ, 01:57, "victor.hera...@gmail.com" <victor.hera...@gmail.com>
wrote:
Hi Everyone,
i have another question. What if i wanted to make n tuples, each with
a list of coordinates. For example :
coords = list()
for h in xrange(1,11,1):
for i in xrange(1, 5, 1) :
for j in xrange(1, 5, 1) :
for k in xrange(1,2,1) :
coords.append((i,j,k))
lista+str(h)= tuple coords
print tuple(coords)
so that i will have tuple1, tuple2,..., tupleN, etc. I am trying to do
it the way i show you above but it is not working properly. I wish you
could help me with that. Thanks again,
>>from itertools import repeat, izip
>>coords = tuple((i,j,k) for i in xrange(1,5) for j in xrange(1,5) for k in xrange(1,2))
>>locals().update(("tuple%s" % i, coord) for i, coord in izip(xrange(1,11), repeat(coords)))
>>tuple1
((1, 1, 1), (1, 2, 1), (1, 3, 1), (1, 4, 1), (2, 1, 1), (2, 2, 1), (2,
3, 1), (2
, 4, 1), (3, 1, 1), (3, 2, 1), (3, 3, 1), (3, 4, 1), (4, 1, 1), (4, 2,
1), (4, 3
, 1), (4, 4, 1))
Does this help?
But I don't understand why you need this?
Ivan
Hi,
What i need is, for example:
tuple 1=((1, 1, 1), (1, 2, 1), (1, 3, 1), (1, 4, 1))
tuple 2=((2, 1, 1), (2, 2, 1), (2, 3, 1), (2, 4, 1))
tuple 3=((3, 1, 1), (3, 2, 1), (3, 3, 1), (3, 4, 1))
and so on. Please help me and sorry for not taking the time to post my
questions properly.
Victor
Or even so:
locals().update(("tuple_%s" % i, tuple((i,j,k) for j in range(1,5) for
k in range(1,2))) for i in range(1,5))
Ivan
Tried to make it readable:
def iter_coords(i):
for j in xrange(1,5):
for k in xrange(1,2):
yield i, j, k
def iter_vars():
for i in xrange(1, 5):
yield "tuple_%s" % i, tuple(iter_coords(i))
locals().update(dict(iter_vars()))
locals().update() works by accident here because it's in global scope;
it doesn't work within a function.
Use a proper data structure, like a dict or a list, and access each
tuple list as 'tuples[n]' instead of 'tuple_n'.
George
OP wanted variables and I showed him how to do this. I agree that a
list or a dict would be better.
Ivan
Generating variable names at runtime doesn't work for locals and it is
a bad solution for globals in 99.9% of the cases. It is usually more
helpful to point someone who can't even express his problem clearly to
the right direction, rather than taking his pseudocode literally and
coming up with a semi-working translation.
George | | |
On 5 июн, 21:22, George Sakkis <george.sak...@gmail.comwrote:
On Jun 5, 11:48 am, Ivan Illarionov <ivan.illario...@gmail.comwrote:
On 5 июн, 19:38, George Sakkis <george.sak...@gmail.comwrote:
On Jun 5, 11:21 am, Ivan Illarionov <ivan.illario...@gmail.comwrote:
On 5 июн, 18:56, Ivan Illarionov <ivan.illario...@gmail.comwrote:
On 5 июн, 18:19, "victor.hera...@gmail.com" <victor..hera...@gmail.com>
wrote:
On Jun 5, 3:49 pm, Ivan Illarionov <ivan.illario...@gmail.comwrote:
On 5 ÉÀÎ, 01:57, "victor.hera...@gmail.com" <victor.hera...@gmail.com>
wrote:
Hi Everyone,
i have another question. What if i wanted to make n tuples, each with
a list of coordinates. For example :
coords = list()
for h in xrange(1,11,1):
for i in xrange(1, 5, 1) :
for j in xrange(1, 5, 1) :
for k in xrange(1,2,1) :
coords.append((i,j,k))
lista+str(h)= tuple coords
print tuple(coords)
so that i will have tuple1, tuple2,..., tupleN, etc. I am trying to do
it the way i show you above but it is not working properly. I wish you
could help me with that. Thanks again,
>from itertools import repeat, izip
>coords = tuple((i,j,k) for i in xrange(1,5) for j in xrange(1,5) for k in xrange(1,2))
>locals().update(("tuple%s" % i, coord) for i, coord in izip(xrange(1,11), repeat(coords)))
>tuple1
((1, 1, 1), (1, 2, 1), (1, 3, 1), (1, 4, 1), (2, 1, 1), (2, 2,1), (2,
3, 1), (2
, 4, 1), (3, 1, 1), (3, 2, 1), (3, 3, 1), (3, 4, 1), (4, 1, 1), (4, 2,
1), (4, 3
, 1), (4, 4, 1))
Does this help?
But I don't understand why you need this?
Ivan
Hi,
What i need is, for example:
tuple 1=((1, 1, 1), (1, 2, 1), (1, 3, 1), (1, 4, 1))
tuple 2=((2, 1, 1), (2, 2, 1), (2, 3, 1), (2, 4, 1))
tuple 3=((3, 1, 1), (3, 2, 1), (3, 3, 1), (3, 4, 1))
and so on. Please help me and sorry for not taking the time to post my
questions properly.
Victor
Or even so:
locals().update(("tuple_%s" % i, tuple((i,j,k) for j in range(1,5)for
k in range(1,2))) for i in range(1,5))
Ivan
Tried to make it readable:
def iter_coords(i):
for j in xrange(1,5):
for k in xrange(1,2):
yield i, j, k
def iter_vars():
for i in xrange(1, 5):
yield "tuple_%s" % i, tuple(iter_coords(i))
locals().update(dict(iter_vars()))
locals().update() works by accident here because it's in global scope;
it doesn't work within a function.
Use a proper data structure, like a dict or a list, and access each
tuple list as 'tuples[n]' instead of 'tuple_n'.
George
OP wanted variables and I showed him how to do this. I agree that a
list or a dict would be better.
Ivan
Generating variable names at runtime doesn't work for locals and it is
a bad solution for globals in 99.9% of the cases. It is usually more
helpful to point someone who can't even express his problem clearly to
the right direction, rather than taking his pseudocode literally and
coming up with a semi-working translation.
George
Understanding of how to create variables dynamically can be good for
OP's learning curve even though it's a bad solution in this particular
case.
I agree that it was my mistake to not point him in the right
direction.
Ivan | | This discussion thread is closed Replies have been disabled for this discussion. Similar topics
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