how to proccess the blank in the path on linux

[zhf]

I want ro walk a directory and its sub directory on linux,
to find some shell script file, and run them, but I found some path belong
blank charactor, such as '8000 dir', if I write as follow, I got error
"no such file"
path = '8000 dir'
for root, dirs, files in os.walk(path):
cmd = ' '
cmd = 'cd ' + root
os.system(cmd)

How can I repair it?

thanks, best regards.

[A.T.Hofkamp]

On 2008-05-21, zhf <my*******@sina.comwrote:

I want ro walk a directory and its sub directory on linux,
to find some shell script file, and run them, but I found some path belong
blank charactor, such as '8000 dir', if I write as follow, I got error
"no such file"
path = '8000 dir'
for root, dirs, files in os.walk(path):
cmd = ' '
cmd = 'cd ' + root
os.system(cmd)

How can I repair it?

Escape the space to prevent the shell from interpreting it as a word seperator.
This of course also holds for all other shell meta characters,
such as * [ ] \ < & and a few others I probably have forgotten.
I am not sure why you execute 'cd' commands in a sub-shell, as it is not very
useful. (that is, you start a new sub-process, in that sub-process you run the
'cd' command (causing the cwd of the sub-process to change directory), and then
the sub-process ends)

You most likely want to change the cwd of the Python process. If so, have a
look at os.chdir(). That function has the added advantage that there is no
shell in between that interprets all those meta characters (that is,
"os.chdir('8000 dir')" will work without further effort).

Sincerely,
Albert

[Jeremy Sanders]

A.T.Hofkamp wrote:

Escape the space to prevent the shell from interpreting it as a word
seperator. This of course also holds for all other shell meta characters,
such as * [ ] \ < & and a few others I probably have forgotten.

If the command was useful (unlike cd), it might be better to use subprocess
to launch it so that you don't need the escaping:

subprocess.call(['ls', '8000 dir'])

This avoids using the shell.

--
Jeremy Sanders
http://www.jeremysanders.net/

[TheSaint]

On 22:26, mercoledì 21 maggio 2008 zhf wrote:

I want ro walk a directory and its sub directory on linux

os.path.walk() should do the job.
Recursively you should try this, which I found on some web site:

8<---------8<---------8<---------8<---------8<---------8<---------

def file_find(folder, fname):
"""search for a filename fname starting in folder"""
for root, dirs, files in os.walk(folder):
for file in files:
# make search case insensitive
if fname.lower() == file.lower():
return Path.join(root, fname)

8<---------8<---------8<---------8<---------8<---------8<--------

Definitely I don't know about path with spaces or Unicode file names.